Home/ Sonal Chauhan/Answers
  1. Asked: In:

    In a survey of 50 students, 15 students said they liked football. The number of students who like football is 15 and the _______ (frequency/relative frequency) is _______ (fill in the fraction or decimal).

    Sonal Chauhan

    The blank for the concept is filled by 'relative frequency'. The blank for the value is filled by '15/50' (or '3/10' or '0.3').   Reason: The count 15 represents the frequency (the actual number of times students chose football). The ratio of this frequency to the total sample size of 50 studenRead more

    The blank for the concept is filled by ‘relative frequency’.

    The blank for the value is filled by ’15/50′ (or ‘3/10’ or ‘0.3’).

     

    Reason: The count 15 represents the frequency (the actual number of times students chose football). The ratio of this frequency to the total sample size of 50 students defines the relative frequency:

    Relative frequency = 15 / 50 = 3 / 10 = 0.3 (or 30%).

     

    For more NCERT Solutions of Class 9 Ganita Manjari Chapter 7 The Mathematics of Maybe: Introduction to Probability Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-7/

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    • 58
  2. Asked: In:

    Fill in the blanks. (i) The probability of an impossible event is _______. (ii) The set of all possible outcomes of a random experiment is called the _______. (iii) The probability of an event that is certain to happen is _______. (iv) Tossing a fair coin has a probability of _______ for getting heads.

    Sonal Chauhan

    (i) 0 (An event that cannot happen at all has a probability of 0). (ii) sample space (The collection containing every possible result of a trial is defined as the sample space). (iii) 1 (An event guaranteed to take place has maximum likelihood, which equals 1). (iv) 1/2 or 0.5 (A fair coin possessesRead more

    (i) 0 (An event that cannot happen at all has a probability of 0).

    (ii) sample space (The collection containing every possible result of a trial is defined as the sample space).

    (iii) 1 (An event guaranteed to take place has maximum likelihood, which equals 1).

    (iv) 1/2 or 0.5 (A fair coin possesses two symmetric, equally likely outcomes, heads and tails, giving P(heads) = 1/2).

     

    For more NCERT Solutions of Class 9 Ganita Manjari Chapter 7 The Mathematics of Maybe: Introduction to Probability Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-7/

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    • 51
  3. Asked: In:

    The perimeter of a circle is 44 cm. What is its radius?

    Sonal Chauhan

    Let the radius of the circle be r cm. Given circumference = 44 cm. The formula for the perimeter of a circle is: Circumference = 2 x π x r Substitute π = 22/7: 44 = 2 x (22/7) x r 44 = (44/7) x r Multiply both sides by 7 and divide by 44: r = (44 x 7) / 44 r = 7 cm. Therefore, the radius of the circRead more

    Let the radius of the circle be r cm.

    Given circumference = 44 cm.

    The formula for the perimeter of a circle is: Circumference = 2 x π x r

    Substitute π = 22/7: 44 = 2 x (22/7) x r 44 = (44/7) x r

    Multiply both sides by 7 and divide by 44: r = (44 x 7) / 44 r = 7 cm.

    Therefore, the radius of the circle is 7 cm.

     

    For more NCERT Solutions of Class 9 Ganita Manjari Chapter 6 Measuring Space: Perimeter and Area Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-6/

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    • 39
  5. Asked: In:

    Calculate, correct to 3 significant figures, the circumference of a circle with: (i) radius 7 cm (ii) radius 10 cm (iii) radius 12 cm.

    Sonal Chauhan

    Formula for circumference is C = 2 x π x r, taking π = 22/7: (i) For r = 7 cm: C = 2 x (22/7) x 7 = 44 cm = 44.0 cm (to 3 significant figures). (ii) For r = 10 cm: C = 2 x (22/7) x 10 = 440 / 7 = 62.857... cm = 62.9 cm (to 3 significant figures). (iii) For r = 12 cm: C = 2 x (22/7) x 12 = 528 / 7 =Read more

    Formula for circumference is C = 2 x π x r, taking π = 22/7:

    (i) For r = 7 cm: C = 2 x (22/7) x 7 = 44 cm = 44.0 cm (to 3 significant figures).

    (ii) For r = 10 cm: C = 2 x (22/7) x 10 = 440 / 7 = 62.857… cm = 62.9 cm (to 3 significant figures).

    (iii) For r = 12 cm: C = 2 x (22/7) x 12 = 528 / 7 = 75.428… cm = 75.4 cm (to 3 significant figures).

     

    For more NCERT Solutions of Class 9 Ganita Manjari Chapter 6 Measuring Space: Perimeter and Area Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-6/

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    • 45
  6. Asked: In:

    Calculate the length of the arc of a circle if: (i) the radius is 3.5 cm and the angle at the centre is 60°, and (ii) the radius is 6.3 m and the angle at the centre is 120°.

    Sonal Chauhan

    Arc length formula is l = 2 x π x r x (θ / 360). (i) Given r = 3.5 cm = 7/2 cm, θ = 60°: l = 2 x (22/7) x (7/2) x (60/360) = 22 x (1/6) = 11/3 cm = 3.67 cm. (ii) Given r = 6.3 m = 63/10 m, θ = 120°: l = 2 x (22/7) x (63/10) x (120/360) = (44/7) x (63/10) x (1/3) = (44 x 9) / (10 x 3) = (44 x 3) / 10Read more

    Arc length formula is l = 2 x π x r x (θ / 360).

    (i) Given r = 3.5 cm = 7/2 cm, θ = 60°:

    l = 2 x (22/7) x (7/2) x (60/360) = 22 x (1/6) = 11/3 cm = 3.67 cm.

    (ii) Given r = 6.3 m = 63/10 m, θ = 120°:

    l = 2 x (22/7) x (63/10) x (120/360) = (44/7) x (63/10) x (1/3) = (44 x 9) / (10 x 3) = (44 x 3) / 10 = 132/10 = 13.2 m.

     

    For more NCERT Solutions of Class 9 Ganita Manjari Chapter 6 Measuring Space: Perimeter and Area Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-6/

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    • 43