Let OA is well and AB is ladder in the figure. In triangle AOB, by pythagoras theorem AB² = AO² + OB² ⇒ 10² = 8² + BO² ⇒ 100 = 64 + BO² ⇒ BO² = 36 ⇒ BO = 6m Hence, the distance of the root of the ladder from the base of the wall is 6 m.
Let OA is well and AB is ladder in the figure.
In triangle AOB, by pythagoras theorem
AB² = AO² + OB²
⇒ 10² = 8² + BO²
⇒ 100 = 64 + BO²
⇒ BO² = 36
⇒ BO = 6m
Hence, the distance of the root of the ladder from the base of the wall is 6 m.
Let OB is vertical pole in the figure. In triangle AOB, by pythagoras theorem AB² = OB² + OA² ⇒ 24² = 18² + OA² ⇒ 576 = 324 + OA² ⇒ OA² = 252 ⇒ OA = 6 √7m Hence, the distance of stake from the base of the pole is 6 √7m.
Let OB is vertical pole in the figure.
In triangle AOB, by pythagoras theorem
AB² = OB² + OA²
⇒ 24² = 18² + OA²
⇒ 576 = 324 + OA²
⇒ OA² = 252
⇒ OA = 6 √7m
Hence, the distance of stake from the base of the pole is 6 √7m.
A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from base of the wall.
Let OA is well and AB is ladder in the figure. In triangle AOB, by pythagoras theorem AB² = AO² + OB² ⇒ 10² = 8² + BO² ⇒ 100 = 64 + BO² ⇒ BO² = 36 ⇒ BO = 6m Hence, the distance of the root of the ladder from the base of the wall is 6 m.
Let OA is well and AB is ladder in the figure.
See lessIn triangle AOB, by pythagoras theorem
AB² = AO² + OB²
⇒ 10² = 8² + BO²
⇒ 100 = 64 + BO²
⇒ BO² = 36
⇒ BO = 6m
Hence, the distance of the root of the ladder from the base of the wall is 6 m.
A guy wire attached to a vertical pole of height 18 m is 24 m long and has a stake attached to the other end. How far from the base of the pole should the stake be driven so that the wire will be taut?
Let OB is vertical pole in the figure. In triangle AOB, by pythagoras theorem AB² = OB² + OA² ⇒ 24² = 18² + OA² ⇒ 576 = 324 + OA² ⇒ OA² = 252 ⇒ OA = 6 √7m Hence, the distance of stake from the base of the pole is 6 √7m.
Let OB is vertical pole in the figure.
See lessIn triangle AOB, by pythagoras theorem
AB² = OB² + OA²
⇒ 24² = 18² + OA²
⇒ 576 = 324 + OA²
⇒ OA² = 252
⇒ OA = 6 √7m
Hence, the distance of stake from the base of the pole is 6 √7m.
An aeroplane leaves an airport and flies due north at a speed of 1000 km per hour. At the same time, another aeroplane leaves the same airport and flies due west at a speed of 1200 km per hour. How far apart will be the two planes after 3/2 hours?
E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that Triangles ABE ~ Triangles CFB.
Sides AB and AC and median AD of a triangle ABC are respectively proportional to sides PQ and PR and median PM of another triangle PQR. Show that triangle ABC ~ triangle PQR.