1. Given: The sheet of paper is in rectangular form. Length of sheet = (12) 1/2 cm and Breadth of sheet = (10) 2/3 cm Perimeter of rectangle = 2 (length + breadth) = 2((12)1/2+(10)2/3) = 2(25/2+32/3) = 2(25x3+32x2/6) = 2(75+64/6) = 2x139/6 = 139/3 = (46)1/3 Thus, the perimeter of the rectangular sheetRead more

    Given: The sheet of paper is in rectangular form.
    Length of sheet = (12) 1/2 cm and Breadth of sheet = (10) 2/3 cm
    Perimeter of rectangle = 2 (length + breadth)
    = 2((12)1/2+(10)2/3) = 2(25/2+32/3)
    = 2(25×3+32×2/6) = 2(75+64/6)
    = 2×139/6 = 139/3 = (46)1/3
    Thus, the perimeter of the rectangular sheet is (46)1/3 cm.

    Exercise 2.1 Question 2, 3, 4

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-2/

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  2. Sum of first row = 4/11 + 9/11 + 2/11 = 5/11 [Given] Sum of second row = 3/11 + 5/11 + 7/11 = 3+5+7/11 = 15/11 Sum of third row = 8/11 + 1/11 + 6/11 = 8+1+6/11 = 15/11 Sum of first column = 4/11 + 3/11 + 8/11 = 4+3+8/11 = 15/11 Sum of second column = 9/11 + 5/11 + 1/11 = 9+5+1/11 = 15/11 Sum of thirRead more

    Sum of first row = 4/11 + 9/11 + 2/11 = 5/11 [Given]
    Sum of second row = 3/11 + 5/11 + 7/11 = 3+5+7/11 = 15/11
    Sum of third row = 8/11 + 1/11 + 6/11 = 8+1+6/11 = 15/11
    Sum of first column = 4/11 + 3/11 + 8/11 = 4+3+8/11 = 15/11
    Sum of second column = 9/11 + 5/11 + 1/11 = 9+5+1/11 = 15/11
    Sum of third column = 2/11 + 7/11 + 6/11 = 2+7+6/11 = 15/11
    Sum of first diagonal (left to right) = 4/11+5/11+6/11/11 = 15/11
    Sum of second diagonal (left to right) = 2/11+5/11+8/11/11 = 15/11

    Since the sum of fractions in each row, in each column and along the diagonals are same,
    therefore it is a magic square.

    Exercise 2.1 Question 2, 3, 4

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-2/

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  3. 2/9, 2/3, 8/21 ⇒ 14/63, 42/63, 24/63 [Converting into like fractions] ⇒ 42/63 > 24/63 > 14/63 [Arranging in descending order] Therefore, 2/3 > 8/21 > 2/9 Exercise 2.1 Question 2, 3, 4 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-2/

    2/9, 2/3, 8/21
    ⇒ 14/63, 42/63, 24/63 [Converting into like fractions]
    ⇒ 42/63 > 24/63 > 14/63 [Arranging in descending order]
    Therefore, 2/3 > 8/21 > 2/9

    Exercise 2.1 Question 2, 3, 4

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-2/

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  4. 2-3/5 = 10-3/5 = 7/5 Exercise 2.1 Question 1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-2/

    2-3/5 = 10-3/5 = 7/5

    Exercise 2.1 Question 1

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-2/

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