1. To be divisible by 2, 4, 5, 8, and 10, a number must be a multiple of their least common multiple (LCM), which is 40. Checking each: • 572: Not divisible by 8 or 40. • 2352: Not divisible by 5. • 5600: Divisible by 40. • 6000: Divisible by 40. • 77622160: Divisible by 40. Thus, 5600, 6000, and 77622Read more

    To be divisible by 2, 4, 5, 8, and 10, a number must be a multiple of their least common multiple (LCM), which is 40. Checking each:
    • 572: Not divisible by 8 or 40.
    • 2352: Not divisible by 5.
    • 5600: Divisible by 40.
    • 6000: Divisible by 40.
    • 77622160: Divisible by 40.
    Thus, 5600, 6000, and 77622160 satisfy all conditions for divisibility by the given numbers.

    For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/

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  2. To find two numbers whose product is 10000 without a 0 in their units digit, consider: • 25 and 400: 25 × 400 = 10000. Both end in non-zero digits (5 and 4), fulfilling the condition. While the product must equal 10000, ensuring no trailing zeroes in the individual numbers' digits limits valid combiRead more

    To find two numbers whose product is 10000 without a 0 in their units digit, consider:
    • 25 and 400: 25 × 400 = 10000.
    Both end in non-zero digits (5 and 4), fulfilling the condition. While the product must equal 10000, ensuring no trailing zeroes in the individual numbers’ digits limits valid combinations, and this pair provides one such solution.

    For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/

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  3. To identify numbers divisible by 4 between 330 and 340, test each number for divisibility. Starting from 330: • 330 ÷ 4 = 82.5, not divisible. • 332 ÷ 4 = 83, divisible. • 336 ÷ 4 = 84, divisible. • 340 ÷ 4 = 85, outside the range. Thus, 332 and 336 are the only numbers in this interval that divideRead more

    To identify numbers divisible by 4 between 330 and 340, test each number for divisibility. Starting from 330:
    • 330 ÷ 4 = 82.5, not divisible.
    • 332 ÷ 4 = 83, divisible.
    • 336 ÷ 4 = 84, divisible.
    • 340 ÷ 4 = 85, outside the range.
    Thus, 332 and 336 are the only numbers in this interval that divide evenly by 4, meeting the criteria.

    For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/

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  4. To find numbers divisible by 4: • 1730 – 1740: Test divisibility: 1732 ÷ 4 = 433, 1736 ÷ 4 = 434, 1740 ÷ 4 = 435. Results are 1732, 1736, and 1740. • 2030 – 2040: Test divisibility: 2032 ÷ 4 = 508, 2036 ÷ 4 = 509, 2040 ÷ 4 = 510. Results are 2032, 2036, and 2040. These numbers meet the condition, beRead more

    To find numbers divisible by 4:
    • 1730 – 1740: Test divisibility: 1732 ÷ 4 = 433, 1736 ÷ 4 = 434, 1740 ÷ 4 = 435. Results are 1732, 1736, and 1740.
    • 2030 – 2040: Test divisibility: 2032 ÷ 4 = 508, 2036 ÷ 4 = 509, 2040 ÷ 4 = 510. Results are 2032, 2036, and 2040.
    These numbers meet the condition, being multiples of 4 within their respective ranges.
    For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/

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  5. The smallest 4-digit palindrome divisible by 4 is 2002, found after testing smaller palindromes for divisibility. Similarly, the largest 4-digit palindrome divisible by 4 is 9999, meeting the symmetry and divisibility conditions. Verifying divisors ensures no false inclusions or exclusions occur, paRead more

    The smallest 4-digit palindrome divisible by 4 is 2002, found after testing smaller palindromes for divisibility. Similarly, the largest 4-digit palindrome divisible by 4 is 9999, meeting the symmetry and divisibility conditions. Verifying divisors ensures no false inclusions or exclusions occur, particularly as the symmetry constraints require careful handling of the specific numeric properties concerning modularity and arithmetic parity.

    For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/

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