Tiwari Academy stands out as the best platform for NCERT solutions, offering precise and thoroughly explained answers created by an expert team. Its solutions align with the latest CBSE syllabus, covering every topic in a detailed and simplified manner. The platform provides free resources, includinRead more
Tiwari Academy stands out as the best platform for NCERT solutions, offering precise and thoroughly explained answers created by an expert team. Its solutions align with the latest CBSE syllabus, covering every topic in a detailed and simplified manner. The platform provides free resources, including chapter-wise answers, mock tests, and exemplar solutions, ensuring students gain a clear understanding of concepts. Additionally, its user-friendly interface and downloadable materials make it an invaluable resource for students aiming for academic excellence.
A common Class 6 mensuration example is calculating the area and perimeter of a rectangular park. For instance, if the park's length is 20 m and its breadth is 15 m: • Area (space enclosed): length x breadth = 20 x 15 = 300 square meters. • Perimeter (boundary length): 2 x (length + breadth) = 2 x (Read more
A common Class 6 mensuration example is calculating the area and perimeter of a rectangular park. For instance, if the park’s length is 20 m and its breadth is 15 m:
• Area (space enclosed): length x breadth = 20 x 15 = 300 square meters.
• Perimeter (boundary length): 2 x (length + breadth) = 2 x (20 + 15) = 70 meters.
Mensuration involves practical applications like determining land size or fencing requirements, making it essential for real-world calculations.
The formulas for perimeter and area are essential in Class 7 mathematics: • Perimeter: Rectangle = 2 x (length + breadth), Square = 4 x side. • Area: Rectangle = length x breadth, Square = side x side, Triangle = 1/2 x base x height. These formulas are used to calculate the total boundary length (peRead more
The formulas for perimeter and area are essential in Class 7 mathematics:
• Perimeter: Rectangle = 2 x (length + breadth), Square = 4 x side.
• Area: Rectangle = length x breadth, Square = side x side, Triangle = 1/2 x base x height.
These formulas are used to calculate the total boundary length (perimeter) or the space enclosed by a 2D figure (area). They apply to various real-life scenarios like fencing and flooring.
a. A square To form a square, its perimeter equals 4 x side length. The given string length of 36 cm acts as the perimeter. Using the formula: 36 = 4 x side, divide 36 by 4 to calculate the side length: side = 36 ÷ 4 = 9 cm. This ensures that each side of the square measures 9 cm, making full use ofRead more
a. A square
To form a square, its perimeter equals 4 x side length. The given string length of 36 cm acts as the perimeter. Using the formula: 36 = 4 x side, divide 36 by 4 to calculate the side length: side = 36 ÷ 4 = 9 cm. This ensures that each side of the square measures 9 cm, making full use of the string without any excess.
b. A triangle with all sides of equal length
In an equilateral triangle, all sides are equal. The perimeter of the triangle is calculated as 3 x side. Given a string length of 36 cm as the perimeter: 36 = 3 x side. Divide 36 by 3 to find side = 36 ÷ 3 = 12 cm. Thus, each side of the triangle will measure 12 cm, perfectly using the entire string length for the equilateral triangle.
c. A hexagon (six-sided figure) with sides of equal length
For a regular hexagon, all six sides are of equal length. Its perimeter is calculated as 6 x side. Using the given string length of 36 cm as the perimeter: 36 = 6 x side. Solving for side gives side = 36 ÷ 6 = 6 cm. This means each side of the hexagon measures 6 cm, ensuring the string is fully utilized to form the six-sided figure.
The perimeter of the rectangular park is calculated as 2 x (length + breadth) = 2 x (150 + 120) = 2 x 270 = 540 m. Fencing costs 40 rupees per metre. Multiply the total perimeter by the cost per metre to find the total cost: 540 x 40 = 21600 rupees. This method ensures accurate cost estimation for fRead more
The perimeter of the rectangular park is calculated as 2 x (length + breadth) = 2 x (150 + 120) = 2 x 270 = 540 m. Fencing costs 40 rupees per metre. Multiply the total perimeter by the cost per metre to find the total cost: 540 x 40 = 21600 rupees. This method ensures accurate cost estimation for fencing any rectangular area.
Which is the best website providing NCERT Solutions?
Tiwari Academy stands out as the best platform for NCERT solutions, offering precise and thoroughly explained answers created by an expert team. Its solutions align with the latest CBSE syllabus, covering every topic in a detailed and simplified manner. The platform provides free resources, includinRead more
Tiwari Academy stands out as the best platform for NCERT solutions, offering precise and thoroughly explained answers created by an expert team. Its solutions align with the latest CBSE syllabus, covering every topic in a detailed and simplified manner. The platform provides free resources, including chapter-wise answers, mock tests, and exemplar solutions, ensuring students gain a clear understanding of concepts. Additionally, its user-friendly interface and downloadable materials make it an invaluable resource for students aiming for academic excellence.
See lessWhat is an example of mensuration for Class 6?
A common Class 6 mensuration example is calculating the area and perimeter of a rectangular park. For instance, if the park's length is 20 m and its breadth is 15 m: • Area (space enclosed): length x breadth = 20 x 15 = 300 square meters. • Perimeter (boundary length): 2 x (length + breadth) = 2 x (Read more
A common Class 6 mensuration example is calculating the area and perimeter of a rectangular park. For instance, if the park’s length is 20 m and its breadth is 15 m:
• Area (space enclosed): length x breadth = 20 x 15 = 300 square meters.
• Perimeter (boundary length): 2 x (length + breadth) = 2 x (20 + 15) = 70 meters.
Mensuration involves practical applications like determining land size or fencing requirements, making it essential for real-world calculations.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
What is the formula for perimeter and area chapter class 7?
The formulas for perimeter and area are essential in Class 7 mathematics: • Perimeter: Rectangle = 2 x (length + breadth), Square = 4 x side. • Area: Rectangle = length x breadth, Square = side x side, Triangle = 1/2 x base x height. These formulas are used to calculate the total boundary length (peRead more
The formulas for perimeter and area are essential in Class 7 mathematics:
• Perimeter: Rectangle = 2 x (length + breadth), Square = 4 x side.
• Area: Rectangle = length x breadth, Square = side x side, Triangle = 1/2 x base x height.
These formulas are used to calculate the total boundary length (perimeter) or the space enclosed by a 2D figure (area). They apply to various real-life scenarios like fencing and flooring.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
A piece of string is 36 cm long. What will be the length of each side, if it is used to form: a. A square, b. A triangle with all sides of equal length, and c. A hexagon (a six sided closed figure) with sides of equal length?
a. A square To form a square, its perimeter equals 4 x side length. The given string length of 36 cm acts as the perimeter. Using the formula: 36 = 4 x side, divide 36 by 4 to calculate the side length: side = 36 ÷ 4 = 9 cm. This ensures that each side of the square measures 9 cm, making full use ofRead more
a. A square
To form a square, its perimeter equals 4 x side length. The given string length of 36 cm acts as the perimeter. Using the formula: 36 = 4 x side, divide 36 by 4 to calculate the side length: side = 36 ÷ 4 = 9 cm. This ensures that each side of the square measures 9 cm, making full use of the string without any excess.
b. A triangle with all sides of equal length
In an equilateral triangle, all sides are equal. The perimeter of the triangle is calculated as 3 x side. Given a string length of 36 cm as the perimeter: 36 = 3 x side. Divide 36 by 3 to find side = 36 ÷ 3 = 12 cm. Thus, each side of the triangle will measure 12 cm, perfectly using the entire string length for the equilateral triangle.
c. A hexagon (six-sided figure) with sides of equal length
For a regular hexagon, all six sides are of equal length. Its perimeter is calculated as 6 x side. Using the given string length of 36 cm as the perimeter: 36 = 6 x side. Solving for side gives side = 36 ÷ 6 = 6 cm. This means each side of the hexagon measures 6 cm, ensuring the string is fully utilized to form the six-sided figure.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
What would be the cost of fencing a rectangular park whose length is 150 m and breadth is 120 m, if the fence costs `40 per metre?
The perimeter of the rectangular park is calculated as 2 x (length + breadth) = 2 x (150 + 120) = 2 x 270 = 540 m. Fencing costs 40 rupees per metre. Multiply the total perimeter by the cost per metre to find the total cost: 540 x 40 = 21600 rupees. This method ensures accurate cost estimation for fRead more
The perimeter of the rectangular park is calculated as 2 x (length + breadth) = 2 x (150 + 120) = 2 x 270 = 540 m. Fencing costs 40 rupees per metre. Multiply the total perimeter by the cost per metre to find the total cost: 540 x 40 = 21600 rupees. This method ensures accurate cost estimation for fencing any rectangular area.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/