For a rectangle with a length of 12 cm and a breadth of 8 cm, the perimeter is calculated using the formula 2 x (length + breadth). Substituting the given dimensions: 2 x (12 + 8) = 2 x 20 = 40 cm. This perimeter represents the total length around the rectangle's boundary, helping in applications suRead more
For a rectangle with a length of 12 cm and a breadth of 8 cm, the perimeter is calculated using the formula 2 x (length + breadth). Substituting the given dimensions: 2 x (12 + 8) = 2 x 20 = 40 cm. This perimeter represents the total length around the rectangle’s boundary, helping in applications such as framing or fencing rectangular areas.
Examples of regular shapes in surroundings include square tiles, rectangular books, and circular clocks. The perimeters can be calculated using their respective formulas. For instance, a square tile with a side of 10 cm has a perimeter of 4 x 10 = 40 cm. For rectangles, use 2 x (length + breadth), aRead more
Examples of regular shapes in surroundings include square tiles, rectangular books, and circular clocks. The perimeters can be calculated using their respective formulas. For instance, a square tile with a side of 10 cm has a perimeter of 4 x 10 = 40 cm. For rectangles, use 2 x (length + breadth), and for circles, use 2 x π x radius. Understanding these calculations helps generalize perimeter formulas for all regular polygons like pentagons and hexagons.
Area measures the region enclosed by a shape. For a square, the area is calculated as side x side, while for a rectangle, it is length x breadth. For example, if a square has a side of 5 meters, its area is 5 x 5 = 25 square meters. Similarly, a rectangle with length 6 meters and breadth 4 meters haRead more
Area measures the region enclosed by a shape. For a square, the area is calculated as side x side, while for a rectangle, it is length x breadth. For example, if a square has a side of 5 meters, its area is 5 x 5 = 25 square meters. Similarly, a rectangle with length 6 meters and breadth 4 meters has an area of 6 x 4 = 24 square meters. Areas are expressed in square units like square meters.
The area of the rectangular land is length x width = 12 x 10 = 120 square meters. Each flower bed is a square with an area of side x side = 4 x 4 = 16 square meters. Since there are four flower beds, their total area is 4 x 16 = 64 square meters. Subtract the flower bed area from the land area: 120Read more
The area of the rectangular land is length x width = 12 x 10 = 120 square meters. Each flower bed is a square with an area of side x side = 4 x 4 = 16 square meters. Since there are four flower beds, their total area is 4 x 16 = 64 square meters. Subtract the flower bed area from the land area: 120 – 64 = 56 square meters. This represents the remaining land area available.
To find the width of a rectangular garden, use the formula for area: length x width = area. Substituting the given values: 25 x width = 300. Divide both sides by 25 to isolate the width: width = 300 ÷ 25 = 12 meters. This calculation confirms that the garden's width is 12 meters, providing clarity aRead more
To find the width of a rectangular garden, use the formula for area: length x width = area. Substituting the given values: 25 x width = 300. Divide both sides by 25 to isolate the width: width = 300 ÷ 25 = 12 meters. This calculation confirms that the garden’s width is 12 meters, providing clarity about its dimensions based on the given area and length.
The area of the rectangular plot is calculated as length x width = 500 x 200 = 100,000 square meters. The tiling cost is 8 rupees per hundred square meters. Divide the total area by 100 to find the number of units: 100,000 ÷ 100 = 1,000. Multiply by the cost per unit: 1,000 x 8 = 8,000 rupees. The tRead more
The area of the rectangular plot is calculated as length x width = 500 x 200 = 100,000 square meters. The tiling cost is 8 rupees per hundred square meters. Divide the total area by 100 to find the number of units: 100,000 ÷ 100 = 1,000. Multiply by the cost per unit: 1,000 x 8 = 8,000 rupees. The total tiling cost for the entire plot is therefore 8,000 rupees.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer: https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
To find the maximum number of trees, calculate the area of the grove: length x width = 100 x 50 = 5,000 square meters. Each coconut tree requires 25 square meters. Divide the total grove area by the area per tree: 5,000 ÷ 25 = 200. Thus, the grove can accommodate a maximum of 200 coconut trees, ensuRead more
To find the maximum number of trees, calculate the area of the grove: length x width = 100 x 50 = 5,000 square meters. Each coconut tree requires 25 square meters. Divide the total grove area by the area per tree: 5,000 ÷ 25 = 200. Thus, the grove can accommodate a maximum of 200 coconut trees, ensuring each tree has the required space for growth and proper planting.
Area measures the space enclosed within a shape, expressed in square units, such as square meters. For instance, the area of a rectangle is length x breadth. Perimeter is the total length around a shape, calculated as the sum of its sides. For example, a rectangle's perimeter is 2 x (length + breadtRead more
Area measures the space enclosed within a shape, expressed in square units, such as square meters. For instance, the area of a rectangle is length x breadth. Perimeter is the total length around a shape, calculated as the sum of its sides. For example, a rectangle’s perimeter is 2 x (length + breadth). Both concepts are foundational for understanding dimensions of 2D shapes, widely applied in practical measurements like fencing and flooring.
Toshi ran on the inner rectangular track, whose perimeter is calculated as 2 x (length + breadth) = 2 x (60 + 30) = 180 m. In 7 rounds, Toshi covered 7 x 180 = 1260 m. Akshi, running 5 rounds on the outer track, covered 1100 m. Comparing distances, Toshi’s total of 1260 m exceeds Akshi’s 1100 m, makRead more
Toshi ran on the inner rectangular track, whose perimeter is calculated as 2 x (length + breadth) = 2 x (60 + 30) = 180 m. In 7 rounds, Toshi covered 7 x 180 = 1260 m. Akshi, running 5 rounds on the outer track, covered 1100 m. Comparing distances, Toshi’s total of 1260 m exceeds Akshi’s 1100 m, making Toshi the one who covered a longer distance during their exercise.
The perimeter of a triangle is calculated by summing the lengths of all three sides. Given a perimeter of 55 cm and two side lengths of 20 cm and 14 cm, the equation becomes 55 = 20 + 14 + third side. Simplify to find the third side: 55 - (20 + 14) = 55 - 34 = 21 cm. This approach helps determine aRead more
The perimeter of a triangle is calculated by summing the lengths of all three sides. Given a perimeter of 55 cm and two side lengths of 20 cm and 14 cm, the equation becomes 55 = 20 + 14 + third side. Simplify to find the third side: 55 – (20 + 14) = 55 – 34 = 21 cm. This approach helps determine a missing side when the total perimeter and other side lengths are known.
Consider a rectangle ABCD whose length and breadth are 12 cm and 8 cm, respectively. What is its perimeter?
For a rectangle with a length of 12 cm and a breadth of 8 cm, the perimeter is calculated using the formula 2 x (length + breadth). Substituting the given dimensions: 2 x (12 + 8) = 2 x 20 = 40 cm. This perimeter represents the total length around the rectangle's boundary, helping in applications suRead more
For a rectangle with a length of 12 cm and a breadth of 8 cm, the perimeter is calculated using the formula 2 x (length + breadth). Substituting the given dimensions: 2 x (12 + 8) = 2 x 20 = 40 cm. This perimeter represents the total length around the rectangle’s boundary, helping in applications such as framing or fencing rectangular areas.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
Find various objects from your surroundings that have regular shapes and find their perimeters. Also, generalise your understanding for the perimeter of other regular polygons.
Examples of regular shapes in surroundings include square tiles, rectangular books, and circular clocks. The perimeters can be calculated using their respective formulas. For instance, a square tile with a side of 10 cm has a perimeter of 4 x 10 = 40 cm. For rectangles, use 2 x (length + breadth), aRead more
Examples of regular shapes in surroundings include square tiles, rectangular books, and circular clocks. The perimeters can be calculated using their respective formulas. For instance, a square tile with a side of 10 cm has a perimeter of 4 x 10 = 40 cm. For rectangles, use 2 x (length + breadth), and for circles, use 2 x π x radius. Understanding these calculations helps generalize perimeter formulas for all regular polygons like pentagons and hexagons.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
What is an area? Find area of a square and area of a rectangle.
Area measures the region enclosed by a shape. For a square, the area is calculated as side x side, while for a rectangle, it is length x breadth. For example, if a square has a side of 5 meters, its area is 5 x 5 = 25 square meters. Similarly, a rectangle with length 6 meters and breadth 4 meters haRead more
Area measures the region enclosed by a shape. For a square, the area is calculated as side x side, while for a rectangle, it is length x breadth. For example, if a square has a side of 5 meters, its area is 5 x 5 = 25 square meters. Similarly, a rectangle with length 6 meters and breadth 4 meters has an area of 6 x 4 = 24 square meters. Areas are expressed in square units like square meters.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
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Four square flower beds each of side 4 m are in four corners on a piece of land 12 m long and 10 m wide. Find the area of the remaining part of the land.
The area of the rectangular land is length x width = 12 x 10 = 120 square meters. Each flower bed is a square with an area of side x side = 4 x 4 = 16 square meters. Since there are four flower beds, their total area is 4 x 16 = 64 square meters. Subtract the flower bed area from the land area: 120Read more
The area of the rectangular land is length x width = 12 x 10 = 120 square meters. Each flower bed is a square with an area of side x side = 4 x 4 = 16 square meters. Since there are four flower beds, their total area is 4 x 16 = 64 square meters. Subtract the flower bed area from the land area: 120 – 64 = 56 square meters. This represents the remaining land area available.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
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The area of a rectangular garden 25 m long is 300 sq m. What is the width of the garden?
To find the width of a rectangular garden, use the formula for area: length x width = area. Substituting the given values: 25 x width = 300. Divide both sides by 25 to isolate the width: width = 300 ÷ 25 = 12 meters. This calculation confirms that the garden's width is 12 meters, providing clarity aRead more
To find the width of a rectangular garden, use the formula for area: length x width = area. Substituting the given values: 25 x width = 300. Divide both sides by 25 to isolate the width: width = 300 ÷ 25 = 12 meters. This calculation confirms that the garden’s width is 12 meters, providing clarity about its dimensions based on the given area and length.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
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What is the cost of tiling a rectangular plot of land 500 m long and 200 m wide at the rate of ` 8 per hundred sq m?
The area of the rectangular plot is calculated as length x width = 500 x 200 = 100,000 square meters. The tiling cost is 8 rupees per hundred square meters. Divide the total area by 100 to find the number of units: 100,000 ÷ 100 = 1,000. Multiply by the cost per unit: 1,000 x 8 = 8,000 rupees. The tRead more
The area of the rectangular plot is calculated as length x width = 500 x 200 = 100,000 square meters. The tiling cost is 8 rupees per hundred square meters. Divide the total area by 100 to find the number of units: 100,000 ÷ 100 = 1,000. Multiply by the cost per unit: 1,000 x 8 = 8,000 rupees. The total tiling cost for the entire plot is therefore 8,000 rupees.
See lessFor more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
A rectangular coconut grove is 100 m long and 50 m wide. If each coconut tree requires 25 sq m, what is the maximum number of trees that can be planted in this grove?
To find the maximum number of trees, calculate the area of the grove: length x width = 100 x 50 = 5,000 square meters. Each coconut tree requires 25 square meters. Divide the total grove area by the area per tree: 5,000 ÷ 25 = 200. Thus, the grove can accommodate a maximum of 200 coconut trees, ensuRead more
To find the maximum number of trees, calculate the area of the grove: length x width = 100 x 50 = 5,000 square meters. Each coconut tree requires 25 square meters. Divide the total grove area by the area per tree: 5,000 ÷ 25 = 200. Thus, the grove can accommodate a maximum of 200 coconut trees, ensuring each tree has the required space for growth and proper planting.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
What is area and its perimeter Class 6?
Area measures the space enclosed within a shape, expressed in square units, such as square meters. For instance, the area of a rectangle is length x breadth. Perimeter is the total length around a shape, calculated as the sum of its sides. For example, a rectangle's perimeter is 2 x (length + breadtRead more
Area measures the space enclosed within a shape, expressed in square units, such as square meters. For instance, the area of a rectangle is length x breadth. Perimeter is the total length around a shape, calculated as the sum of its sides. For example, a rectangle’s perimeter is 2 x (length + breadth). Both concepts are foundational for understanding dimensions of 2D shapes, widely applied in practical measurements like fencing and flooring.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
What total distance Toshi has covered in 7 rounds who ran a longer distance?
Toshi ran on the inner rectangular track, whose perimeter is calculated as 2 x (length + breadth) = 2 x (60 + 30) = 180 m. In 7 rounds, Toshi covered 7 x 180 = 1260 m. Akshi, running 5 rounds on the outer track, covered 1100 m. Comparing distances, Toshi’s total of 1260 m exceeds Akshi’s 1100 m, makRead more
Toshi ran on the inner rectangular track, whose perimeter is calculated as 2 x (length + breadth) = 2 x (60 + 30) = 180 m. In 7 rounds, Toshi covered 7 x 180 = 1260 m. Akshi, running 5 rounds on the outer track, covered 1100 m. Comparing distances, Toshi’s total of 1260 m exceeds Akshi’s 1100 m, making Toshi the one who covered a longer distance during their exercise.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
Find the length of the third side of a triangle having a perimeter of 55 cm and having two sides of length 20 cm and 14 cm, respectively.
The perimeter of a triangle is calculated by summing the lengths of all three sides. Given a perimeter of 55 cm and two side lengths of 20 cm and 14 cm, the equation becomes 55 = 20 + 14 + third side. Simplify to find the third side: 55 - (20 + 14) = 55 - 34 = 21 cm. This approach helps determine aRead more
The perimeter of a triangle is calculated by summing the lengths of all three sides. Given a perimeter of 55 cm and two side lengths of 20 cm and 14 cm, the equation becomes 55 = 20 + 14 + third side. Simplify to find the third side: 55 – (20 + 14) = 55 – 34 = 21 cm. This approach helps determine a missing side when the total perimeter and other side lengths are known.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/