a. A square To form a square, its perimeter equals 4 x side length. The given string length of 36 cm acts as the perimeter. Using the formula: 36 = 4 x side, divide 36 by 4 to calculate the side length: side = 36 ÷ 4 = 9 cm. This ensures that each side of the square measures 9 cm, making full use ofRead more
a. A square
To form a square, its perimeter equals 4 x side length. The given string length of 36 cm acts as the perimeter. Using the formula: 36 = 4 x side, divide 36 by 4 to calculate the side length: side = 36 ÷ 4 = 9 cm. This ensures that each side of the square measures 9 cm, making full use of the string without any excess.
b. A triangle with all sides of equal length
In an equilateral triangle, all sides are equal. The perimeter of the triangle is calculated as 3 x side. Given a string length of 36 cm as the perimeter: 36 = 3 x side. Divide 36 by 3 to find side = 36 ÷ 3 = 12 cm. Thus, each side of the triangle will measure 12 cm, perfectly using the entire string length for the equilateral triangle.
c. A hexagon (six-sided figure) with sides of equal length
For a regular hexagon, all six sides are of equal length. Its perimeter is calculated as 6 x side. Using the given string length of 36 cm as the perimeter: 36 = 6 x side. Solving for side gives side = 36 ÷ 6 = 6 cm. This means each side of the hexagon measures 6 cm, ensuring the string is fully utilized to form the six-sided figure.
The perimeter of the rectangular park is calculated as 2 x (length + breadth) = 2 x (150 + 120) = 2 x 270 = 540 m. Fencing costs 40 rupees per metre. Multiply the total perimeter by the cost per metre to find the total cost: 540 x 40 = 21600 rupees. This method ensures accurate cost estimation for fRead more
The perimeter of the rectangular park is calculated as 2 x (length + breadth) = 2 x (150 + 120) = 2 x 270 = 540 m. Fencing costs 40 rupees per metre. Multiply the total perimeter by the cost per metre to find the total cost: 540 x 40 = 21600 rupees. This method ensures accurate cost estimation for fencing any rectangular area.
To calculate the total rope required, first find the perimeter of the rectangular field using 2 x (length + breadth). Substituting the values: 2 x (230 + 160) = 2 x 390 = 780 m. Since the farmer wants to fence the field with 3 rounds of rope, multiply the perimeter by 3: 3 x 780 = 2340 m. This ensurRead more
To calculate the total rope required, first find the perimeter of the rectangular field using 2 x (length + breadth). Substituting the values: 2 x (230 + 160) = 2 x 390 = 780 m. Since the farmer wants to fence the field with 3 rounds of rope, multiply the perimeter by 3: 3 x 780 = 2340 m. This ensures enough rope to surround the field three times, securing the boundary effectively.
For Akshi, the perimeter of the outer track is 2 x (70 + 40) = 220 m. Distance covered in 5 rounds = 5 x 220 = 1100 m. For Toshi, the inner track perimeter is 2 x (60 + 30) = 180 m. Distance covered in 7 rounds = 7 x 180 = 1260 m. Comparing distances, Toshi covers 1260 m, which is more than Akshi'sRead more
For Akshi, the perimeter of the outer track is 2 x (70 + 40) = 220 m. Distance covered in 5 rounds = 5 x 220 = 1100 m. For Toshi, the inner track perimeter is 2 x (60 + 30) = 180 m. Distance covered in 7 rounds = 7 x 180 = 1260 m. Comparing distances, Toshi covers 1260 m, which is more than Akshi’s 1100 m. Toshi ran a longer distance overall.
The perimeter of the rectangular outer track where Akshi runs is calculated as 2 x (length + breadth) = 2 x (70 + 40) = 2 x 110 = 220 m. Akshi completes 5 rounds of this track, so her total distance covered is 5 x 220 = 1100 m. This calculation provides the exact distance Akshi ran during her exerciRead more
The perimeter of the rectangular outer track where Akshi runs is calculated as 2 x (length + breadth) = 2 x (70 + 40) = 2 x 110 = 220 m. Akshi completes 5 rounds of this track, so her total distance covered is 5 x 220 = 1100 m. This calculation provides the exact distance Akshi ran during her exercise on the outer rectangular track.
Toshi runs on the inner rectangular track with a perimeter of 2 x (length + breadth) = 2 x (60 + 30) = 2 x 90 = 180 m. Completing 7 rounds, Toshi's total distance is 7 x 180 = 1260 m. Comparing with Akshi's distance of 1100 m, Toshi covered a longer distance by 160 m, making her the one who ran fartRead more
Toshi runs on the inner rectangular track with a perimeter of 2 x (length + breadth) = 2 x (60 + 30) = 2 x 90 = 180 m. Completing 7 rounds, Toshi’s total distance is 7 x 180 = 1260 m. Comparing with Akshi’s distance of 1100 m, Toshi covered a longer distance by 160 m, making her the one who ran farther overall.
The inner track perimeter is 4 x 100 = 400 m, and the outer track perimeter is 4 x 150 = 600 m. To ensure both runners finish at the same point after 350 m, their starting points must account for their track perimeters. Use the ratio 350/400 for the inner track and 350/600 for the outer track to finRead more
The inner track perimeter is 4 x 100 = 400 m, and the outer track perimeter is 4 x 150 = 600 m. To ensure both runners finish at the same point after 350 m, their starting points must account for their track perimeters. Use the ratio 350/400 for the inner track and 350/600 for the outer track to find relative start positions. This ensures both runners finish simultaneously at the common finish line.
Cut a piece of paper into random shapes. First, estimate the total boundary length based on observation. Then, measure each side using a ruler or measuring tape. Sum the lengths of all sides to calculate the exact perimeter. Compare the estimated perimeter with the calculated one to understand the aRead more
Cut a piece of paper into random shapes. First, estimate the total boundary length based on observation. Then, measure each side using a ruler or measuring tape. Sum the lengths of all sides to calculate the exact perimeter. Compare the estimated perimeter with the calculated one to understand the accuracy of your estimation. This activity enhances understanding of the concept of perimeter and the importance of precise measurement in everyday calculations.
Regular polygons are shapes with equal-length sides and equal angles. Examples include squares, equilateral triangles, and regular hexagons. For an equilateral triangle, the perimeter is calculated as the sum of its three equal sides. Using the formula 3 x side length, if each side is 6 cm, the periRead more
Regular polygons are shapes with equal-length sides and equal angles. Examples include squares, equilateral triangles, and regular hexagons. For an equilateral triangle, the perimeter is calculated as the sum of its three equal sides. Using the formula 3 x side length, if each side is 6 cm, the perimeter is 3 x 6 = 18 cm. This formula simplifies the calculation of the perimeter for all equilateral triangles, aiding in geometric studies and practical applications.
To find the uncarpeted area of the floor, first calculate the area of the rectangular floor as length x width = 5 x 4 = 20 square meters. Next, find the carpet area using side x side = 3 x 3 = 9 square meters. Subtract the carpet area from the floor area: 20 - 9 = 11 square meters. This calculationRead more
To find the uncarpeted area of the floor, first calculate the area of the rectangular floor as length x width = 5 x 4 = 20 square meters. Next, find the carpet area using side x side = 3 x 3 = 9 square meters. Subtract the carpet area from the floor area: 20 – 9 = 11 square meters. This calculation ensures an accurate measure of the uncovered portion of the floor.
A piece of string is 36 cm long. What will be the length of each side, if it is used to form: a. A square, b. A triangle with all sides of equal length, and c. A hexagon (a six sided closed figure) with sides of equal length?
a. A square To form a square, its perimeter equals 4 x side length. The given string length of 36 cm acts as the perimeter. Using the formula: 36 = 4 x side, divide 36 by 4 to calculate the side length: side = 36 ÷ 4 = 9 cm. This ensures that each side of the square measures 9 cm, making full use ofRead more
a. A square
To form a square, its perimeter equals 4 x side length. The given string length of 36 cm acts as the perimeter. Using the formula: 36 = 4 x side, divide 36 by 4 to calculate the side length: side = 36 ÷ 4 = 9 cm. This ensures that each side of the square measures 9 cm, making full use of the string without any excess.
b. A triangle with all sides of equal length
In an equilateral triangle, all sides are equal. The perimeter of the triangle is calculated as 3 x side. Given a string length of 36 cm as the perimeter: 36 = 3 x side. Divide 36 by 3 to find side = 36 ÷ 3 = 12 cm. Thus, each side of the triangle will measure 12 cm, perfectly using the entire string length for the equilateral triangle.
c. A hexagon (six-sided figure) with sides of equal length
For a regular hexagon, all six sides are of equal length. Its perimeter is calculated as 6 x side. Using the given string length of 36 cm as the perimeter: 36 = 6 x side. Solving for side gives side = 36 ÷ 6 = 6 cm. This means each side of the hexagon measures 6 cm, ensuring the string is fully utilized to form the six-sided figure.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
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What would be the cost of fencing a rectangular park whose length is 150 m and breadth is 120 m, if the fence costs `40 per metre?
The perimeter of the rectangular park is calculated as 2 x (length + breadth) = 2 x (150 + 120) = 2 x 270 = 540 m. Fencing costs 40 rupees per metre. Multiply the total perimeter by the cost per metre to find the total cost: 540 x 40 = 21600 rupees. This method ensures accurate cost estimation for fRead more
The perimeter of the rectangular park is calculated as 2 x (length + breadth) = 2 x (150 + 120) = 2 x 270 = 540 m. Fencing costs 40 rupees per metre. Multiply the total perimeter by the cost per metre to find the total cost: 540 x 40 = 21600 rupees. This method ensures accurate cost estimation for fencing any rectangular area.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
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A farmer has a rectangular field having length 230 m and breadth 160 m. He wants to fence it with 3 rounds of rope as shown. What is the total length of rope needed?
To calculate the total rope required, first find the perimeter of the rectangular field using 2 x (length + breadth). Substituting the values: 2 x (230 + 160) = 2 x 390 = 780 m. Since the farmer wants to fence the field with 3 rounds of rope, multiply the perimeter by 3: 3 x 780 = 2340 m. This ensurRead more
To calculate the total rope required, first find the perimeter of the rectangular field using 2 x (length + breadth). Substituting the values: 2 x (230 + 160) = 2 x 390 = 780 m. Since the farmer wants to fence the field with 3 rounds of rope, multiply the perimeter by 3: 3 x 780 = 2340 m. This ensures enough rope to surround the field three times, securing the boundary effectively.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
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Akshi and Toshi start running along the rectangular tracks as shown in the figure. Akshi runs along the outer track and completes 5 rounds. Toshi runs along the inner track and completes 7 rounds. Now, they are wondering who ran more. Find out who ran the longer distance.
For Akshi, the perimeter of the outer track is 2 x (70 + 40) = 220 m. Distance covered in 5 rounds = 5 x 220 = 1100 m. For Toshi, the inner track perimeter is 2 x (60 + 30) = 180 m. Distance covered in 7 rounds = 7 x 180 = 1260 m. Comparing distances, Toshi covers 1260 m, which is more than Akshi'sRead more
For Akshi, the perimeter of the outer track is 2 x (70 + 40) = 220 m. Distance covered in 5 rounds = 5 x 220 = 1100 m. For Toshi, the inner track perimeter is 2 x (60 + 30) = 180 m. Distance covered in 7 rounds = 7 x 180 = 1260 m. Comparing distances, Toshi covers 1260 m, which is more than Akshi’s 1100 m. Toshi ran a longer distance overall.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
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Find out the total distance Akshi has covered in 5 rounds.
The perimeter of the rectangular outer track where Akshi runs is calculated as 2 x (length + breadth) = 2 x (70 + 40) = 2 x 110 = 220 m. Akshi completes 5 rounds of this track, so her total distance covered is 5 x 220 = 1100 m. This calculation provides the exact distance Akshi ran during her exerciRead more
The perimeter of the rectangular outer track where Akshi runs is calculated as 2 x (length + breadth) = 2 x (70 + 40) = 2 x 110 = 220 m. Akshi completes 5 rounds of this track, so her total distance covered is 5 x 220 = 1100 m. This calculation provides the exact distance Akshi ran during her exercise on the outer rectangular track.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
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Find out the total distance Toshi has covered in 7 rounds. Who ran a longer distance?
Toshi runs on the inner rectangular track with a perimeter of 2 x (length + breadth) = 2 x (60 + 30) = 2 x 90 = 180 m. Completing 7 rounds, Toshi's total distance is 7 x 180 = 1260 m. Comparing with Akshi's distance of 1100 m, Toshi covered a longer distance by 160 m, making her the one who ran fartRead more
Toshi runs on the inner rectangular track with a perimeter of 2 x (length + breadth) = 2 x (60 + 30) = 2 x 90 = 180 m. Completing 7 rounds, Toshi’s total distance is 7 x 180 = 1260 m. Comparing with Akshi’s distance of 1100 m, Toshi covered a longer distance by 160 m, making her the one who ran farther overall.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
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In races, usually there is a common finish line for all the runners. Here are two square running tracks with the inner track of 100 m each side and outer track of 150 m each side. The common finishing line for both runners is shown by the flags in the figure which are in the center of one of the sides of the tracks. If the total race is of 350 m, then we have to find out where the starting positions of the two runners should be on these two tracks so that they both have a common finishing line after they run for 350 m. Mark the starting points of the runner on the inner track as ‘A’ and the runner on the outer track as ‘B’.
The inner track perimeter is 4 x 100 = 400 m, and the outer track perimeter is 4 x 150 = 600 m. To ensure both runners finish at the same point after 350 m, their starting points must account for their track perimeters. Use the ratio 350/400 for the inner track and 350/600 for the outer track to finRead more
The inner track perimeter is 4 x 100 = 400 m, and the outer track perimeter is 4 x 150 = 600 m. To ensure both runners finish at the same point after 350 m, their starting points must account for their track perimeters. Use the ratio 350/400 for the inner track and 350/600 for the outer track to find relative start positions. This ensures both runners finish simultaneously at the common finish line.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
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Take a rough sheet of paper or a sheet of newspaper. Make a few random shapes by cutting the paper in different ways. Estimate the total length of the boundaries of each shape then use a scale or measuring tape to measure and verify the perimeter for each shape.
Cut a piece of paper into random shapes. First, estimate the total boundary length based on observation. Then, measure each side using a ruler or measuring tape. Sum the lengths of all sides to calculate the exact perimeter. Compare the estimated perimeter with the calculated one to understand the aRead more
Cut a piece of paper into random shapes. First, estimate the total boundary length based on observation. Then, measure each side using a ruler or measuring tape. Sum the lengths of all sides to calculate the exact perimeter. Compare the estimated perimeter with the calculated one to understand the accuracy of your estimation. This activity enhances understanding of the concept of perimeter and the importance of precise measurement in everyday calculations.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
What is regular polygons? Find perimeter of an equilateral triangle.
Regular polygons are shapes with equal-length sides and equal angles. Examples include squares, equilateral triangles, and regular hexagons. For an equilateral triangle, the perimeter is calculated as the sum of its three equal sides. Using the formula 3 x side length, if each side is 6 cm, the periRead more
Regular polygons are shapes with equal-length sides and equal angles. Examples include squares, equilateral triangles, and regular hexagons. For an equilateral triangle, the perimeter is calculated as the sum of its three equal sides. Using the formula 3 x side length, if each side is 6 cm, the perimeter is 3 x 6 = 18 cm. This formula simplifies the calculation of the perimeter for all equilateral triangles, aiding in geometric studies and practical applications.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
A floor is 5 m long and 4 m wide. A square carpet of sides 3 m is laid on the floor. Find the area of the floor that is not carpeted.
To find the uncarpeted area of the floor, first calculate the area of the rectangular floor as length x width = 5 x 4 = 20 square meters. Next, find the carpet area using side x side = 3 x 3 = 9 square meters. Subtract the carpet area from the floor area: 20 - 9 = 11 square meters. This calculationRead more
To find the uncarpeted area of the floor, first calculate the area of the rectangular floor as length x width = 5 x 4 = 20 square meters. Next, find the carpet area using side x side = 3 x 3 = 9 square meters. Subtract the carpet area from the floor area: 20 – 9 = 11 square meters. This calculation ensures an accurate measure of the uncovered portion of the floor.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/