1. The linear function C(d) = 100 + 60d represents the total journey cost, where d is the distance travelled in kilometres. The fixed charge is 100 rupees and the cost increases by 60 rupees for every kilometre. For example, when d equals 0, the cost is 100 rupees and when d equals 1, the cost becomesRead more

    The linear function C(d) = 100 + 60d represents the total journey cost, where d is the distance travelled in kilometres. The fixed charge is 100 rupees and the cost increases by 60 rupees for every kilometre. For example, when d equals 0, the cost is 100 rupees and when d equals 1, the cost becomes 160 rupees. The pattern continues with a constant increase of 60 rupees each time. Therefore, this function represents linear growth because the increase remains fixed.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/

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  2. The height of water in the tank at the start of summer is 3 metres. According to the function h(t) = 3 minus 0.5t, the water level decreases by 0.5 metre every month. For example, after 1 month, the height becomes 2.5 metres and after 2 months, it becomes 2 metres. Since the height decreases by theRead more

    The height of water in the tank at the start of summer is 3 metres. According to the function h(t) = 3 minus 0.5t, the water level decreases by 0.5 metre every month. For example, after 1 month, the height becomes 2.5 metres and after 2 months, it becomes 2 metres. Since the height decreases by the same amount every month, the pattern represents linear decay. The variable t shows the number of months, while h gives the water height.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/

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  3. The plant is initially 1.75 feet tall and grows by 0.5 feet every month. After 7 months, its height becomes 1.75 plus 0.5 multiplied by 7, which equals 5.25 feet. A table from 0 to 10 months will show a regular increase of 0.5 feet each month. If t represents the number of months and h represents thRead more

    The plant is initially 1.75 feet tall and grows by 0.5 feet every month. After 7 months, its height becomes 1.75 plus 0.5 multiplied by 7, which equals 5.25 feet. A table from 0 to 10 months will show a regular increase of 0.5 feet each month. If t represents the number of months and h represents the height, then the relation is h = 1.75 + 0.5t. This represents linear growth because the increase is constant every month.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/

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  4. The mobile phone is bought for 10000 rupees and loses 800 rupees in value every year. After 3 years, the value decreases by 800 multiplied by 3, which equals 2400 rupees. Therefore, the remaining value becomes 10000 minus 2400, which equals 7600 rupees. If t represents the number of years and v reprRead more

    The mobile phone is bought for 10000 rupees and loses 800 rupees in value every year. After 3 years, the value decreases by 800 multiplied by 3, which equals 2400 rupees. Therefore, the remaining value becomes 10000 minus 2400, which equals 7600 rupees. If t represents the number of years and v represents the value of the phone, then the expression is v = 10000 minus 800t. This represents linear decay because the decrease remains constant every year.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/

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  5. Class 9 of Ganita Manjari Maths Chapter 5 “I’m Up and Down and Round and Round” focuses on integers and their operations. It explains positive and negative numbers, representation on a number line and addition and subtraction of integers. The chapter shows real-life applications such as temperature,Read more

    Class 9 of Ganita Manjari Maths Chapter 5 “I’m Up and Down and Round and Round” focuses on integers and their operations. It explains positive and negative numbers, representation on a number line and addition and subtraction of integers. The chapter shows real-life applications such as temperature, altitude and financial transactions. It helps students understand number movement, develop logical thinking and strengthen their understanding of numerical relationships.

     

    For more NCERT Solutions of Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27) Question Answers

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/

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