The growing pattern of square tiles forms a sequence where each stage has 2 more squares than the previous stage. The first four stages contain 1, 3, 5 and 7 squares. Continuing this pattern, the next three stages will contain 9, 11 and 13 squares respectively. Therefore, the complete sequence fromRead more
The growing pattern of square tiles forms a sequence where each stage has 2 more squares than the previous stage. The first four stages contain 1, 3, 5 and 7 squares. Continuing this pattern, the next three stages will contain 9, 11 and 13 squares respectively. Therefore, the complete sequence from Stage 1 to Stage 7 becomes 1, 3, 5, 7, 9, 11 and 13. This is called a linear pattern because the increase between consecutive terms remains constant.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
The auto-rikshaw fare remains fixed at 25 rupees for the first 2 km. After 2 km, the fare increases by 15 rupees for every additional kilometre travelled. For a journey of 10 km, the extra distance after the first 2 km is 8 km. Therefore, the additional fare becomes 15 multiplied by 8, which equalsRead more
The auto-rikshaw fare remains fixed at 25 rupees for the first 2 km. After 2 km, the fare increases by 15 rupees for every additional kilometre travelled. For a journey of 10 km, the extra distance after the first 2 km is 8 km. Therefore, the additional fare becomes 15 multiplied by 8, which equals 120 rupees. Adding this to the fixed fare of 25 rupees, the total fare becomes 145 rupees for travelling 10 km.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
The student begins with 500 rupees in her savings bank account. Every month, she receives an additional 150 rupees as pocket money. At the end of the first month, she will have 650 rupees. After the second month, she will have 800 rupees and the amount will continue increasing regularly. If n represRead more
The student begins with 500 rupees in her savings bank account. Every month, she receives an additional 150 rupees as pocket money. At the end of the first month, she will have 650 rupees. After the second month, she will have 800 rupees and the amount will continue increasing regularly. If n represents the number of months, then the total amount after n months can be written as 500 plus 150n rupees. This is a linear expression because the increase is constant every month.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
The area of a rectangle is calculated by multiplying its length and breadth. Here, the length is fixed at 13 cm. When the breadth is 12 cm, the area becomes 13 multiplied by 12, which equals 156 square cm. For breadth 10 cm, the area becomes 130 square cm and for breadth 8 cm, the area becomes 104 sRead more
The area of a rectangle is calculated by multiplying its length and breadth. Here, the length is fixed at 13 cm. When the breadth is 12 cm, the area becomes 13 multiplied by 12, which equals 156 square cm. For breadth 10 cm, the area becomes 130 square cm and for breadth 8 cm, the area becomes 104 square cm. If the breadth is represented by b, then the linear expression for the area of the rectangle is 13b square cm.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
At the beginning, the rally has 120 members. Every hour, 9 members drop out of the group. After 1 hour, the number becomes 111. After 2 hours, it becomes 102 and the decrease continues regularly. If n represents the number of hours, then the number of members remaining after n hours can be written aRead more
At the beginning, the rally has 120 members. Every hour, 9 members drop out of the group. After 1 hour, the number becomes 111. After 2 hours, it becomes 102 and the decrease continues regularly. If n represents the number of hours, then the number of members remaining after n hours can be written as 120 minus 9n. This expression forms a linear pattern because the number of members decreases by the same amount every hour.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
Predict the number of squares in the next three stages of the pattern and write the sequence of numbers up to Stage 7 of the pattern
The growing pattern of square tiles forms a sequence where each stage has 2 more squares than the previous stage. The first four stages contain 1, 3, 5 and 7 squares. Continuing this pattern, the next three stages will contain 9, 11 and 13 squares respectively. Therefore, the complete sequence fromRead more
The growing pattern of square tiles forms a sequence where each stage has 2 more squares than the previous stage. The first four stages contain 1, 3, 5 and 7 squares. Continuing this pattern, the next three stages will contain 9, 11 and 13 squares respectively. Therefore, the complete sequence from Stage 1 to Stage 7 becomes 1, 3, 5, 7, 9, 11 and 13. This is called a linear pattern because the increase between consecutive terms remains constant.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessAn auto-rikshaw fare starts at rupees 25 and remains the same for the initial 2 km. Then it increases by rupees 15 per km. What will be the fare for a travel of 10 km?
The auto-rikshaw fare remains fixed at 25 rupees for the first 2 km. After 2 km, the fare increases by 15 rupees for every additional kilometre travelled. For a journey of 10 km, the extra distance after the first 2 km is 8 km. Therefore, the additional fare becomes 15 multiplied by 8, which equalsRead more
The auto-rikshaw fare remains fixed at 25 rupees for the first 2 km. After 2 km, the fare increases by 15 rupees for every additional kilometre travelled. For a journey of 10 km, the extra distance after the first 2 km is 8 km. Therefore, the additional fare becomes 15 multiplied by 8, which equals 120 rupees. Adding this to the fixed fare of 25 rupees, the total fare becomes 145 rupees for travelling 10 km.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessA student has rupees 500 in her savings bank account. She gets rupees 150 every month as pocket money. How much money will she have at the end of every month from the second month onwards? Find a linear expression to represent the amount she will have in the nth month.
The student begins with 500 rupees in her savings bank account. Every month, she receives an additional 150 rupees as pocket money. At the end of the first month, she will have 650 rupees. After the second month, she will have 800 rupees and the amount will continue increasing regularly. If n represRead more
The student begins with 500 rupees in her savings bank account. Every month, she receives an additional 150 rupees as pocket money. At the end of the first month, she will have 650 rupees. After the second month, she will have 800 rupees and the amount will continue increasing regularly. If n represents the number of months, then the total amount after n months can be written as 500 plus 150n rupees. This is a linear expression because the increase is constant every month.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessSuppose the length of a rectangle is 13 cm. Find the area if the breadth is (i) 12 cm, (ii) 10 cm, (iii) 8 cm. Find the linear pattern representing the area of the rectangle.
The area of a rectangle is calculated by multiplying its length and breadth. Here, the length is fixed at 13 cm. When the breadth is 12 cm, the area becomes 13 multiplied by 12, which equals 156 square cm. For breadth 10 cm, the area becomes 130 square cm and for breadth 8 cm, the area becomes 104 sRead more
The area of a rectangle is calculated by multiplying its length and breadth. Here, the length is fixed at 13 cm. When the breadth is 12 cm, the area becomes 13 multiplied by 12, which equals 156 square cm. For breadth 10 cm, the area becomes 130 square cm and for breadth 8 cm, the area becomes 104 square cm. If the breadth is represented by b, then the linear expression for the area of the rectangle is 13b square cm.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessA rally starts with 120 members. Each hour, 9 members drop out of the group. How many members will remain after 1, 2, 3, … hours? Find a linear expression to represent the number of members at the end of the nth hour.
At the beginning, the rally has 120 members. Every hour, 9 members drop out of the group. After 1 hour, the number becomes 111. After 2 hours, it becomes 102 and the decrease continues regularly. If n represents the number of hours, then the number of members remaining after n hours can be written aRead more
At the beginning, the rally has 120 members. Every hour, 9 members drop out of the group. After 1 hour, the number becomes 111. After 2 hours, it becomes 102 and the decrease continues regularly. If n represents the number of hours, then the number of members remaining after n hours can be written as 120 minus 9n. This expression forms a linear pattern because the number of members decreases by the same amount every hour.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See less