The perimeter of a square is found by multiplying the side by 4. Therefore, for sides 1 cm, 1.5 cm, 2 cm, 2.5 cm and 3 cm, the perimeters are 4 cm, 6 cm, 8 cm, 10 cm and 12 cm respectively. We observe that every time the side increases by 0.5 cm, the perimeter increases by 2 cm. This increase is conRead more
The perimeter of a square is found by multiplying the side by 4. Therefore, for sides 1 cm, 1.5 cm, 2 cm, 2.5 cm and 3 cm, the perimeters are 4 cm, 6 cm, 8 cm, 10 cm and 12 cm respectively. We observe that every time the side increases by 0.5 cm, the perimeter increases by 2 cm. This increase is constant, so the pattern formed is called a linear pattern.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
Suppose the smaller number is x. Since the larger number is 10 more than the smaller number, it becomes x plus 10. According to the question, the sum of the two numbers is 64. Therefore, we form the equation x plus x plus 10 equals 64. This simplifies to 2x plus 10 equals 64. Subtracting 10 gives 2xRead more
Suppose the smaller number is x. Since the larger number is 10 more than the smaller number, it becomes x plus 10. According to the question, the sum of the two numbers is 64. Therefore, we form the equation x plus x plus 10 equals 64. This simplifies to 2x plus 10 equals 64. Subtracting 10 gives 2x equals 54 and dividing by 2 gives x equals 27. Hence, the two numbers are 27 and 37.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
The chess club charges a fixed joining fee of 200 rupees. In addition, the player must pay 50 rupees for every match played. If the number of matches played is represented by m, then the total amount paid can be written as 200 plus 50m. This is a linear polynomial because the highest power of the vaRead more
The chess club charges a fixed joining fee of 200 rupees. In addition, the player must pay 50 rupees for every match played. If the number of matches played is represented by m, then the total amount paid can be written as 200 plus 50m. This is a linear polynomial because the highest power of the variable m is 1. The amount paid increases regularly by 50 rupees whenever one more match is played.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
Assume Salil’s present age is x years. Since his mother is three times his age, her present age is 3x years. After 5 years, Salil’s age will become x plus 5 and his mother’s age will become 3x plus 5. According to the question, their total age after 5 years will be 70 years. Therefore, x plus 5 plusRead more
Assume Salil’s present age is x years. Since his mother is three times his age, her present age is 3x years. After 5 years, Salil’s age will become x plus 5 and his mother’s age will become 3x plus 5. According to the question, their total age after 5 years will be 70 years. Therefore, x plus 5 plus 3x plus 5 equals 70. Solving gives x equal to 15. Hence, Salil is 15 years old and his mother is 45 years old.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
Since the ratio of the two integers is 2:5, let the integers be 2x and 5x. The difference between the larger and smaller integer is 63. Therefore, we form the equation 5x minus 2x equals 63. This simplifies to 3x equals 63. Dividing both sides by 3, we get x equal to 21. Substituting the value of x,Read more
Since the ratio of the two integers is 2:5, let the integers be 2x and 5x. The difference between the larger and smaller integer is 63. Therefore, we form the equation 5x minus 2x equals 63. This simplifies to 3x equals 63. Dividing both sides by 3, we get x equal to 21. Substituting the value of x, the two integers become 2 multiplied by 21 and 5 multiplied by 21. Hence, the integers are 42 and 105.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
Find the perimeter of squares with sides 1 cm, 1.5 cm, 2 cm, 2.5 cm and 3 cm. What will happen to the perimeters if the sides increase by 0.5 cm?
The perimeter of a square is found by multiplying the side by 4. Therefore, for sides 1 cm, 1.5 cm, 2 cm, 2.5 cm and 3 cm, the perimeters are 4 cm, 6 cm, 8 cm, 10 cm and 12 cm respectively. We observe that every time the side increases by 0.5 cm, the perimeter increases by 2 cm. This increase is conRead more
The perimeter of a square is found by multiplying the side by 4. Therefore, for sides 1 cm, 1.5 cm, 2 cm, 2.5 cm and 3 cm, the perimeters are 4 cm, 6 cm, 8 cm, 10 cm and 12 cm respectively. We observe that every time the side increases by 0.5 cm, the perimeter increases by 2 cm. This increase is constant, so the pattern formed is called a linear pattern.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessThe sum of two numbers is 64. One of the numbers is 10 more than the other. What are the two numbers?
Suppose the smaller number is x. Since the larger number is 10 more than the smaller number, it becomes x plus 10. According to the question, the sum of the two numbers is 64. Therefore, we form the equation x plus x plus 10 equals 64. This simplifies to 2x plus 10 equals 64. Subtracting 10 gives 2xRead more
Suppose the smaller number is x. Since the larger number is 10 more than the smaller number, it becomes x plus 10. According to the question, the sum of the two numbers is 64. Therefore, we form the equation x plus x plus 10 equals 64. This simplifies to 2x plus 10 equals 64. Subtracting 10 gives 2x equals 54 and dividing by 2 gives x equals 27. Hence, the two numbers are 27 and 37.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessA chess club charges a joining fee of rupees 200 plus rupees 50 for every match played. The following table shows the amount a player will have to pay as the number of matches varies.
The chess club charges a fixed joining fee of 200 rupees. In addition, the player must pay 50 rupees for every match played. If the number of matches played is represented by m, then the total amount paid can be written as 200 plus 50m. This is a linear polynomial because the highest power of the vaRead more
The chess club charges a fixed joining fee of 200 rupees. In addition, the player must pay 50 rupees for every match played. If the number of matches played is represented by m, then the total amount paid can be written as 200 plus 50m. This is a linear polynomial because the highest power of the variable m is 1. The amount paid increases regularly by 50 rupees whenever one more match is played.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessThe present age of Salil’s mother is three times Salil’s present age. After 5 years, their ages will add up to 70 years. Find their present ages.
Assume Salil’s present age is x years. Since his mother is three times his age, her present age is 3x years. After 5 years, Salil’s age will become x plus 5 and his mother’s age will become 3x plus 5. According to the question, their total age after 5 years will be 70 years. Therefore, x plus 5 plusRead more
Assume Salil’s present age is x years. Since his mother is three times his age, her present age is 3x years. After 5 years, Salil’s age will become x plus 5 and his mother’s age will become 3x plus 5. According to the question, their total age after 5 years will be 70 years. Therefore, x plus 5 plus 3x plus 5 equals 70. Solving gives x equal to 15. Hence, Salil is 15 years old and his mother is 45 years old.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessThe difference between two positive integers is 63. The ratio of the two integers is 2:5. Find the two integers.
Since the ratio of the two integers is 2:5, let the integers be 2x and 5x. The difference between the larger and smaller integer is 63. Therefore, we form the equation 5x minus 2x equals 63. This simplifies to 3x equals 63. Dividing both sides by 3, we get x equal to 21. Substituting the value of x,Read more
Since the ratio of the two integers is 2:5, let the integers be 2x and 5x. The difference between the larger and smaller integer is 63. Therefore, we form the equation 5x minus 2x equals 63. This simplifies to 3x equals 63. Dividing both sides by 3, we get x equal to 21. Substituting the value of x, the two integers become 2 multiplied by 21 and 5 multiplied by 21. Hence, the integers are 42 and 105.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See less