1. As shown in Fig. 6.39, a landing mat or soft sand bed yields under the falling athlete, increasing the time duration taken to bring their high downward velocity to zero. From Newton's second law of motion, rate of change of momentum is proportional to force. By extending this stopping time, the acceRead more

    As shown in Fig. 6.39, a landing mat or soft sand bed yields under the falling athlete, increasing the time duration taken to bring their high downward velocity to zero. From Newton’s second law of motion, rate of change of momentum is proportional to force. By extending this stopping time, the acceleration and the resulting impact force decrease substantially, protecting the athlete from severe impact injuries.

     

    For more NCERT Solutions of Class 9 Science Exploration Chapter 6 How Forces Affect Motion Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-6/

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  2. Yes, the boat will move in the backward direction away from the shore as depicted in Fig. 6.38. To propel himself forward onto the land, the sailor must push his feet backward against the boat. According to Newton's third law of motion, the boat simultaneously exerts an equal and opposite reaction fRead more

    Yes, the boat will move in the backward direction away from the shore as depicted in Fig. 6.38. To propel himself forward onto the land, the sailor must push his feet backward against the boat. According to Newton’s third law of motion, the boat simultaneously exerts an equal and opposite reaction force pushing the sailor forward, while the sailor’s backward action force drives the boat backward.

     

    For more NCERT Solutions of Class 9 Science Exploration Chapter 6 How Forces Affect Motion Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-6/

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  3. Option (iii) is correct. In Fig. 6.37, Object B is stationary with zero velocity, while Objects A and D have straight line graphs representing uniform motion at constant velocity with zero acceleration. Object C has a curved position-time graph showing continuously increasing velocity. Since ObjectRead more

    Option (iii) is correct. In Fig. 6.37, Object B is stationary with zero velocity, while Objects A and D have straight line graphs representing uniform motion at constant velocity with zero acceleration. Object C has a curved position-time graph showing continuously increasing velocity. Since Object C possesses non-zero acceleration, a non-zero net external force acts on it according to Newton’s second law.

     

    For more NCERT Solutions of Class 9 Science Exploration Chapter 6 How Forces Affect Motion Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-6/

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  4. Option (iv) is the correct statement. According to Newton's second law of motion, the acceleration produced in a body is directly proportional to the applied net force and takes place in the direction in which that net force acts. Inversely, acceleration is inversely proportional to the mass of theRead more

    Option (iv) is the correct statement. According to Newton’s second law of motion, the acceleration produced in a body is directly proportional to the applied net force and takes place in the direction in which that net force acts. Inversely, acceleration is inversely proportional to the mass of the object, making options (i), (ii) and (iii) incorrect.

     

    For more NCERT Solutions of Class 9 Science Exploration Chapter 6 How Forces Affect Motion Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-6/

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  5. Let the length of the shorter diagonal be d cm. Then the longer diagonal is 2d cm. The formula for the area of a rhombus is: Area = (1/2) x diagonal 1 x diagonal 2 Given Area = 128 cm²: (1/2) x d x 2d = 128 d² = 128 Taking square root on both sides: d = √128 = √(64 x 2) = 8√2 cm. In decimal form, 8√Read more

    Let the length of the shorter diagonal be d cm.

    Then the longer diagonal is 2d cm.

    The formula for the area of a rhombus is:

    Area = (1/2) x diagonal 1 x diagonal 2

    Given Area = 128 cm²:

    (1/2) x d x 2d = 128

    d² = 128

    Taking square root on both sides:

    d = √128 = √(64 x 2) = 8√2 cm.

    In decimal form, 8√2 is approximately 8 x 1.414 = 11.31 cm.

    Therefore, the shorter diagonal is 8√2 cm.

     

    For more NCERT Solutions of Class 9 Ganita Manjari Chapter 6 Measuring Space: Perimeter and Area Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-6/

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