Since Section A has 30 students and Section B has 25 students, their different class sizes require a weighted average rather than a simple mean. Multiplying each section's average by its student count gives total scores of 2160 and 1900, totaling 4060 marks. Dividing this total score by all 55 studeRead more
Since Section A has 30 students and Section B has 25 students, their different class sizes require a weighted average rather than a simple mean. Multiplying each section’s average by its student count gives total scores of 2160 and 1900, totaling 4060 marks. Dividing this total score by all 55 students results in an overall combined test average of approximately 73.82 for both sections.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 10 How Quantities Combine Understanding Data Question Answer (2026-27)
To find the combined purity, we determine the weighted average by multiplying each piece's weight by its varṇa rating. This gives 345 varṇa-units. Dividing this sum by the combined weight of 31 units (9 + 5 + 17) results in an overall purity of approximately 11.13 varṇa. For more NCERT SolutiRead more
To find the combined purity, we determine the weighted average by multiplying each piece’s weight by its varṇa rating. This gives 345 varṇa-units. Dividing this sum by the combined weight of 31 units (9 + 5 + 17) results in an overall purity of approximately 11.13 varṇa.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 10 How Quantities Combine Understanding Data Question Answer (2026-27)
The proposition is true because (m²)(n²) = (mn)². However, its converse statement—"If ab is a perfect square, then a and b are perfect squares"—is false. As a clear counterexample, choose a = 2 and b = 8. Their product ab = 16 is a square, yet neither 2 nor 8 is a square. For more NCERT SolutRead more
The proposition is true because (m²)(n²) = (mn)². However, its converse statement—”If ab is a perfect square, then a and b are perfect squares”—is false. As a clear counterexample, choose a = 2 and b = 8. Their product ab = 16 is a square, yet neither 2 nor 8 is a square.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 9 Propositions and their Converses Question Answer (2026-27)
Because the three months have differing lengths—May has 31 days, June has 30 days and July has 31 days—the daily averages cannot be simply added and divided by 3. Each average must be weighted by the number of days in that month. Summing these products and dividing by the total of 92 days gives theRead more
Because the three months have differing lengths—May has 31 days, June has 30 days and July has 31 days—the daily averages cannot be simply added and divided by 3. Each average must be weighted by the number of days in that month. Summing these products and dividing by the total of 92 days gives the combined average expression: (31 × 3.5 + 30 × 10 + 31 × 8.7) / 92.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 10 How Quantities Combine Understanding Data Question Answer (2026-27)
When three equal quantities of fertilisers are mixed, each contributes equally to the total volume. We calculate the arithmetic mean of the three nitrogen fractions. Simplifying 3/60 to 1/20 and using the common denominator 100, the sum is 10/100 + 18/100 + 5/100 = 33/100. Dividing this sum by 3 givRead more
When three equal quantities of fertilisers are mixed, each contributes equally to the total volume. We calculate the arithmetic mean of the three nitrogen fractions. Simplifying 3/60 to 1/20 and using the common denominator 100, the sum is 10/100 + 18/100 + 5/100 = 33/100. Dividing this sum by 3 gives the final combined fraction of nitrogen in the mixture as 11/100.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 10 How Quantities Combine Understanding Data Question Answer (2026-27)
The average score of students on a test in Section A is 72 and that of students in Section B is 76. What is the combined average of both the sections given that Section A has 30 students and Section B has 25 students?
Since Section A has 30 students and Section B has 25 students, their different class sizes require a weighted average rather than a simple mean. Multiplying each section's average by its student count gives total scores of 2160 and 1900, totaling 4060 marks. Dividing this total score by all 55 studeRead more
Since Section A has 30 students and Section B has 25 students, their different class sizes require a weighted average rather than a simple mean. Multiplying each section’s average by its student count gives total scores of 2160 and 1900, totaling 4060 marks. Dividing this total score by all 55 students results in an overall combined test average of approximately 73.82 for both sections.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 10 How Quantities Combine Understanding Data Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-10/
See less(Śrīdharācārya, Pātīgaṇita, c. 750 CE) In ancient India, Varṇa was the measure of gold purity. A purity of 16 varṇa meant pure gold; in general, a purity of varṇa meant that the gold-alloy was gold and the rest impurities. (Now the term used is karat; 16 Varṇa = 24 karat.) Suppose a goldsmith melts together three pieces of gold: 9 units at 12 varṇa, 5 units at 10 varṇa and 17 units at 11 varṇa. Find the purity in varṇa of the combined gold.
To find the combined purity, we determine the weighted average by multiplying each piece's weight by its varṇa rating. This gives 345 varṇa-units. Dividing this sum by the combined weight of 31 units (9 + 5 + 17) results in an overall purity of approximately 11.13 varṇa. For more NCERT SolutiRead more
To find the combined purity, we determine the weighted average by multiplying each piece’s weight by its varṇa rating. This gives 345 varṇa-units. Dividing this sum by the combined weight of 31 units (9 + 5 + 17) results in an overall purity of approximately 11.13 varṇa.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 10 How Quantities Combine Understanding Data Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-10/
See lessIf a and b are perfect squares, then ab is a perfect square.
The proposition is true because (m²)(n²) = (mn)². However, its converse statement—"If ab is a perfect square, then a and b are perfect squares"—is false. As a clear counterexample, choose a = 2 and b = 8. Their product ab = 16 is a square, yet neither 2 nor 8 is a square. For more NCERT SolutRead more
The proposition is true because (m²)(n²) = (mn)². However, its converse statement—”If ab is a perfect square, then a and b are perfect squares”—is false. As a clear counterexample, choose a = 2 and b = 8. Their product ab = 16 is a square, yet neither 2 nor 8 is a square.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 9 Propositions and their Converses Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-9/
See lessThe average rainfall per day in the months of May, June and July in a certain location are 3.5 mm, 10 mm and 8.7 mm respectively. Write an expression that gives their combined average.
Because the three months have differing lengths—May has 31 days, June has 30 days and July has 31 days—the daily averages cannot be simply added and divided by 3. Each average must be weighted by the number of days in that month. Summing these products and dividing by the total of 92 days gives theRead more
Because the three months have differing lengths—May has 31 days, June has 30 days and July has 31 days—the daily averages cannot be simply added and divided by 3. Each average must be weighted by the number of days in that month. Summing these products and dividing by the total of 92 days gives the combined average expression: (31 × 3.5 + 30 × 10 + 31 × 8.7) / 92.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 10 How Quantities Combine Understanding Data Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-10/
See lessA farmer mixes three equal quantities of fertilisers. The first one contains 1/10 nitrogen, the second contains 9/50 nitrogen and the third contains 3/60 nitrogen. What is the fraction of nitrogen in the mixture?
When three equal quantities of fertilisers are mixed, each contributes equally to the total volume. We calculate the arithmetic mean of the three nitrogen fractions. Simplifying 3/60 to 1/20 and using the common denominator 100, the sum is 10/100 + 18/100 + 5/100 = 33/100. Dividing this sum by 3 givRead more
When three equal quantities of fertilisers are mixed, each contributes equally to the total volume. We calculate the arithmetic mean of the three nitrogen fractions. Simplifying 3/60 to 1/20 and using the common denominator 100, the sum is 10/100 + 18/100 + 5/100 = 33/100. Dividing this sum by 3 gives the final combined fraction of nitrogen in the mixture as 11/100.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 10 How Quantities Combine Understanding Data Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-10/
See less