With a fixed base charge of ₹x and a running charge of ₹y per kilometre, the total fare equals x + (distance × y). For Sahil, travelling 6 km at a total cost of ₹122 leads to x + 6y = 122. For Meena, travelling 8 km with a total fare of ₹160 produces x + 8y = 160. These two relations construct the rRead more
With a fixed base charge of ₹x and a running charge of ₹y per kilometre, the total fare equals x + (distance × y). For Sahil, travelling 6 km at a total cost of ₹122 leads to x + 6y = 122. For Meena, travelling 8 km with a total fare of ₹160 produces x + 8y = 160. These two relations construct the required system.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)
Let ₹x represent the price of one movie ticket and ₹y represent the price of one snack box. For the first day, 2 tickets and 3 snack boxes total ₹850, giving the linear equation 2x + 3y = 850. For the second day, 4 tickets and 1 snack box cost ₹1100, which gives 4x + y = 1100. Together, they form thRead more
Let ₹x represent the price of one movie ticket and ₹y represent the price of one snack box. For the first day, 2 tickets and 3 snack boxes total ₹850, giving the linear equation 2x + 3y = 850. For the second day, 4 tickets and 1 snack box cost ₹1100, which gives 4x + y = 1100. Together, they form the pair of linear equations.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)
The slope guideline requires a ratio of vertical rise to horizontal run equal to 1 / 12. Setting up the proportional relationship gives Rise / Run = 1 / 12. Given that the total rise of the staircase is 18 cm, substituting this into the equation yields 18 / Run = 1 / 12. Cross-multiplying gives RunRead more
The slope guideline requires a ratio of vertical rise to horizontal run equal to 1 / 12. Setting up the proportional relationship gives Rise / Run = 1 / 12. Given that the total rise of the staircase is 18 cm, substituting this into the equation yields 18 / Run = 1 / 12. Cross-multiplying gives Run = 18 × 12 = 216 cm (or 2.16 m).
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)
The line l is a vertical line parallel to the y-axis, located at x = -2. For any two points selected on this line, the x-coordinate does not change, resulting in a horizontal run of zero. Since calculating the slope requires dividing the vertical rise by the horizontal run, division by zero occurs,Read more
The line l is a vertical line parallel to the y-axis, located at x = -2. For any two points selected on this line, the x-coordinate does not change, resulting in a horizontal run of zero. Since calculating the slope requires dividing the vertical rise by the horizontal run, division by zero occurs, which means the slope is completely undefined.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)
The line passes through the origin (0, 0) and the marked grid point (4, -4). As it moves from left to right, it slants downwards, indicating a negative slope. Using the two-point formula, slope = (y₂ - y₁) / (x₂ - x₁) = (-4 - 0) / (4 - 0) = -4 / 4 = -1. Hence, the slope of line l is -1. For mRead more
The line passes through the origin (0, 0) and the marked grid point (4, -4). As it moves from left to right, it slants downwards, indicating a negative slope. Using the two-point formula, slope = (y₂ – y₁) / (x₂ – x₁) = (-4 – 0) / (4 – 0) = -4 / 4 = -1. Hence, the slope of line l is -1.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)
Two friends, Sahil and Meena, travelled by taxi. Let the fixed charge for one taxi trip be ₹x and the additional charge per kilometre be ₹y. Frame a pair of linear equations in x and y to represent the following situation: (i) Sahil travelled 6 km and paid a total fare of ₹122. (ii) Meena travelled 8 km and paid a total fare of ₹160.
With a fixed base charge of ₹x and a running charge of ₹y per kilometre, the total fare equals x + (distance × y). For Sahil, travelling 6 km at a total cost of ₹122 leads to x + 6y = 122. For Meena, travelling 8 km with a total fare of ₹160 produces x + 8y = 160. These two relations construct the rRead more
With a fixed base charge of ₹x and a running charge of ₹y per kilometre, the total fare equals x + (distance × y). For Sahil, travelling 6 km at a total cost of ₹122 leads to x + 6y = 122. For Meena, travelling 8 km with a total fare of ₹160 produces x + 8y = 160. These two relations construct the required system.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-13/
See lessOn two different days a family buys movie tickets and snack boxes. Let the cost of one movie ticket be ₹x and the cost of one snack box be ₹y. Frame a pair of linear equations in x and y to represent the following situations: (i) On the first day, the family buys 2 movie tickets and 3 snack boxes for ₹850. (ii) On the second day, the family buys 4 movie tickets and 1 snack box for ₹1100.
Let ₹x represent the price of one movie ticket and ₹y represent the price of one snack box. For the first day, 2 tickets and 3 snack boxes total ₹850, giving the linear equation 2x + 3y = 850. For the second day, 4 tickets and 1 snack box cost ₹1100, which gives 4x + y = 1100. Together, they form thRead more
Let ₹x represent the price of one movie ticket and ₹y represent the price of one snack box. For the first day, 2 tickets and 3 snack boxes total ₹850, giving the linear equation 2x + 3y = 850. For the second day, 4 tickets and 1 snack box cost ₹1100, which gives 4x + y = 1100. Together, they form the pair of linear equations.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-13/
See lessAn accessibility ramp for wheelchairs is to be made alongside the staircase. The guidelines given for the slope of the ramp is 1 cm vertical rise to 12 cm horizontal length. What should be the horizontal length of the ramp if the total height of the stairs is 18 cm?
The slope guideline requires a ratio of vertical rise to horizontal run equal to 1 / 12. Setting up the proportional relationship gives Rise / Run = 1 / 12. Given that the total rise of the staircase is 18 cm, substituting this into the equation yields 18 / Run = 1 / 12. Cross-multiplying gives RunRead more
The slope guideline requires a ratio of vertical rise to horizontal run equal to 1 / 12. Setting up the proportional relationship gives Rise / Run = 1 / 12. Given that the total rise of the staircase is 18 cm, substituting this into the equation yields 18 / Run = 1 / 12. Cross-multiplying gives Run = 18 × 12 = 216 cm (or 2.16 m).
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-13/
See lessFind the slope of the line l in diagram (iv).
The line l is a vertical line parallel to the y-axis, located at x = -2. For any two points selected on this line, the x-coordinate does not change, resulting in a horizontal run of zero. Since calculating the slope requires dividing the vertical rise by the horizontal run, division by zero occurs,Read more
The line l is a vertical line parallel to the y-axis, located at x = -2. For any two points selected on this line, the x-coordinate does not change, resulting in a horizontal run of zero. Since calculating the slope requires dividing the vertical rise by the horizontal run, division by zero occurs, which means the slope is completely undefined.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-13/
See lessFind the slope of the line l in diagram (ii).
The line passes through the origin (0, 0) and the marked grid point (4, -4). As it moves from left to right, it slants downwards, indicating a negative slope. Using the two-point formula, slope = (y₂ - y₁) / (x₂ - x₁) = (-4 - 0) / (4 - 0) = -4 / 4 = -1. Hence, the slope of line l is -1. For mRead more
The line passes through the origin (0, 0) and the marked grid point (4, -4). As it moves from left to right, it slants downwards, indicating a negative slope. Using the two-point formula, slope = (y₂ – y₁) / (x₂ – x₁) = (-4 – 0) / (4 – 0) = -4 / 4 = -1. Hence, the slope of line l is -1.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-13/
See less