For large data sets, a bar graph is the most suitable option. It visually represents data using rectangular bars, making it easy to compare different categories and observe trends. Click here for more: https://www.tiwariacademy.com/ncert-solutions/class-6/maths/
For large data sets, a bar graph is the most suitable option. It visually represents data using rectangular bars, making it easy to compare different categories and observe trends.
The primary purpose of collecting data is to convey information. Data collection helps in analyzing trends, making informed decisions, and understanding patterns effectively. Click here for more: https://www.tiwariacademy.com/ncert-solutions/class-6/maths/
The primary purpose of collecting data is to convey information. Data collection helps in analyzing trends, making informed decisions, and understanding patterns effectively.
A bar graph represents data using bars of uniform width. The length or height of each bar corresponds to the value it represents, making it easy to compare different categories. Click here for more: https://www.tiwariacademy.com/ncert-solutions/class-6/maths/
A bar graph represents data using bars of uniform width. The length or height of each bar corresponds to the value it represents, making it easy to compare different categories.
To solve this, let's break it down step by step. We are given the equation |A| = |kA|, where A is a square matrix of order 2. That means it is a 2x2 matrix. We are trying to find the sum of all possible values of k. Key Concepts: 1. Determinant of a matrix: For a square matrix A, the determinant isRead more
To solve this, let’s break it down step by step.
We are given the equation |A| = |kA|, where A is a square matrix of order 2. That means it is a 2×2 matrix. We are trying to find the sum of all possible values of k.
Key Concepts:
1. Determinant of a matrix: For a square matrix A, the determinant is denoted as |A|.
2. Scalar multiplication and determinant:** Let A be any square matrix of order n and k be any scalar, then |kA| = k^n |A|.
Here:
– A is of the order of 2. Thus, n = 2.
– The determinant |kA| is defined as:
|kA| = k² |A|
Now, from |A|=|kA| we have:
|A| = k² |A|
If |A| ≠ 0, then divide both sides by |A|. Then
1 = k²
Hence, k = ±1
If |A| = 0, the equation holds true for all value of k.
Therefore, sum of all the possible values of k
= 1 + (-1)
= 0
Hence, sum of all possible values of k is zero.
We are given y = tan⁻¹(e²ˣ) and need to find dy/dx. Step 1: Differentiate both sides with respect to x We differentiate the equation y = tan⁻¹(e²ˣ) using the chain rule. The derivative of tan⁻¹(u) with respect to u is 1/(1 + u²), so: dy/dx = 1 / (1 + (e²ˣ)²) * d/dx(e²ˣ) Step 2: Differentiate e²ˣ TheRead more
We are given y = tan⁻¹(e²ˣ) and need to find dy/dx.
Step 1: Differentiate both sides with respect to x
We differentiate the equation y = tan⁻¹(e²ˣ) using the chain rule. The derivative of tan⁻¹(u) with respect to u is 1/(1 + u²), so:
dy/dx = 1 / (1 + (e²ˣ)²) * d/dx(e²ˣ)
Step 2: Differentiate e²ˣ
The derivative of e²ˣ with respect to x is:
d/dx(e²ˣ) = 2e²ˣ
Step 3: Substitute into the derivative
Substitute this back into the expression for dy/dx:
dy/dx = 1 / (1 + e⁴ˣ) * 2e²ˣ
dy/dx = 2e²ˣ / (1 + e⁴ˣ)
What type of graph is suitable for large data sets?
For large data sets, a bar graph is the most suitable option. It visually represents data using rectangular bars, making it easy to compare different categories and observe trends. Click here for more: https://www.tiwariacademy.com/ncert-solutions/class-6/maths/
For large data sets, a bar graph is the most suitable option. It visually represents data using rectangular bars, making it easy to compare different categories and observe trends.
Click here for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-6/maths/
What is the primary purpose of collecting data?
The primary purpose of collecting data is to convey information. Data collection helps in analyzing trends, making informed decisions, and understanding patterns effectively. Click here for more: https://www.tiwariacademy.com/ncert-solutions/class-6/maths/
The primary purpose of collecting data is to convey information. Data collection helps in analyzing trends, making informed decisions, and understanding patterns effectively.
Click here for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-6/maths/
What does a bar graph use to represent data?
A bar graph represents data using bars of uniform width. The length or height of each bar corresponds to the value it represents, making it easy to compare different categories. Click here for more: https://www.tiwariacademy.com/ncert-solutions/class-6/maths/
A bar graph represents data using bars of uniform width. The length or height of each bar corresponds to the value it represents, making it easy to compare different categories.
Click here for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-6/maths/
|A| = |kA|, where A is a square matrix of order 2, then sum of all possible values of k is
To solve this, let's break it down step by step. We are given the equation |A| = |kA|, where A is a square matrix of order 2. That means it is a 2x2 matrix. We are trying to find the sum of all possible values of k. Key Concepts: 1. Determinant of a matrix: For a square matrix A, the determinant isRead more
To solve this, let’s break it down step by step.
We are given the equation |A| = |kA|, where A is a square matrix of order 2. That means it is a 2×2 matrix. We are trying to find the sum of all possible values of k.
Key Concepts:
1. Determinant of a matrix: For a square matrix A, the determinant is denoted as |A|.
2. Scalar multiplication and determinant:** Let A be any square matrix of order n and k be any scalar, then |kA| = k^n |A|.
Here:
– A is of the order of 2. Thus, n = 2.
– The determinant |kA| is defined as:
|kA| = k² |A|
Now, from |A|=|kA| we have:
|A| = k² |A|
If |A| ≠ 0, then divide both sides by |A|. Then
1 = k²
Hence, k = ±1
If |A| = 0, the equation holds true for all value of k.
Therefore, sum of all the possible values of k
= 1 + (-1)
= 0
Hence, sum of all possible values of k is zero.
Click here for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/maths/#chapter-4
If y = tan⁻¹ (e²ˣ), then dy/dx is equal to
We are given y = tan⁻¹(e²ˣ) and need to find dy/dx. Step 1: Differentiate both sides with respect to x We differentiate the equation y = tan⁻¹(e²ˣ) using the chain rule. The derivative of tan⁻¹(u) with respect to u is 1/(1 + u²), so: dy/dx = 1 / (1 + (e²ˣ)²) * d/dx(e²ˣ) Step 2: Differentiate e²ˣ TheRead more
We are given y = tan⁻¹(e²ˣ) and need to find dy/dx.
Step 1: Differentiate both sides with respect to x
We differentiate the equation y = tan⁻¹(e²ˣ) using the chain rule. The derivative of tan⁻¹(u) with respect to u is 1/(1 + u²), so:
dy/dx = 1 / (1 + (e²ˣ)²) * d/dx(e²ˣ)
Step 2: Differentiate e²ˣ
The derivative of e²ˣ with respect to x is:
d/dx(e²ˣ) = 2e²ˣ
Step 3: Substitute into the derivative
Substitute this back into the expression for dy/dx:
dy/dx = 1 / (1 + e⁴ˣ) * 2e²ˣ
dy/dx = 2e²ˣ / (1 + e⁴ˣ)
Click here for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/maths/#chapter-4