The correct answer is "Multiply by 3 and add 1". In the Collatz sequence, if the number is odd, it is multiplied by 3 and then 1 is added to the result. This operation continues until the number eventually reaches 1. The sequence follows the pattern: if odd, multiply by 3 and add 1; if even, divideRead more
The correct answer is “Multiply by 3 and add 1”. In the Collatz sequence, if the number is odd, it is multiplied by 3 and then 1 is added to the result. This operation continues until the number eventually reaches 1. The sequence follows the pattern: if odd, multiply by 3 and add 1; if even, divide by 2.
A composite number is one that has more than two factors. It can be divided by at least one number other than 1 and itself. For example 4 is a composite number because its factors are 1 2 and 4. Unlike prime numbers which only have two factors composite numbers have additional factors. Click here foRead more
A composite number is one that has more than two factors. It can be divided by at least one number other than 1 and itself. For example 4 is a composite number because its factors are 1 2 and 4. Unlike prime numbers which only have two factors composite numbers have additional factors.
When five fair coins are tossed simultaneously the probability of getting at least one head is found using the complement rule 1. Total possible outcomes when tossing 5 coins = 2⁵ = 32 2. Only unfavorable outcome is getting all tails which happens in one way: TTTTT 3. Probability of getting all tailRead more
When five fair coins are tossed simultaneously the probability of getting at least one head is found using the complement rule
1. Total possible outcomes when tossing 5 coins = 2⁵ = 32
2. Only unfavorable outcome is getting all tails which happens in one way: TTTTT
3. Probability of getting all tails = 1/32
4. Probability of getting at least one head = 1 – P(all tails) = 1 – 1/32 = 31/32
Given: P(A) = 4/5 P(A ∩ B) = 7/10 Using the conditional probability formula: P(B|A) = P(A ∩ B) / P(A) Substituting the values: P(B|A) = (7/10) ÷ (4/5) = (7/10) × (5/4) = 35/40 = 7/8 So the correct answer is 7/8 Click here for more: https://www.tiwariacademy.com/ncert-solutions/class-12/maths/#chapteRead more
Given:
P(A) = 4/5
P(A ∩ B) = 7/10
Using the conditional probability formula:
P(B|A) = P(A ∩ B) / P(A)
Given: P(A hits) = 0.4 P(B hits) = 0.3 P(C hits) = 0.2 To find the probability of exactly two hits, we consider the cases where exactly two of A, B, and C hit the target: 1. A and B hit, C misses: P(A ∩ B ∩ C') = (0.4) × (0.3) × (1 - 0.2) = 0.4 × 0.3 × 0.8 = 0.096 2. A and C hit, B misses: P(A ∩ B'Read more
In the Collatz sequence, what operation is applied if the number is odd?
The correct answer is "Multiply by 3 and add 1". In the Collatz sequence, if the number is odd, it is multiplied by 3 and then 1 is added to the result. This operation continues until the number eventually reaches 1. The sequence follows the pattern: if odd, multiply by 3 and add 1; if even, divideRead more
The correct answer is “Multiply by 3 and add 1”. In the Collatz sequence, if the number is odd, it is multiplied by 3 and then 1 is added to the result. This operation continues until the number eventually reaches 1. The sequence follows the pattern: if odd, multiply by 3 and add 1; if even, divide by 2.
Click here for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-3/
A composite number is one that has:
A composite number is one that has more than two factors. It can be divided by at least one number other than 1 and itself. For example 4 is a composite number because its factors are 1 2 and 4. Unlike prime numbers which only have two factors composite numbers have additional factors. Click here foRead more
A composite number is one that has more than two factors. It can be divided by at least one number other than 1 and itself. For example 4 is a composite number because its factors are 1 2 and 4. Unlike prime numbers which only have two factors composite numbers have additional factors.
Click here for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/
Five fair coins are tossed simultaneously. The probability of the events that at least one head comes up is
When five fair coins are tossed simultaneously the probability of getting at least one head is found using the complement rule 1. Total possible outcomes when tossing 5 coins = 2⁵ = 32 2. Only unfavorable outcome is getting all tails which happens in one way: TTTTT 3. Probability of getting all tailRead more
When five fair coins are tossed simultaneously the probability of getting at least one head is found using the complement rule
1. Total possible outcomes when tossing 5 coins = 2⁵ = 32
2. Only unfavorable outcome is getting all tails which happens in one way: TTTTT
3. Probability of getting all tails = 1/32
4. Probability of getting at least one head = 1 – P(all tails) = 1 – 1/32 = 31/32
Click here for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/maths/#chapter-13
If for any two events A and B, P(A) = 4/5 and P(A ∩ B) = 7/10, then P(B/A) is equal to
Given: P(A) = 4/5 P(A ∩ B) = 7/10 Using the conditional probability formula: P(B|A) = P(A ∩ B) / P(A) Substituting the values: P(B|A) = (7/10) ÷ (4/5) = (7/10) × (5/4) = 35/40 = 7/8 So the correct answer is 7/8 Click here for more: https://www.tiwariacademy.com/ncert-solutions/class-12/maths/#chapteRead more
Given:
P(A) = 4/5
P(A ∩ B) = 7/10
Using the conditional probability formula:
P(B|A) = P(A ∩ B) / P(A)
Substituting the values:
P(B|A) = (7/10) ÷ (4/5)
= (7/10) × (5/4) = 35/40 = 7/8
So the correct answer is 7/8
Click here for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/maths/#chapter-13
Three persons A, B and C, fire at a target in turn, starting with A. Their probability of hitting the target are 0.4, 0.3 and 0.2 respectively. The probability of two hits is
Given: P(A hits) = 0.4 P(B hits) = 0.3 P(C hits) = 0.2 To find the probability of exactly two hits, we consider the cases where exactly two of A, B, and C hit the target: 1. A and B hit, C misses: P(A ∩ B ∩ C') = (0.4) × (0.3) × (1 - 0.2) = 0.4 × 0.3 × 0.8 = 0.096 2. A and C hit, B misses: P(A ∩ B'Read more
Given:
P(A hits) = 0.4
P(B hits) = 0.3
P(C hits) = 0.2
To find the probability of exactly two hits, we consider the cases where exactly two of A, B, and C hit the target:
1. A and B hit, C misses:
P(A ∩ B ∩ C’) = (0.4) × (0.3) × (1 – 0.2)
= 0.4 × 0.3 × 0.8 = 0.096
2. A and C hit, B misses:
P(A ∩ B’ ∩ C) = (0.4) × (1 – 0.3) × (0.2)
= 0.4 × 0.7 × 0.2 = 0.056
3. B and C hit, A misses:
P(A’ ∩ B ∩ C) = (1 – 0.4) × (0.3) × (0.2)
= 0.6 × 0.3 × 0.2 = 0.036
Total probability of exactly two hits:
P = 0.096 + 0.056 + 0.036 = 0.188
Click here for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/maths/#chapter-13