1. The correct answer is "Multiply by 3 and add 1". In the Collatz sequence, if the number is odd, it is multiplied by 3 and then 1 is added to the result. This operation continues until the number eventually reaches 1. The sequence follows the pattern: if odd, multiply by 3 and add 1; if even, divideRead more

    The correct answer is “Multiply by 3 and add 1”. In the Collatz sequence, if the number is odd, it is multiplied by 3 and then 1 is added to the result. This operation continues until the number eventually reaches 1. The sequence follows the pattern: if odd, multiply by 3 and add 1; if even, divide by 2.

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  2. A composite number is one that has more than two factors. It can be divided by at least one number other than 1 and itself. For example 4 is a composite number because its factors are 1 2 and 4. Unlike prime numbers which only have two factors composite numbers have additional factors. Click here foRead more

    A composite number is one that has more than two factors. It can be divided by at least one number other than 1 and itself. For example 4 is a composite number because its factors are 1 2 and 4. Unlike prime numbers which only have two factors composite numbers have additional factors.

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  3. When five fair coins are tossed simultaneously the probability of getting at least one head is found using the complement rule 1. Total possible outcomes when tossing 5 coins = 2⁵ = 32 2. Only unfavorable outcome is getting all tails which happens in one way: TTTTT 3. Probability of getting all tailRead more

    When five fair coins are tossed simultaneously the probability of getting at least one head is found using the complement rule

    1. Total possible outcomes when tossing 5 coins = 2⁵ = 32
    2. Only unfavorable outcome is getting all tails which happens in one way: TTTTT
    3. Probability of getting all tails = 1/32
    4. Probability of getting at least one head = 1 – P(all tails) = 1 – 1/32 = 31/32

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  4. Given: P(A) = 4/5 P(A ∩ B) = 7/10 Using the conditional probability formula: P(B|A) = P(A ∩ B) / P(A) Substituting the values: P(B|A) = (7/10) ÷ (4/5) = (7/10) × (5/4) = 35/40 = 7/8 So the correct answer is 7/8 Click here for more: https://www.tiwariacademy.com/ncert-solutions/class-12/maths/#chapteRead more

    Given:
    P(A) = 4/5
    P(A ∩ B) = 7/10

    Using the conditional probability formula:
    P(B|A) = P(A ∩ B) / P(A)

    Substituting the values:
    P(B|A) = (7/10) ÷ (4/5)

    = (7/10) × (5/4) = 35/40 = 7/8

    So the correct answer is 7/8

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  5. Given: P(A hits) = 0.4 P(B hits) = 0.3 P(C hits) = 0.2 To find the probability of exactly two hits, we consider the cases where exactly two of A, B, and C hit the target: 1. A and B hit, C misses: P(A ∩ B ∩ C') = (0.4) × (0.3) × (1 - 0.2) = 0.4 × 0.3 × 0.8 = 0.096 2. A and C hit, B misses: P(A ∩ B'Read more

    Given:
    P(A hits) = 0.4
    P(B hits) = 0.3
    P(C hits) = 0.2

    To find the probability of exactly two hits, we consider the cases where exactly two of A, B, and C hit the target:

    1. A and B hit, C misses:
    P(A ∩ B ∩ C’) = (0.4) × (0.3) × (1 – 0.2)
    = 0.4 × 0.3 × 0.8 = 0.096

    2. A and C hit, B misses:
    P(A ∩ B’ ∩ C) = (0.4) × (1 – 0.3) × (0.2)
    = 0.4 × 0.7 × 0.2 = 0.056

    3. B and C hit, A misses:
    P(A’ ∩ B ∩ C) = (1 – 0.4) × (0.3) × (0.2)
    = 0.6 × 0.3 × 0.2 = 0.036

    Total probability of exactly two hits:
    P = 0.096 + 0.056 + 0.036 = 0.188

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