Given the mass of the sphere M = 100 kg, the mass of the particle m = 10 g or 10⁻² kg, and the radius R = 10 cm or 0.01 m, the initial potential energy (P.E.) of the two bodies is calculated based on their gravitational interaction. When the particle is moved far away from the sphere, the gravitatioRead more
Given the mass of the sphere M = 100 kg, the mass of the particle m = 10 g or 10⁻² kg, and the radius R = 10 cm or 0.01 m, the initial potential energy (P.E.) of the two bodies is calculated based on their gravitational interaction. When the particle is moved far away from the sphere, the gravitational potential energy of the system becomes zero. The work done in moving the particle from its initial position to an infinite distance is the difference between the final and initial potential energies, resulting in a positive value.
In the given scenario, the initial potential energy of the system is determined by the gravitational interaction between the two masses. When the particle is moved infinitely far away, the potential energy becomes zero. To move the particle from its initial position to infinity, the kinetic energy rRead more
In the given scenario, the initial potential energy of the system is determined by the gravitational interaction between the two masses. When the particle is moved infinitely far away, the potential energy becomes zero. To move the particle from its initial position to infinity, the kinetic energy required is equivalent to the change in potential energy. This kinetic energy can be understood as the work needed to overcome the gravitational attraction between the two bodies. The amount of kinetic energy required is proportional to the gravitational acceleration, the mass of the particle, and the radius of the sphere.
The gravitational potential energy (P.E.) of a mass m in an orbit of radius R is negative and proportional to the inverse of the radius. When the radius is doubled, the potential energy becomes less negative, reflecting the decrease in gravitational attraction. Similarly, when the radius is tripled,Read more
The gravitational potential energy (P.E.) of a mass m in an orbit of radius R is negative and proportional to the inverse of the radius. When the radius is doubled, the potential energy becomes less negative, reflecting the decrease in gravitational attraction. Similarly, when the radius is tripled, the potential energy further decreases. The change in gravitational potential energy between two orbits, such as from a radius of 2R to 3R, can be found by calculating the difference between the two potential energies. This difference represents the work done by the gravitational force in moving the object between these orbits.
If g is the acceleration due to gravity on the Earth's surface, the gain in potential energy of an object of mass m, when raised from the surface of the Earth to a height equal to the Earth's radius R, can be calculated by considering the change in gravitational potential energy. The potential energRead more
If g is the acceleration due to gravity on the Earth’s surface, the gain in potential energy of an object of mass m, when raised from the surface of the Earth to a height equal to the Earth’s radius R, can be calculated by considering the change in gravitational potential energy. The potential energy at the Earth’s surface and at the height R are compared, and the difference gives the gain in potential energy. This results in a gain of half the product of the object’s mass, gravitational acceleration, and the radius of the Earth.
If the gravitational force acting on a satellite were to suddenly become zero, the satellite would no longer experience the centripetal force required to maintain its curved orbital path. As a result, it would move in a straight line tangent to its original orbit, maintaining the velocity it had atRead more
If the gravitational force acting on a satellite were to suddenly become zero, the satellite would no longer experience the centripetal force required to maintain its curved orbital path. As a result, it would move in a straight line tangent to its original orbit, maintaining the velocity it had at the moment the gravitational force ceased.
This is due to the principle of inertia, where an object in motion continues in its state of motion unless acted upon by an external force. Therefore, without gravity to keep it in orbit, the satellite would follow a straight-line trajectory in the direction of its velocity.
A particle of mass 10g is kept on the surface of a uniform sphere of mass 100 kg and radius 10 cm. Find the work to be done against the gravitational force between them to take the particle far away from the sphere. You may take G = 6.67 x 10⁻¹¹ Nm²kg ⁻²
Given the mass of the sphere M = 100 kg, the mass of the particle m = 10 g or 10⁻² kg, and the radius R = 10 cm or 0.01 m, the initial potential energy (P.E.) of the two bodies is calculated based on their gravitational interaction. When the particle is moved far away from the sphere, the gravitatioRead more
Given the mass of the sphere M = 100 kg, the mass of the particle m = 10 g or 10⁻² kg, and the radius R = 10 cm or 0.01 m, the initial potential energy (P.E.) of the two bodies is calculated based on their gravitational interaction. When the particle is moved far away from the sphere, the gravitational potential energy of the system becomes zero. The work done in moving the particle from its initial position to an infinite distance is the difference between the final and initial potential energies, resulting in a positive value.
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See lessThe kinetic energy needed to project a body of mass m from the earth’s surface (radius R) to infinity is
In the given scenario, the initial potential energy of the system is determined by the gravitational interaction between the two masses. When the particle is moved infinitely far away, the potential energy becomes zero. To move the particle from its initial position to infinity, the kinetic energy rRead more
In the given scenario, the initial potential energy of the system is determined by the gravitational interaction between the two masses. When the particle is moved infinitely far away, the potential energy becomes zero. To move the particle from its initial position to infinity, the kinetic energy required is equivalent to the change in potential energy. This kinetic energy can be understood as the work needed to overcome the gravitational attraction between the two bodies. The amount of kinetic energy required is proportional to the gravitational acceleration, the mass of the particle, and the radius of the sphere.
Check out for more :- https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-7/
See lessEnergy required to move a body of mass m from an orbit of radius 2 R to 3 R is
The gravitational potential energy (P.E.) of a mass m in an orbit of radius R is negative and proportional to the inverse of the radius. When the radius is doubled, the potential energy becomes less negative, reflecting the decrease in gravitational attraction. Similarly, when the radius is tripled,Read more
The gravitational potential energy (P.E.) of a mass m in an orbit of radius R is negative and proportional to the inverse of the radius. When the radius is doubled, the potential energy becomes less negative, reflecting the decrease in gravitational attraction. Similarly, when the radius is tripled, the potential energy further decreases. The change in gravitational potential energy between two orbits, such as from a radius of 2R to 3R, can be found by calculating the difference between the two potential energies. This difference represents the work done by the gravitational force in moving the object between these orbits.
Check out for more:- https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-7/
See lessIf g is the acceleration due to gravity on the earth’s surface, the gain in the potential energy of an object of mass m raised from the surface of the earth to a height equal to the radius R of the earth, is
If g is the acceleration due to gravity on the Earth's surface, the gain in potential energy of an object of mass m, when raised from the surface of the Earth to a height equal to the Earth's radius R, can be calculated by considering the change in gravitational potential energy. The potential energRead more
If g is the acceleration due to gravity on the Earth’s surface, the gain in potential energy of an object of mass m, when raised from the surface of the Earth to a height equal to the Earth’s radius R, can be calculated by considering the change in gravitational potential energy. The potential energy at the Earth’s surface and at the height R are compared, and the difference gives the gain in potential energy. This results in a gain of half the product of the object’s mass, gravitational acceleration, and the radius of the Earth.
Check out for more :- https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-7/
See lessIf suddenly the gravitational force of attraction between earth and a satellite revolving around it become zero, then the satellite will
If the gravitational force acting on a satellite were to suddenly become zero, the satellite would no longer experience the centripetal force required to maintain its curved orbital path. As a result, it would move in a straight line tangent to its original orbit, maintaining the velocity it had atRead more
If the gravitational force acting on a satellite were to suddenly become zero, the satellite would no longer experience the centripetal force required to maintain its curved orbital path. As a result, it would move in a straight line tangent to its original orbit, maintaining the velocity it had at the moment the gravitational force ceased.
This is due to the principle of inertia, where an object in motion continues in its state of motion unless acted upon by an external force. Therefore, without gravity to keep it in orbit, the satellite would follow a straight-line trajectory in the direction of its velocity.
Check out for more : – https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-7/
See less