The frequency table of the two-wheelers, three-wheelers and four-wheelers going past during 2:30 pm to 3:30 pm in front of our school is given below: Vehicle Two-wheelers Three-wheelers Four-wheelers Total Frequency 12 7 9 28 Total number of vehicles = 28 and number of two- wheelers = 12 Therefore,Read more
The frequency table of the two-wheelers, three-wheelers and four-wheelers going past during 2:30 pm to 3:30 pm in front of our school is given below:
Vehicle Two-wheelers Three-wheelers Four-wheelers Total
Frequency 12 7 9 28
Total number of vehicles = 28 and number of two- wheelers = 12
Therefore,
P(two – wheelers ) = 12/28 = 3/7
Hence, the probability of two- wheelers is 3/7.
Given 3- digit numbers = 100, 101, 102 ... 999 and total number of 3-digit numbers = 999 - 99 = 900 Numbers divisible by 3 = 102, 105, 108 ... 999. So, the number of numbers divisible by 3 = 300 Therefore, P(number divisible by 3) = 300/900 = 1/3 Hence, the probability that the number written by herRead more
Given 3- digit numbers = 100, 101, 102 … 999 and total number of 3-digit numbers = 999 – 99 = 900
Numbers divisible by 3 = 102, 105, 108 … 999. So, the number of numbers divisible by 3 = 300
Therefore,
P(number divisible by 3) = 300/900 = 1/3
Hence, the probability that the number written by her/him is divisible by 3 is 1/3.
Arranging the data in ascending order: 4.97, 4.98, 5.00. 5.03, 5.04, 5.05, 5.06, 5.07, 5.08, Total number of flour bang = 11 and number of bags containing more than 5 kg of flour = 7 Therefore, P(A bag contains more than 5 kg of flour) = 7/11 Hence, the probality that any of these bags chosen at ranRead more
Arranging the data in ascending order: 4.97, 4.98, 5.00. 5.03, 5.04, 5.05, 5.06, 5.07, 5.08,
Total number of flour bang = 11 and number of bags containing more than 5 kg of flour = 7
Therefore,
P(A bag contains more than 5 kg of flour) = 7/11
Hence, the probality that any of these bags chosen at random contains more than 5 kg of flour is 7/11.
Activity : Note the frequency of two-wheelers, three-wheelers and four-wheelers going past during a time interval, in front of your school gate. Find the probability that any one vehicle out of the total vehicles you have observed is a two-wheeler.
The frequency table of the two-wheelers, three-wheelers and four-wheelers going past during 2:30 pm to 3:30 pm in front of our school is given below: Vehicle Two-wheelers Three-wheelers Four-wheelers Total Frequency 12 7 9 28 Total number of vehicles = 28 and number of two- wheelers = 12 Therefore,Read more
The frequency table of the two-wheelers, three-wheelers and four-wheelers going past during 2:30 pm to 3:30 pm in front of our school is given below:
See lessVehicle Two-wheelers Three-wheelers Four-wheelers Total
Frequency 12 7 9 28
Total number of vehicles = 28 and number of two- wheelers = 12
Therefore,
P(two – wheelers ) = 12/28 = 3/7
Hence, the probability of two- wheelers is 3/7.
Activity : Ask all the students in your class to write a 3-digit number. Choose any student from the room at random. What is the probability that the number written by her/him is divisible by 3? Remember that a number is divisible by 3, if the sum of its digits is divisible by 3.
Given 3- digit numbers = 100, 101, 102 ... 999 and total number of 3-digit numbers = 999 - 99 = 900 Numbers divisible by 3 = 102, 105, 108 ... 999. So, the number of numbers divisible by 3 = 300 Therefore, P(number divisible by 3) = 300/900 = 1/3 Hence, the probability that the number written by herRead more
Given 3- digit numbers = 100, 101, 102 … 999 and total number of 3-digit numbers = 999 – 99 = 900
See lessNumbers divisible by 3 = 102, 105, 108 … 999. So, the number of numbers divisible by 3 = 300
Therefore,
P(number divisible by 3) = 300/900 = 1/3
Hence, the probability that the number written by her/him is divisible by 3 is 1/3.
Eleven bags of wheat flour, each marked 5 kg, actually contained the following weights of flour (in kg): 4.97 5.05 5.08 5.03 5.00 5.06 5.08 4.98 5.04 5.07 5.00 Find the probability that any of these bags chosen at random contains more than 5 kg of flour.
Arranging the data in ascending order: 4.97, 4.98, 5.00. 5.03, 5.04, 5.05, 5.06, 5.07, 5.08, Total number of flour bang = 11 and number of bags containing more than 5 kg of flour = 7 Therefore, P(A bag contains more than 5 kg of flour) = 7/11 Hence, the probality that any of these bags chosen at ranRead more
Arranging the data in ascending order: 4.97, 4.98, 5.00. 5.03, 5.04, 5.05, 5.06, 5.07, 5.08,
See lessTotal number of flour bang = 11 and number of bags containing more than 5 kg of flour = 7
Therefore,
P(A bag contains more than 5 kg of flour) = 7/11
Hence, the probality that any of these bags chosen at random contains more than 5 kg of flour is 7/11.