The first equation of motion is v = u + at, where u is the initial velocity a is the acceleration, and t is the time. This equation applies to objects moving under uniform acceleration. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
The first equation of motion is v = u + at, where u is the initial velocity a is the acceleration, and t is the time. This equation applies to objects moving under uniform acceleration.
The slope of a velocity-time graph represents acceleration. Mathematically, acceleration is the rate of change of velocity, which corresponds to the slope of the graph. This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according toRead more
The slope of a velocity-time graph represents acceleration. Mathematically, acceleration is the rate of change of velocity, which corresponds to the slope of the graph.
This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.
Displacement is calculated using s=vt, where v = 10m/s and t = 3s: s = 10 × 3 = 30m. This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-Read more
Displacement is calculated using s=vt, where v = 10m/s and t = 3s: s = 10 × 3 = 30m. This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.
Displacement is a vector quantity because it has both magnitude and direction, unlike speed, distance, or time, which are scalar quantities. This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding. For moreRead more
Displacement is a vector quantity because it has both magnitude and direction, unlike speed, distance, or time, which are scalar quantities. This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.
Using a = v-u/t, where u = 40 m/s, v = 0m/s and t = 10s: a = 0 - 40/10 = -4m/s ² This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-soluRead more
Using a = v-u/t, where u = 40 m/s, v = 0m/s and t = 10s: a = 0 – 40/10 = -4m/s ²
This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.
What is the equation for the final velocity of an object moving with uniform acceleration?
The first equation of motion is v = u + at, where u is the initial velocity a is the acceleration, and t is the time. This equation applies to objects moving under uniform acceleration. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
The first equation of motion is v = u + at, where u is the initial velocity a is the acceleration, and t is the time. This equation applies to objects moving under uniform acceleration.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
What represent in the slope of a velocity-time graph?
The slope of a velocity-time graph represents acceleration. Mathematically, acceleration is the rate of change of velocity, which corresponds to the slope of the graph. This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according toRead more
The slope of a velocity-time graph represents acceleration. Mathematically, acceleration is the rate of change of velocity, which corresponds to the slope of the graph.
This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
What will be the displacement of a body moving with uniform velocity after 3 s if its velocity is 10 m/s?
Displacement is calculated using s=vt, where v = 10m/s and t = 3s: s = 10 × 3 = 30m. This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-Read more
Displacement is calculated using s=vt, where v = 10m/s and t = 3s: s = 10 × 3 = 30m. This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
Which of the following quantities is a vector?
Displacement is a vector quantity because it has both magnitude and direction, unlike speed, distance, or time, which are scalar quantities. This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding. For moreRead more
Displacement is a vector quantity because it has both magnitude and direction, unlike speed, distance, or time, which are scalar quantities. This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
A train moving with a velocity of 40m/s is brought to rest in 10 s. What is its acceleration?
Using a = v-u/t, where u = 40 m/s, v = 0m/s and t = 10s: a = 0 - 40/10 = -4m/s ² This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-soluRead more
Using a = v-u/t, where u = 40 m/s, v = 0m/s and t = 10s: a = 0 – 40/10 = -4m/s ²
This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/