Using s = 1/2gt² , where s= 80m and g = 10 m/s ²: 80 = 1/2(10)t² 80 = 5t² t² = 16 t = 4s This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncRead more
Using s = 1/2gt² , where s= 80m and g = 10 m/s ²:
80 = 1/2(10)t²
80 = 5t²
t² = 16
t = 4s
This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.
Acceleration is defined as the rate of change of velocity with respect to time. It can be positive, negative, or zero depending on whether the velocity is increasing, decreasing, or constant. This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. GiRead more
Acceleration is defined as the rate of change of velocity with respect to time. It can be positive, negative, or zero depending on whether the velocity is increasing, decreasing, or constant.
This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.
Displacement is given by s = vt, where v = 10m/s and t = 5s: s= 10 × 5 = 50m. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
Displacement is given by s = vt, where v = 10m/s and t = 5s:
s= 10 × 5 = 50m.
The area under the velocity-time graph represents the displacement of an object. It is calculated by integrating the velocity with respect to time or finding the area geometrically in cases of simple shapes. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/physics/cRead more
The area under the velocity-time graph represents the displacement of an object. It is calculated by integrating the velocity with respect to time or finding the area geometrically in cases of simple shapes.
Using s = ut +1/2at², where u = 0, a = 4m/s² and t = 5s: s = 0 +1/2(4)(5²) = 1/2(4)(25) = 50 × 2 = 100m. This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding. For more please visit here: https://www.tiwaRead more
Using s = ut +1/2at², where u = 0, a = 4m/s² and t = 5s:
s = 0 +1/2(4)(5²) = 1/2(4)(25) = 50 × 2 = 100m.
This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.
The second equation of motion is s=ut+ 1/2at², where u is the initial velocity, a is the acceleration, and t is the time. For objects starting from rest (u =0), the displacement simplifies to s = 1/2at². For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chaptRead more
The second equation of motion is s=ut+ 1/2at², where u is the initial velocity, a is the acceleration, and t is the time. For objects starting from rest (u =0), the displacement simplifies to s = 1/2at².
The second equation of motion is s = ut +1/2at². Substituting u = 0, s = 20m and t = 2s: 20 = 0 +1/2a(2²) 20 = 2a a = 10 m/s². For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
The second equation of motion is s = ut +1/2at². Substituting u = 0, s = 20m and t = 2s:
20 = 0 +1/2a(2²)
20 = 2a
a = 10 m/s².
The first equation of motion is v = u + at. Here, u = 0, a = 5m/s² and t = 4s. Substituting these values: v = 0 + 5 × 4 = 20 m/s. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
The first equation of motion is v = u + at. Here, u = 0, a = 5m/s² and t = 4s. Substituting these values:
v = 0 + 5 × 4 = 20 m/s.
The first equation of motion is v = u + at, where u is the initial velocity a is the acceleration, and t is the time. This equation applies to objects moving under uniform acceleration. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
The first equation of motion is v = u + at, where u is the initial velocity a is the acceleration, and t is the time. This equation applies to objects moving under uniform acceleration.
The slope of a velocity-time graph represents acceleration. Mathematically, acceleration is the rate of change of velocity, which corresponds to the slope of the graph. This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according toRead more
The slope of a velocity-time graph represents acceleration. Mathematically, acceleration is the rate of change of velocity, which corresponds to the slope of the graph.
This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.
An object is dropped from a height of 80 m. Assuming no air resistance, how long will it take to reach the ground? ( 𝑔 = 10 m/s² )
Using s = 1/2gt² , where s= 80m and g = 10 m/s ²: 80 = 1/2(10)t² 80 = 5t² t² = 16 t = 4s This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncRead more
Using s = 1/2gt² , where s= 80m and g = 10 m/s ²:
80 = 1/2(10)t²
80 = 5t²
t² = 16
t = 4s
This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
Which of the following is a correct statement about acceleration?
Acceleration is defined as the rate of change of velocity with respect to time. It can be positive, negative, or zero depending on whether the velocity is increasing, decreasing, or constant. This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. GiRead more
Acceleration is defined as the rate of change of velocity with respect to time. It can be positive, negative, or zero depending on whether the velocity is increasing, decreasing, or constant.
This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
A body moves in a straight line with a uniform velocity of 10m/s for 5 seconds. What is the total displacement?
Displacement is given by s = vt, where v = 10m/s and t = 5s: s= 10 × 5 = 50m. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
Displacement is given by s = vt, where v = 10m/s and t = 5s:
s= 10 × 5 = 50m.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
What does the area under the velocity-time graph of an object represent?
The area under the velocity-time graph represents the displacement of an object. It is calculated by integrating the velocity with respect to time or finding the area geometrically in cases of simple shapes. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/physics/cRead more
The area under the velocity-time graph represents the displacement of an object. It is calculated by integrating the velocity with respect to time or finding the area geometrically in cases of simple shapes.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
An object moves with uniform acceleration of 4 m/s². If it starts from rest, what will be its displacement after 5 seconds?
Using s = ut +1/2at², where u = 0, a = 4m/s² and t = 5s: s = 0 +1/2(4)(5²) = 1/2(4)(25) = 50 × 2 = 100m. This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding. For more please visit here: https://www.tiwaRead more
Using s = ut +1/2at², where u = 0, a = 4m/s² and t = 5s:
s = 0 +1/2(4)(5²) = 1/2(4)(25) = 50 × 2 = 100m.
This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
If an object starts from rest and moves with uniform acceleration, what will be its displacement after 𝑡 seconds?
The second equation of motion is s=ut+ 1/2at², where u is the initial velocity, a is the acceleration, and t is the time. For objects starting from rest (u =0), the displacement simplifies to s = 1/2at². For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chaptRead more
The second equation of motion is s=ut+ 1/2at², where u is the initial velocity, a is the acceleration, and t is the time. For objects starting from rest (u =0), the displacement simplifies to s = 1/2at².
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
A particle covers 20m in the first 2 seconds of its motion from rest under uniform acceleration. What is the magnitude of its acceleration?
The second equation of motion is s = ut +1/2at². Substituting u = 0, s = 20m and t = 2s: 20 = 0 +1/2a(2²) 20 = 2a a = 10 m/s². For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
The second equation of motion is s = ut +1/2at². Substituting u = 0, s = 20m and t = 2s:
20 = 0 +1/2a(2²)
20 = 2a
a = 10 m/s².
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
A car starts from rest and accelerates uniformly at 5m/s². What will be its velocity after 4 seconds?
The first equation of motion is v = u + at. Here, u = 0, a = 5m/s² and t = 4s. Substituting these values: v = 0 + 5 × 4 = 20 m/s. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
The first equation of motion is v = u + at. Here, u = 0, a = 5m/s² and t = 4s. Substituting these values:
v = 0 + 5 × 4 = 20 m/s.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
What is the equation for the final velocity of an object moving with uniform acceleration?
The first equation of motion is v = u + at, where u is the initial velocity a is the acceleration, and t is the time. This equation applies to objects moving under uniform acceleration. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
The first equation of motion is v = u + at, where u is the initial velocity a is the acceleration, and t is the time. This equation applies to objects moving under uniform acceleration.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
What represent in the slope of a velocity-time graph?
The slope of a velocity-time graph represents acceleration. Mathematically, acceleration is the rate of change of velocity, which corresponds to the slope of the graph. This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according toRead more
The slope of a velocity-time graph represents acceleration. Mathematically, acceleration is the rate of change of velocity, which corresponds to the slope of the graph.
This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/