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(a) (–7) – 8 – (–25) = –7 – 8 + 25 = –15 + 25 = 10 (b) (–13) + 32 – 8 – 1 = –13 + 32 – 8 – 1 = 32 – 22 = 10 (c) (–7) + (–8) + (–90) = –7 – 8 – 90 = –105 (d) 50 – (–40) – (–2) = 50 + 40 + 2 = 92 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-6/
(a) (–7) – 8 – (–25) = –7 – 8 + 25 = –15 + 25 = 10
(b) (–13) + 32 – 8 – 1 = –13 + 32 – 8 – 1 = 32 – 22 = 10
(c) (–7) + (–8) + (–90) = –7 – 8 – 90 = –105
(d) 50 – (–40) – (–2) = 50 + 40 + 2 = 92
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-6/
(a) (–8) + 8 = 0 (b) 13 + (–13) = 0 (c) 12 + (–12) = 0 (d) (–4) + (–8) = –12 (e) 5 – 15 = –10 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-6/
(a) (–8) + 8 = 0 (b) 13 + (–13) = 0 (c) 12 + (–12) = 0 (d) (–4) + (–8) = –12 (e) 5 – 15 = –10
(a) 35 – 20 = 15 (b) 72 – 90 = –18 (c) (–15) – (–18) = –15 + 18 = 3 (d) –20 – (13) = –20 – 13 = –33 (e) 23 – (–12) = 23 + 12 = 35 (f) (–32) – (–40) = –32 + 40 = 8 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-6/
(a) 35 – 20 = 15 (b) 72 – 90 = –18 (c) (–15) – (–18) = –15 + 18 = 3 (d) –20 – (13) = –20 – 13 = –33 (e) 23 – (–12) = 23 + 12 = 35 (f) (–32) – (–40) = –32 + 40 = 8
(a) (–7) + (–9) + 4 + 16 = –7 – 9 + 4 + 16 = –16 + 20 = 4 (b) 37 + (–2) + (–65) + (–8) = 37 – 2 – 65 – 8 = 37 – 75 = –38 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-6/
(a) (–7) + (–9) + 4 + 16 = –7 – 9 + 4 + 16 = –16 + 20 = 4 (b) 37 + (–2) + (–65) + (–8) = 37 – 2 – 65 – 8 = 37 – 75 = –38
(a) 137 + (–354) = 137 – 354 = –217 (b) (–52) + 52 = 0 (c) (–312) + 39 + 192 = –312 + 231 = –81 (d) (–50) + (–200) + 300 = –50 – 200 + 300 = –250 + 300 = 50 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-6/
(a) 137 + (–354) = 137 – 354 = –217 (b) (–52) + 52 = 0 (c) (–312) + 39 + 192 = –312 + 231 = –81 (d) (–50) + (–200) + 300 = –50 – 200 + 300 = –250 + 300 = 50
Find: (a) (–7) – 8 – (–25) (b) (–13) + 32 – 8 – 1 (c) (–7) + (–8) + (–90) (d) 50 – (–40) – (–2)
(a) (–7) – 8 – (–25) = –7 – 8 + 25 = –15 + 25 = 10 (b) (–13) + 32 – 8 – 1 = –13 + 32 – 8 – 1 = 32 – 22 = 10 (c) (–7) + (–8) + (–90) = –7 – 8 – 90 = –105 (d) 50 – (–40) – (–2) = 50 + 40 + 2 = 92 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-6/
(a) (–7) – 8 – (–25)
= –7 – 8 + 25
= –15 + 25
= 10
(b) (–13) + 32 – 8 – 1
= –13 + 32 – 8 – 1
= 32 – 22
= 10
(c) (–7) + (–8) + (–90)
= –7 – 8 – 90
= –105
(d) 50 – (–40) – (–2)
= 50 + 40 + 2
= 92
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-6/
See lessFill in the blanks: (a) (–8) + __________ = 0 (b) 13 + __________ = 0 (c) 12 + (–12) = __________ (d) (–4) + __________ = –12 (e) __________ – 15 = –10
(a) (–8) + 8 = 0 (b) 13 + (–13) = 0 (c) 12 + (–12) = 0 (d) (–4) + (–8) = –12 (e) 5 – 15 = –10 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-6/
(a) (–8) + 8 = 0
(b) 13 + (–13) = 0
(c) 12 + (–12) = 0
(d) (–4) + (–8) = –12
(e) 5 – 15 = –10
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-6/
See lessSubtract: (a) 35 – (20) (b) 72 – (90) (c) (–15) – (–18) (d) (–20) – (13) (e) 23 – (–12) (f) (–32) – (–40)
(a) 35 – 20 = 15 (b) 72 – 90 = –18 (c) (–15) – (–18) = –15 + 18 = 3 (d) –20 – (13) = –20 – 13 = –33 (e) 23 – (–12) = 23 + 12 = 35 (f) (–32) – (–40) = –32 + 40 = 8 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-6/
(a) 35 – 20 = 15
(b) 72 – 90 = –18
(c) (–15) – (–18) = –15 + 18 = 3
(d) –20 – (13) = –20 – 13 = –33
(e) 23 – (–12) = 23 + 12 = 35
(f) (–32) – (–40) = –32 + 40 = 8
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-6/
See lessFind the value of: (a) (–7) + (–9) + 4 + 16 (b) 37 + (–2) + (–65) + (–8)
(a) (–7) + (–9) + 4 + 16 = –7 – 9 + 4 + 16 = –16 + 20 = 4 (b) 37 + (–2) + (–65) + (–8) = 37 – 2 – 65 – 8 = 37 – 75 = –38 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-6/
(a) (–7) + (–9) + 4 + 16 = –7 – 9 + 4 + 16 = –16 + 20 = 4
(b) 37 + (–2) + (–65) + (–8) = 37 – 2 – 65 – 8 = 37 – 75 = –38
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-6/
See lessFind the sum of: (a) 137 and –354 (b) –52 and 52 (c) –213, 39 and 192 (d) –50, –200 and 300
(a) 137 + (–354) = 137 – 354 = –217 (b) (–52) + 52 = 0 (c) (–312) + 39 + 192 = –312 + 231 = –81 (d) (–50) + (–200) + 300 = –50 – 200 + 300 = –250 + 300 = 50 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-6/
(a) 137 + (–354) = 137 – 354 = –217
(b) (–52) + 52 = 0
(c) (–312) + 39 + 192 = –312 + 231 = –81
(d) (–50) + (–200) + 300 = –50 – 200 + 300 = –250 + 300 = 50
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-6/
See less