S.P. of each buffalo = ₹ 20,000 S.P. of two buffaloes = ₹ 20,000 x 2 = ₹ 40,000 One buffalo is sold at 5% gain. Let C.P. be ₹ 100, then S.P. = 100 + 5 = ₹105 ∵ When S.P. is ₹ 105, then C.P. = ₹ 100 ∴ When S.P. is ₹ 1, then C.P. = 100/105 ∴ When S.P. is ₹ 20,000, then C.P. = 100/105 x 20000 = ₹ 19,04Read more
S.P. of each buffalo = ₹ 20,000
S.P. of two buffaloes = ₹ 20,000 x 2 = ₹ 40,000
One buffalo is sold at 5% gain.
Let C.P. be ₹ 100, then S.P. = 100 + 5 = ₹105
∵ When S.P. is ₹ 105, then C.P. = ₹ 100
∴ When S.P. is ₹ 1, then C.P. = 100/105
∴ When S.P. is ₹ 20,000, then C.P. = 100/105 x 20000 = ₹ 19,047.62
Another buffalo is sold at 10% loss.
Let C.P. be ₹ 100, then S.P. = 100 – 10 = ₹ 90
∵ When S.P. is ₹ 90, then C.P. = ₹ 100
∴ When S.P. is ₹ 1, then C.P. = 100/90
∴ When S.P. is ₹ 20,000, then C.P. = 100/90×20000 = ₹ 22,222.22
Total C.P. = ₹ 19,047.62 + ₹ 22,222.22 = ₹ 41,269.84
Since C.P. > S.P. Therefore here it is loss.
Loss = C.P. – S.P. = ₹ 41,269.84 – ₹ 40,000.00 = ₹ 1,269.84
Class 8 Maths Chapter 8 Exercise 8.2 Solution in Video
Class 8 Maths Chapter 8 Exercise 8.2 Solution in Video
Rate of discount on all items = 10% Marked Price of a pair of jeans = ₹ 1450 and Marked Price of a shirt = ₹ 850 Discount on a pair of jeans = Rate X M.P./100 = 10 X 1450/100 = ₹ 145 ∴ S.P. of a pair of jeans = ₹ 1450 – ₹ 145 = ₹ 1305 Marked Price of two shirts = 2 x 850 = ₹ 1700 Discount on two shiRead more
Rate of discount on all items = 10%
Marked Price of a pair of jeans = ₹ 1450 and Marked Price of a shirt = ₹ 850
Discount on a pair of jeans = Rate X M.P./100 = 10 X 1450/100 = ₹ 145
∴ S.P. of a pair of jeans = ₹ 1450 – ₹ 145 = ₹ 1305
Marked Price of two shirts = 2 x 850 = ₹ 1700
Discount on two shirts = Rate X M.P./100 = 10X1700/100 = ₹ 170
∴ S.P. of two shirts = ₹ 1700 – ₹ 170 = ₹ 1530
Therefore, the customer had to pay = 1305 + 1530 = ₹ 2,835
Class 8 Maths Chapter 8 Exercise 8.2 Solution in Video
Cost price of VCR = ₹ 8000 and Cost price of TV = ₹ 8000 Total Cost Price of both articles = ₹ 8000 + ₹ 8000 = ₹ 16,000 Now VCR is sold at 4% loss. Let C.P. of each article be ₹ 100, then S.P. of VCR = 100 – 4 = ₹ 96 ∵ When C.P. is ₹ 100, then S.P. = ₹ 96 ∴ When C.P. is ₹ 1, then S.P. = 96/100 ∴ WheRead more
Cost price of VCR = ₹ 8000 and Cost price of TV = ₹ 8000
Total Cost Price of both articles = ₹ 8000 + ₹ 8000 = ₹ 16,000
Now VCR is sold at 4% loss.
Let C.P. of each article be ₹ 100, then S.P. of VCR = 100 – 4 = ₹ 96
∵ When C.P. is ₹ 100, then S.P. = ₹ 96
∴ When C.P. is ₹ 1, then S.P. = 96/100
∴ When C.P. is ₹ 8000, then S.P. = 96/100×8000 =₹ 7,680
And TV is sold at 8% profit, then S.P. of TV = 100 + 8 = ₹ 108
∵ When C.P. is ₹ 100, then S.P. = ₹ 108
∴ When C.P. is ₹ 1, then S.P. = 108/100
∴ When C.P. is ₹ 8000, then S.P. = 108/100 = ₹ 8,640
Then, Total S.P. = ₹ 7,680 + ₹ 8,640 = ₹ 16,320
Since S.P. > C.P.,
Therefore Profit = S.P. – C.P. = 16320 – 16000 = ₹ 320
And Profit% = Profit/Cost Price x 100 = 320/16000 x 100 = 2%
Class 8 Maths Chapter 8 Exercise 8.2 Solution in Video
Here, C.P. = ₹ 15,500 and Repair cost = ₹ 450 Therefore Total Cost Price = 15500 + 450 = ₹ 15,950 Let C.P be ₹ 100, then S.P. = 100 + 15 = ₹ 115 ∵ When C.P. is ₹ 100, then S.P. = ₹ 115 ∴ When C.P. is ₹ 1, then S.P. = 115/100 ∴ When C.P. is ₹ 15950, then S.P. = 115/100x15950 = ₹ 18,342.50 Class 8 MatRead more
Here, C.P. = ₹ 15,500 and Repair cost = ₹ 450
Therefore Total Cost Price = 15500 + 450 = ₹ 15,950
Let C.P be ₹ 100, then S.P. = 100 + 15 = ₹ 115
∵ When C.P. is ₹ 100, then S.P. = ₹ 115
∴ When C.P. is ₹ 1, then S.P. = 115/100
∴ When C.P. is ₹ 15950, then S.P. = 115/100×15950 = ₹ 18,342.50
Class 8 Maths Chapter 8 Exercise 8.2 Solution in Video
A milkman sold two of his buffaloes for ₹ 20,000 each. On one he made a gain of 5% and on the other a loss of 10%. Find his overall gain or loss. (Hint: Find CP of each)
S.P. of each buffalo = ₹ 20,000 S.P. of two buffaloes = ₹ 20,000 x 2 = ₹ 40,000 One buffalo is sold at 5% gain. Let C.P. be ₹ 100, then S.P. = 100 + 5 = ₹105 ∵ When S.P. is ₹ 105, then C.P. = ₹ 100 ∴ When S.P. is ₹ 1, then C.P. = 100/105 ∴ When S.P. is ₹ 20,000, then C.P. = 100/105 x 20000 = ₹ 19,04Read more
S.P. of each buffalo = ₹ 20,000
S.P. of two buffaloes = ₹ 20,000 x 2 = ₹ 40,000
One buffalo is sold at 5% gain.
Let C.P. be ₹ 100, then S.P. = 100 + 5 = ₹105
∵ When S.P. is ₹ 105, then C.P. = ₹ 100
∴ When S.P. is ₹ 1, then C.P. = 100/105
∴ When S.P. is ₹ 20,000, then C.P. = 100/105 x 20000 = ₹ 19,047.62
Another buffalo is sold at 10% loss.
Let C.P. be ₹ 100, then S.P. = 100 – 10 = ₹ 90
∵ When S.P. is ₹ 90, then C.P. = ₹ 100
∴ When S.P. is ₹ 1, then C.P. = 100/90
∴ When S.P. is ₹ 20,000, then C.P. = 100/90×20000 = ₹ 22,222.22
Total C.P. = ₹ 19,047.62 + ₹ 22,222.22 = ₹ 41,269.84
Since C.P. > S.P. Therefore here it is loss.
Loss = C.P. – S.P. = ₹ 41,269.84 – ₹ 40,000.00 = ₹ 1,269.84
Class 8 Maths Chapter 8 Exercise 8.2 Solution in Video
Class 8 Maths Chapter 8 Exercise 8.2 Solution in Video
See lessDuring a sale, a shop offered a discount of 10% on the marked prices of all the items. What would a customer have to pay for a pair of jeans marked at ₹ 1450 and two shirts marked at ₹ 850 each?
Rate of discount on all items = 10% Marked Price of a pair of jeans = ₹ 1450 and Marked Price of a shirt = ₹ 850 Discount on a pair of jeans = Rate X M.P./100 = 10 X 1450/100 = ₹ 145 ∴ S.P. of a pair of jeans = ₹ 1450 – ₹ 145 = ₹ 1305 Marked Price of two shirts = 2 x 850 = ₹ 1700 Discount on two shiRead more
Rate of discount on all items = 10%
Marked Price of a pair of jeans = ₹ 1450 and Marked Price of a shirt = ₹ 850
Discount on a pair of jeans = Rate X M.P./100 = 10 X 1450/100 = ₹ 145
∴ S.P. of a pair of jeans = ₹ 1450 – ₹ 145 = ₹ 1305
Marked Price of two shirts = 2 x 850 = ₹ 1700
Discount on two shirts = Rate X M.P./100 = 10X1700/100 = ₹ 170
∴ S.P. of two shirts = ₹ 1700 – ₹ 170 = ₹ 1530
Therefore, the customer had to pay = 1305 + 1530 = ₹ 2,835
Class 8 Maths Chapter 8 Exercise 8.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-8/
A VCR and TV were bought for ₹ 8,000 each. The shopkeeper made a loss of 4% on the VCR and a profit of 8% on the TV. Find the gain or loss percent on the whole transaction.
Cost price of VCR = ₹ 8000 and Cost price of TV = ₹ 8000 Total Cost Price of both articles = ₹ 8000 + ₹ 8000 = ₹ 16,000 Now VCR is sold at 4% loss. Let C.P. of each article be ₹ 100, then S.P. of VCR = 100 – 4 = ₹ 96 ∵ When C.P. is ₹ 100, then S.P. = ₹ 96 ∴ When C.P. is ₹ 1, then S.P. = 96/100 ∴ WheRead more
Cost price of VCR = ₹ 8000 and Cost price of TV = ₹ 8000
Total Cost Price of both articles = ₹ 8000 + ₹ 8000 = ₹ 16,000
Now VCR is sold at 4% loss.
Let C.P. of each article be ₹ 100, then S.P. of VCR = 100 – 4 = ₹ 96
∵ When C.P. is ₹ 100, then S.P. = ₹ 96
∴ When C.P. is ₹ 1, then S.P. = 96/100
∴ When C.P. is ₹ 8000, then S.P. = 96/100×8000 =₹ 7,680
And TV is sold at 8% profit, then S.P. of TV = 100 + 8 = ₹ 108
∵ When C.P. is ₹ 100, then S.P. = ₹ 108
∴ When C.P. is ₹ 1, then S.P. = 108/100
∴ When C.P. is ₹ 8000, then S.P. = 108/100 = ₹ 8,640
Then, Total S.P. = ₹ 7,680 + ₹ 8,640 = ₹ 16,320
Since S.P. > C.P.,
Therefore Profit = S.P. – C.P. = 16320 – 16000 = ₹ 320
And Profit% = Profit/Cost Price x 100 = 320/16000 x 100 = 2%
Class 8 Maths Chapter 8 Exercise 8.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-8/
The cost of an article was ₹ 15,500, ₹ 450 were spent on its repairs. If it sold for a profit of 15%, find the selling price of the article.
Here, C.P. = ₹ 15,500 and Repair cost = ₹ 450 Therefore Total Cost Price = 15500 + 450 = ₹ 15,950 Let C.P be ₹ 100, then S.P. = 100 + 15 = ₹ 115 ∵ When C.P. is ₹ 100, then S.P. = ₹ 115 ∴ When C.P. is ₹ 1, then S.P. = 115/100 ∴ When C.P. is ₹ 15950, then S.P. = 115/100x15950 = ₹ 18,342.50 Class 8 MatRead more
Here, C.P. = ₹ 15,500 and Repair cost = ₹ 450
Therefore Total Cost Price = 15500 + 450 = ₹ 15,950
Let C.P be ₹ 100, then S.P. = 100 + 15 = ₹ 115
∵ When C.P. is ₹ 100, then S.P. = ₹ 115
∴ When C.P. is ₹ 1, then S.P. = 115/100
∴ When C.P. is ₹ 15950, then S.P. = 115/100×15950 = ₹ 18,342.50
Class 8 Maths Chapter 8 Exercise 8.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-8/
A shopkeeper buys 80 articles for ₹ 2,400 and sells them for a profit of 16%. Find the selling price of one article.
No. of articles = 80 Cost Price of articles = ₹ 2,400 And Profit = 16% ∵ Cost price of articles is ₹ 100, then selling price = 100 + 16 = ₹ 116 ∴ Cost price of articles is ₹ 1, then selling price = 116/100 ∴ Cost price of articles is ₹ 2400, then selling price = 116/100x2400 = ₹ 2784 Hence, SellingRead more
No. of articles = 80
Cost Price of articles = ₹ 2,400
And Profit = 16%
∵ Cost price of articles is ₹ 100, then selling price = 100 + 16 = ₹ 116
∴ Cost price of articles is ₹ 1, then selling price = 116/100
∴ Cost price of articles is ₹ 2400, then selling price = 116/100×2400 = ₹ 2784
Hence, Selling Price of 80 articles = ₹ 2784
Therefore Selling Price of 1 article = 2784/80 = ₹ 34.80
Class 8 Maths Chapter 8 Exercise 8.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-8/