Here, Principal (P) = ₹ 12,500, Time (T) = 3 years, Rate of interest (R) = 12% p.a. Simple Interest for Fabina = PxRxT/100 = 12500x12x3/100 = ₹ 4,500 Amount for Radha, P = ₹ 12,500, R = 10% and n = 3 years Amount (A) = P(1+R/100)ⁿ = 12500(1+10/100)³ = 12500(1+1/100)³ 12500(11/10)³ = 1250x11/10 x 11/Read more
Here, Principal (P) = ₹ 12,500, Time (T) = 3 years, Rate of interest (R) = 12% p.a.
Simple Interest for Fabina = PxRxT/100 = 12500x12x3/100 = ₹ 4,500
Amount for Radha, P = ₹ 12,500, R = 10% and n = 3 years
Amount (A) = P(1+R/100)ⁿ = 12500(1+10/100)³ = 12500(1+1/100)³
12500(11/10)³ = 1250×11/10 x 11/10 x 11/10 = ₹ 16,637.50
∴ C.I. for Radha = A – P = ₹ 16,637.50 – ₹ 12,500 = ₹ 4,137.50
Here, Fabina pays more interest = ₹ 4,500 – ₹ 4,137.50 = ₹ 362.50
Class 8 Maths Chapter 8 Exercise 8.3 Solution in Video
Here, Principal (P) = ₹ 26,400, Time (n) = 2 years 4 months, Rate of interest (R) = 15% p.a. Amount for 2 years (A) = P(1+R/100)ⁿ = 26400(1+15/100)² = 26400(1+3/20)² = 26400 (23/20)² = 26400 x 23/20 x 23/20 = ₹ 34,914 Interest for 4 months = 4/12 = 1/3 years at the rate of 15% = 1/3x 34914x15x1/100Read more
Here, Principal (P) = ₹ 26,400,
Time (n) = 2 years 4 months, Rate of interest (R) = 15% p.a.
Amount for 2 years (A) = P(1+R/100)ⁿ = 26400(1+15/100)² = 26400(1+3/20)²
= 26400 (23/20)² = 26400 x 23/20 x 23/20 = ₹ 34,914
Interest for 4 months = 4/12 = 1/3 years at the rate of 15% = 1/3x 34914x15x1/100
= ₹ 1745.70
Total amount = ₹ 34,914 + ₹ 1,745.70 = ₹ 36,659.70
∴ Total amount = ₹ 34,914 + ₹ 1,745.70 = ₹ 36,659.70
Class 8 Maths Chapter 8 Exercise 8.3 Solution in Video
C.P. = ₹ 5,400 and Rate of VAT = 8% Let C.P. without VAT is ₹100, then price including VAT = 100 + 8 = ₹ 108 ∵ When price including VAT is ₹ 108, then original price = ₹ 100 ∴ When price including VAT is ₹ 1, then original price = 100/108 ∴ When price including VAT is ₹ 5400, then original price = 1Read more
C.P. = ₹ 5,400 and Rate of VAT = 8%
Let C.P. without VAT is ₹100, then price including VAT = 100 + 8 = ₹ 108
∵ When price including VAT is ₹ 108, then original price = ₹ 100
∴ When price including VAT is ₹ 1, then original price = 100/108
∴ When price including VAT is ₹ 5400,
then original price = 100/108 x 5400 = ₹ 5000
Class 8 Maths Chapter 8 Exercise 8.2 Solution in Video
S.P. = ₹1,600 and Rate of discount = 20% Let M.P. be ₹ 100, then S.P. for customer = 100 – 20 = ₹ 80 ∵ When S.P. is ₹ 80, then M.P. = ₹ 100 ∴ When S.P. is ₹1, then M.P. = 100/80 ∴ When S.P. is ₹1600, then M.P. = 100/80 x 1600 = ₹ 2,000 Class 8 Maths Chapter 8 Exercise 8.2 Solution in Video for moreRead more
S.P. = ₹1,600 and Rate of discount = 20%
Let M.P. be ₹ 100, then S.P. for customer = 100 – 20 = ₹ 80
∵ When S.P. is ₹ 80, then M.P. = ₹ 100
∴ When S.P. is ₹1, then M.P. = 100/80
∴ When S.P. is ₹1600, then M.P. = 100/80 x 1600 = ₹ 2,000
Class 8 Maths Chapter 8 Exercise 8.2 Solution in Video
C.P. = ₹ 13,000 and S.T. rate = 12% Let C.P. be ₹ 100, then S.P. for purchaser = 100 + 12 = ₹ 112 ∵ When C.P. is ₹ 100, then S.P. = ₹ 112 ∴ When C.P. is ₹ 1, then S.P. = 112/100 ∴ When C.P. is ₹ 13,000, then S.P. = 112/100 x 13000 = ₹ 14,560 Class 8 Maths Chapter 8 Exercise 8.2 Solution in Video forRead more
C.P. = ₹ 13,000 and S.T. rate = 12%
Let C.P. be ₹ 100, then S.P. for purchaser = 100 + 12 = ₹ 112
∵ When C.P. is ₹ 100, then S.P. = ₹ 112
∴ When C.P. is ₹ 1, then S.P. = 112/100
∴ When C.P. is ₹ 13,000, then S.P. = 112/100 x 13000 = ₹ 14,560
Class 8 Maths Chapter 8 Exercise 8.2 Solution in Video
Fabina borrows ₹ 12,500 per annum for 3 years at simple interest and Radha borrows the same amount for the same time period at 10% per annum, compounded annually. Who pays more interest and by how much?
Here, Principal (P) = ₹ 12,500, Time (T) = 3 years, Rate of interest (R) = 12% p.a. Simple Interest for Fabina = PxRxT/100 = 12500x12x3/100 = ₹ 4,500 Amount for Radha, P = ₹ 12,500, R = 10% and n = 3 years Amount (A) = P(1+R/100)ⁿ = 12500(1+10/100)³ = 12500(1+1/100)³ 12500(11/10)³ = 1250x11/10 x 11/Read more
Here, Principal (P) = ₹ 12,500, Time (T) = 3 years, Rate of interest (R) = 12% p.a.
Simple Interest for Fabina = PxRxT/100 = 12500x12x3/100 = ₹ 4,500
Amount for Radha, P = ₹ 12,500, R = 10% and n = 3 years
Amount (A) = P(1+R/100)ⁿ = 12500(1+10/100)³ = 12500(1+1/100)³
12500(11/10)³ = 1250×11/10 x 11/10 x 11/10 = ₹ 16,637.50
∴ C.I. for Radha = A – P = ₹ 16,637.50 – ₹ 12,500 = ₹ 4,137.50
Here, Fabina pays more interest = ₹ 4,500 – ₹ 4,137.50 = ₹ 362.50
Class 8 Maths Chapter 8 Exercise 8.3 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-8/
Kamala borrowed ₹ 26,400 from a Bank to buy a scooter at a rate of 15% p.a. compounded yearly. What amount will she pay at the end of 2 years and 4 months to clear the loan? (Hint: Find A for 2 years with interest is compounded yearly and then find SI on the 2ⁿᵈ year amount for 4/12 years).
Here, Principal (P) = ₹ 26,400, Time (n) = 2 years 4 months, Rate of interest (R) = 15% p.a. Amount for 2 years (A) = P(1+R/100)ⁿ = 26400(1+15/100)² = 26400(1+3/20)² = 26400 (23/20)² = 26400 x 23/20 x 23/20 = ₹ 34,914 Interest for 4 months = 4/12 = 1/3 years at the rate of 15% = 1/3x 34914x15x1/100Read more
Here, Principal (P) = ₹ 26,400,
Time (n) = 2 years 4 months, Rate of interest (R) = 15% p.a.
Amount for 2 years (A) = P(1+R/100)ⁿ = 26400(1+15/100)² = 26400(1+3/20)²
= 26400 (23/20)² = 26400 x 23/20 x 23/20 = ₹ 34,914
Interest for 4 months = 4/12 = 1/3 years at the rate of 15% = 1/3x 34914x15x1/100
= ₹ 1745.70
Total amount = ₹ 34,914 + ₹ 1,745.70 = ₹ 36,659.70
∴ Total amount = ₹ 34,914 + ₹ 1,745.70 = ₹ 36,659.70
Class 8 Maths Chapter 8 Exercise 8.3 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-8/
I purchased a hair-dryer for ₹ 5,400 including 8% VAT. Find the price before VAT was added.
C.P. = ₹ 5,400 and Rate of VAT = 8% Let C.P. without VAT is ₹100, then price including VAT = 100 + 8 = ₹ 108 ∵ When price including VAT is ₹ 108, then original price = ₹ 100 ∴ When price including VAT is ₹ 1, then original price = 100/108 ∴ When price including VAT is ₹ 5400, then original price = 1Read more
C.P. = ₹ 5,400 and Rate of VAT = 8%
Let C.P. without VAT is ₹100, then price including VAT = 100 + 8 = ₹ 108
∵ When price including VAT is ₹ 108, then original price = ₹ 100
∴ When price including VAT is ₹ 1, then original price = 100/108
∴ When price including VAT is ₹ 5400,
then original price = 100/108 x 5400 = ₹ 5000
Class 8 Maths Chapter 8 Exercise 8.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-8/
Arun bought a pair of skates at a sale where the discount given was 20%. If the amount he pays is ₹1,600, find the marked price.
S.P. = ₹1,600 and Rate of discount = 20% Let M.P. be ₹ 100, then S.P. for customer = 100 – 20 = ₹ 80 ∵ When S.P. is ₹ 80, then M.P. = ₹ 100 ∴ When S.P. is ₹1, then M.P. = 100/80 ∴ When S.P. is ₹1600, then M.P. = 100/80 x 1600 = ₹ 2,000 Class 8 Maths Chapter 8 Exercise 8.2 Solution in Video for moreRead more
S.P. = ₹1,600 and Rate of discount = 20%
Let M.P. be ₹ 100, then S.P. for customer = 100 – 20 = ₹ 80
∵ When S.P. is ₹ 80, then M.P. = ₹ 100
∴ When S.P. is ₹1, then M.P. = 100/80
∴ When S.P. is ₹1600, then M.P. = 100/80 x 1600 = ₹ 2,000
Class 8 Maths Chapter 8 Exercise 8.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-8/
The price of a TV is ₹ 13,000. The sales tax charged on it is at the rate of 12%. Find the amount that Vinod will have to pay if he buys it.
C.P. = ₹ 13,000 and S.T. rate = 12% Let C.P. be ₹ 100, then S.P. for purchaser = 100 + 12 = ₹ 112 ∵ When C.P. is ₹ 100, then S.P. = ₹ 112 ∴ When C.P. is ₹ 1, then S.P. = 112/100 ∴ When C.P. is ₹ 13,000, then S.P. = 112/100 x 13000 = ₹ 14,560 Class 8 Maths Chapter 8 Exercise 8.2 Solution in Video forRead more
C.P. = ₹ 13,000 and S.T. rate = 12%
Let C.P. be ₹ 100, then S.P. for purchaser = 100 + 12 = ₹ 112
∵ When C.P. is ₹ 100, then S.P. = ₹ 112
∴ When C.P. is ₹ 1, then S.P. = 112/100
∴ When C.P. is ₹ 13,000, then S.P. = 112/100 x 13000 = ₹ 14,560
Class 8 Maths Chapter 8 Exercise 8.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-8/