Drift velocity vd is given by = vd = eEτ/m, Where E = V/L. Thus, vd = eVr/mL Since vd is directly proportional to V, the correct answer is (c) V. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-3/
Drift velocity vd is given by = vd = eEτ/m, Where E = V/L. Thus,
vd = eVr/mL
Since vd is directly proportional to V, the correct answer is (c) V.
Current is given by I = Q/t For A: I = 300/60 = 5A (correct). For B: Charge Q = (3.125 10) (1.6 10) = 5C, so I = 5A (correct). Thus, both A and B are correct. Answer: (c) both A and B. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-3/
Current is given by I = Q/t
For A: I = 300/60 = 5A (correct).
For B: Charge Q = (3.125 10) (1.6 10) = 5C, so I = 5A (correct).
Thus, both A and B are correct. Answer: (c) both A and B.
The resistance of the bulb is R =220²/100= 484Ω . When operated at 110V, power consumed is P ′ = 110²/484 = 25W. thus, the Correct answer: (a) 25 W. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-3/
The resistance of the bulb is
R =220²/100= 484Ω
. When operated at 110V, power consumed is
P ′ = 110²/484 = 25W.
thus, the Correct answer: (a) 25 W.
When a potential difference V is applied across a conductor at temperature T, the drift velocity of the electrons is proportional to :
Drift velocity vd is given by = vd = eEτ/m, Where E = V/L. Thus, vd = eVr/mL Since vd is directly proportional to V, the correct answer is (c) V. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-3/
Drift velocity vd is given by = vd = eEτ/m, Where E = V/L. Thus,
vd = eVr/mL
Since vd is directly proportional to V, the correct answer is (c) V.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-3/
Two students A and B calculate the charge flowing through a circuit. A concludes that 300 C of charge flows in 1 minute. B concludes that 3.125 x 10¹⁹ electrons flow in 1 second. If the current measured in the circuit is 5 A, then the correct calculation is done by
Current is given by I = Q/t For A: I = 300/60 = 5A (correct). For B: Charge Q = (3.125 10) (1.6 10) = 5C, so I = 5A (correct). Thus, both A and B are correct. Answer: (c) both A and B. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-3/
Current is given by I = Q/t
For A: I = 300/60 = 5A (correct).
For B: Charge Q = (3.125 10) (1.6 10) = 5C, so I = 5A (correct).
Thus, both A and B are correct. Answer: (c) both A and B.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-3/
The electric power consumed by a 220 V-100 W bulb when operated at 110 V is:
The resistance of the bulb is R =220²/100= 484Ω . When operated at 110V, power consumed is P ′ = 110²/484 = 25W. thus, the Correct answer: (a) 25 W. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-3/
The resistance of the bulb is
R =220²/100= 484Ω
. When operated at 110V, power consumed is
P ′ = 110²/484 = 25W.
thus, the Correct answer: (a) 25 W.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-3/