√2, √8, √18 , √32, . . . a₂ - a₁ = √8 - √2 = 2√2 - √2 = √2 a₃ - a₂ = √18 - √8 = 3√2 - 2√2 = √2 a₄ - a₃ = √32 - √18 = 4√2 - 3√2 = √2 The difference between the successive terms are same Hence, it is an A.P. Common difference = √2, next three terms of this AP is as follows: Fifth term a₅ = a₄ + d = √3Read more
√2, √8, √18 , √32, . . .
a₂ – a₁ = √8 – √2 = 2√2 – √2 = √2
a₃ – a₂ = √18 – √8 = 3√2 – 2√2 = √2
a₄ – a₃ = √32 – √18 = 4√2 – 3√2 = √2
The difference between the successive terms are same Hence, it is an A.P.
Common difference = √2, next three terms of this AP is as follows:
Fifth term a₅ = a₄ + d = √32 + √2 = 4√2 + √2 = 5√2 = √50
Sixth term a₆ = a₅ + d = 5√2 + √2 = 6√2 = √72
Seventh term a₇ = a₆ + d = 6√2 + √2 = 7√2 = √98
a, a², a³, a⁴, . . . a₂ - a₁ = a² - a a₃ - a₂ = a³ - a² a₄ - a₃ = a⁴ - a³ The difference between the successive terms are not same Hence, it is not an A.P.
a, a², a³, a⁴, . . .
a₂ – a₁ = a² – a
a₃ – a₂ = a³ – a²
a₄ – a₃ = a⁴ – a³
The difference between the successive terms are not same Hence, it is not an A.P.
a, 2a, 3a, 4a, . . . a₂ - a₁ = 2a - a = a a₃ - a₂ = 3a - 2a = a a₄ - a₃ = 4a - 3a = a The difference between the successive terms are same Hence, it is an A.P. Common difference = a, next three terms of this AP is as follows: Fifth term a₅ = a₄ + d = 4a + a = 5a Sixth term a₆ = a₅ + d = 5a + a = 6aRead more
a, 2a, 3a, 4a, . . .
a₂ – a₁ = 2a – a = a
a₃ – a₂ = 3a – 2a = a
a₄ – a₃ = 4a – 3a = a
The difference between the successive terms are same Hence, it is an A.P.
Common difference = a, next three terms of this AP is as follows:
Fifth term a₅ = a₄ + d = 4a + a = 5a
Sixth term a₆ = a₅ + d = 5a + a = 6a
Seventh term a₇ = a₆ + d = 6a + a = 7a
0.2, 0.22, 0.222, 0.2222, . . . a₂ - a₁ = 0.22 - 0.2 = 0.02 a₃ - a₂ = 0.222 - 0.22 = 0.002 a₄ - a₃ = 0.2222 - 0.222 = 0.0002 The difference between the successive terms are not same Hence, it is not an A.P.
0.2, 0.22, 0.222, 0.2222, . . .
a₂ – a₁ = 0.22 – 0.2 = 0.02
a₃ – a₂ = 0.222 – 0.22 = 0.002
a₄ – a₃ = 0.2222 – 0.222 = 0.0002
The difference between the successive terms are not same Hence, it is not an A.P.
1, 3, 9, 27, . . . a₂ - a₁ = 3 - 1 = 2 a₃ - a₂ = 9 - 3 = 6 a₄ - a₃ = 27 - 9 = 18 The difference between the successive terms are not same Hence, it is not an A.P.
1, 3, 9, 27, . . .
a₂ – a₁ = 3 – 1 = 2
a₃ – a₂ = 9 – 3 = 6
a₄ – a₃ = 27 – 9 = 18
The difference between the successive terms are not same Hence, it is not an A.P.
–1/2, – 1/2, – 1/2, – 1/2, . . . a₂ - a₁ = - 1/2 - (-1/2) = 0 a₃ - a₂ = - 1/2 - (-1/2) = 0 a₄ - a₃ = - 1/2 - (-1/2) = 0 The difference between the successive terms are not same Hence, it is not an A.P. Common difference = 0, next three terms of this AP is as follows: Fifth term a₅ = a₄ + d = - 1/2 +Read more
–1/2, – 1/2, – 1/2, – 1/2, . . .
a₂ – a₁ = – 1/2 – (-1/2) = 0
a₃ – a₂ = – 1/2 – (-1/2) = 0
a₄ – a₃ = – 1/2 – (-1/2) = 0
The difference between the successive terms are not same Hence, it is not an A.P.
Common difference = 0, next three terms of this AP is as follows:
Fifth term a₅ = a₄ + d = – 1/2 + 0 = – 1/2
Sixth term a₆ = a₅ + d = – 1/2 + 0 = – 1/2
Seventh term a₇ = a₆ + d = – 1/2 + 0 = – 1/2.
0, – 4, – 8, –12, . . . a₂ - a₁ = - 4 - 0 = - 4 a₃ - a₂ = - 8 - (-4) = - 4 a₄ - a₃ = - 12 - (-8) = - 4 The difference between the successive terms are same Hence, it is an A.P. Common difference = - 4, next three terms of this AP is as follows: Fifth term a₅ = a₄ + d = - 12 - 4 = - 16 Sixth term a₆Read more
0, – 4, – 8, –12, . . .
a₂ – a₁ = – 4 – 0 = – 4
a₃ – a₂ = – 8 – (-4) = – 4
a₄ – a₃ = – 12 – (-8) = – 4
The difference between the successive terms are same Hence, it is an A.P.
Common difference = – 4, next three terms of this AP is as follows:
Fifth term a₅ = a₄ + d = – 12 – 4 = – 16
Sixth term a₆ = a₅ + d = – 16 – 4 = – 20
Seventh term a₇ = a₆ + d = – 20 – 4 = -24.
Which of the following are APs ? If they form an AP, find the common difference d and write three more terms. √2, √8, √18 , √32, . . .
√2, √8, √18 , √32, . . . a₂ - a₁ = √8 - √2 = 2√2 - √2 = √2 a₃ - a₂ = √18 - √8 = 3√2 - 2√2 = √2 a₄ - a₃ = √32 - √18 = 4√2 - 3√2 = √2 The difference between the successive terms are same Hence, it is an A.P. Common difference = √2, next three terms of this AP is as follows: Fifth term a₅ = a₄ + d = √3Read more
√2, √8, √18 , √32, . . .
See lessa₂ – a₁ = √8 – √2 = 2√2 – √2 = √2
a₃ – a₂ = √18 – √8 = 3√2 – 2√2 = √2
a₄ – a₃ = √32 – √18 = 4√2 – 3√2 = √2
The difference between the successive terms are same Hence, it is an A.P.
Common difference = √2, next three terms of this AP is as follows:
Fifth term a₅ = a₄ + d = √32 + √2 = 4√2 + √2 = 5√2 = √50
Sixth term a₆ = a₅ + d = 5√2 + √2 = 6√2 = √72
Seventh term a₇ = a₆ + d = 6√2 + √2 = 7√2 = √98
Which of the following are APs ? If they form an AP, find the common difference d and write three more terms. a, a², a³, a⁴, . . .
a, a², a³, a⁴, . . . a₂ - a₁ = a² - a a₃ - a₂ = a³ - a² a₄ - a₃ = a⁴ - a³ The difference between the successive terms are not same Hence, it is not an A.P.
a, a², a³, a⁴, . . .
See lessa₂ – a₁ = a² – a
a₃ – a₂ = a³ – a²
a₄ – a₃ = a⁴ – a³
The difference between the successive terms are not same Hence, it is not an A.P.
Which of the following are APs ? If they form an AP, find the common difference d and write three more terms. a, 2a, 3a, 4a, . . .
a, 2a, 3a, 4a, . . . a₂ - a₁ = 2a - a = a a₃ - a₂ = 3a - 2a = a a₄ - a₃ = 4a - 3a = a The difference between the successive terms are same Hence, it is an A.P. Common difference = a, next three terms of this AP is as follows: Fifth term a₅ = a₄ + d = 4a + a = 5a Sixth term a₆ = a₅ + d = 5a + a = 6aRead more
a, 2a, 3a, 4a, . . .
See lessa₂ – a₁ = 2a – a = a
a₃ – a₂ = 3a – 2a = a
a₄ – a₃ = 4a – 3a = a
The difference between the successive terms are same Hence, it is an A.P.
Common difference = a, next three terms of this AP is as follows:
Fifth term a₅ = a₄ + d = 4a + a = 5a
Sixth term a₆ = a₅ + d = 5a + a = 6a
Seventh term a₇ = a₆ + d = 6a + a = 7a
Which of the following are APs ? If they form an AP, find the common difference d and write three more terms. 0.2, 0.22, 0.222, 0.2222, . . .
0.2, 0.22, 0.222, 0.2222, . . . a₂ - a₁ = 0.22 - 0.2 = 0.02 a₃ - a₂ = 0.222 - 0.22 = 0.002 a₄ - a₃ = 0.2222 - 0.222 = 0.0002 The difference between the successive terms are not same Hence, it is not an A.P.
0.2, 0.22, 0.222, 0.2222, . . .
See lessa₂ – a₁ = 0.22 – 0.2 = 0.02
a₃ – a₂ = 0.222 – 0.22 = 0.002
a₄ – a₃ = 0.2222 – 0.222 = 0.0002
The difference between the successive terms are not same Hence, it is not an A.P.
Which of the following are APs ? If they form an AP, find the common difference d and write three more terms. 1, 3, 9, 27, . . .
1, 3, 9, 27, . . . a₂ - a₁ = 3 - 1 = 2 a₃ - a₂ = 9 - 3 = 6 a₄ - a₃ = 27 - 9 = 18 The difference between the successive terms are not same Hence, it is not an A.P.
1, 3, 9, 27, . . .
See lessa₂ – a₁ = 3 – 1 = 2
a₃ – a₂ = 9 – 3 = 6
a₄ – a₃ = 27 – 9 = 18
The difference between the successive terms are not same Hence, it is not an A.P.
Which of the following are APs ? If they form an AP, find the common difference d and write three more terms. –1/2, – 1/2, – 1/2, – 1/2, . . .
–1/2, – 1/2, – 1/2, – 1/2, . . . a₂ - a₁ = - 1/2 - (-1/2) = 0 a₃ - a₂ = - 1/2 - (-1/2) = 0 a₄ - a₃ = - 1/2 - (-1/2) = 0 The difference between the successive terms are not same Hence, it is not an A.P. Common difference = 0, next three terms of this AP is as follows: Fifth term a₅ = a₄ + d = - 1/2 +Read more
–1/2, – 1/2, – 1/2, – 1/2, . . .
See lessa₂ – a₁ = – 1/2 – (-1/2) = 0
a₃ – a₂ = – 1/2 – (-1/2) = 0
a₄ – a₃ = – 1/2 – (-1/2) = 0
The difference between the successive terms are not same Hence, it is not an A.P.
Common difference = 0, next three terms of this AP is as follows:
Fifth term a₅ = a₄ + d = – 1/2 + 0 = – 1/2
Sixth term a₆ = a₅ + d = – 1/2 + 0 = – 1/2
Seventh term a₇ = a₆ + d = – 1/2 + 0 = – 1/2.
Which of the following are APs ? If they form an AP, find the common difference d and write three more terms. 0, – 4, – 8, –12, . . .
0, – 4, – 8, –12, . . . a₂ - a₁ = - 4 - 0 = - 4 a₃ - a₂ = - 8 - (-4) = - 4 a₄ - a₃ = - 12 - (-8) = - 4 The difference between the successive terms are same Hence, it is an A.P. Common difference = - 4, next three terms of this AP is as follows: Fifth term a₅ = a₄ + d = - 12 - 4 = - 16 Sixth term a₆Read more
0, – 4, – 8, –12, . . .
See lessa₂ – a₁ = – 4 – 0 = – 4
a₃ – a₂ = – 8 – (-4) = – 4
a₄ – a₃ = – 12 – (-8) = – 4
The difference between the successive terms are same Hence, it is an A.P.
Common difference = – 4, next three terms of this AP is as follows:
Fifth term a₅ = a₄ + d = – 12 – 4 = – 16
Sixth term a₆ = a₅ + d = – 16 – 4 = – 20
Seventh term a₇ = a₆ + d = – 20 – 4 = -24.