1. –1/2, – 1/2, – 1/2, – 1/2, . . . a₂ - a₁ = - 1/2 - (-1/2) = 0 a₃ - a₂ = - 1/2 - (-1/2) = 0 a₄ - a₃ = - 1/2 - (-1/2) = 0 The difference between the successive terms are not same Hence, it is not an A.P. Common difference = 0, next three terms of this AP is as follows: Fifth term a₅ = a₄ + d = - 1/2 +Read more

    –1/2, – 1/2, – 1/2, – 1/2, . . .
    a₂ – a₁ = – 1/2 – (-1/2) = 0
    a₃ – a₂ = – 1/2 – (-1/2) = 0
    a₄ – a₃ = – 1/2 – (-1/2) = 0
    The difference between the successive terms are not same Hence, it is not an A.P.
    Common difference = 0, next three terms of this AP is as follows:
    Fifth term a₅ = a₄ + d = – 1/2 + 0 = – 1/2
    Sixth term a₆ = a₅ + d = – 1/2 + 0 = – 1/2
    Seventh term a₇ = a₆ + d = – 1/2 + 0 = – 1/2.

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    • 2
  2. 0, – 4, – 8, –12, . . . a₂ - a₁ = - 4 - 0 = - 4 a₃ - a₂ = - 8 - (-4) = - 4 a₄ - a₃ = - 12 - (-8) = - 4 The difference between the successive terms are same Hence, it is an A.P. Common difference = - 4, next three terms of this AP is as follows: Fifth term a₅ = a₄ + d = - 12 - 4 = - 16 Sixth term a₆Read more

    0, – 4, – 8, –12, . . .
    a₂ – a₁ = – 4 – 0 = – 4
    a₃ – a₂ = – 8 – (-4) = – 4
    a₄ – a₃ = – 12 – (-8) = – 4
    The difference between the successive terms are same Hence, it is an A.P.
    Common difference = – 4, next three terms of this AP is as follows:
    Fifth term a₅ = a₄ + d = – 12 – 4 = – 16
    Sixth term a₆ = a₅ + d = – 16 – 4 = – 20
    Seventh term a₇ = a₆ + d = – 20 – 4 = -24.

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    • 1