as s αt^3⇒ s = Kt³ velocity, V = ds/dt = 3kt² acceleration, a = dv/dt = 6kt i.e., a α t. ⇒ motion is uniform, accelerated motion, a – t graph is straight-line
as s αt^3⇒ s = Kt³
velocity, V = ds/dt = 3kt²
acceleration, a = dv/dt = 6kt
i.e., a α t.
⇒ motion is uniform, accelerated motion, a – t graph is straight-line
If speed of an object increases with time, its acceleration is positive. (Acceleration is in the direction of motion) and if speed of an object decreases with time its acceleration is negative (Acceleration is opposite to the direction of motion).
If speed of an object increases with time, its acceleration is positive.
(Acceleration is in the direction of motion) and if speed of an object
decreases with time its acceleration is negative (Acceleration is opposite
A sphere of radius ‘r’ is rolling without sliding. What is the ratio of rotational kinetic energy and total kinetic energy associated with sphere
(a) 2/7
(a) 2/7
See lessAn ant is walking on the horizontal surface. The number of degrees of freedom of ant will be
(b) 2
(b) 2
See lessIs the acceleration of a particle in circular motion not always towards the centre. Explain.
No acceleration is towards the centre only in case of uniform circular motion.
No acceleration is towards the centre only in case of uniform circular motion.
See lessA gunman always keep his gun slightly tilted above the line of sight while shooting. Why ?
Because bullet follow Parabolic trajectory under constant downward acceleration.
Because bullet follow Parabolic trajectory under constant downward acceleration.
See lessA person sitting in a train moving at constant velocity throws a ball vertically upwards. How will the ball appear to move to an observer. (i) Sitting inside the train (ii) Standing outside the train
(i) Vertical straight line motion (ii) Parabolic path.
(i) Vertical straight line motion
See less(ii) Parabolic path.
The greatest height to which a man can throw a stone is h. What will be the greatest distance upto which he can throw the stone ?
Maximum height ; H= u²sin²θ/2g = Hₘₐₓ = u²/2g=h(at θ = 90°) Max. Range Rₘₐₓ =u²/g =2h
Maximum height ; H= u²sin²θ/2g
See less= Hₘₐₓ = u²/2g=h(at θ = 90°)
Max. Range Rₘₐₓ =u²/g =2h
What will be the effect on horizontal range of a projectile when its initial velocity is doubled keeping angle of projection same ?
R= u²sin20/g ⇒ R a u² Range becomes four times.
R= u²sin20/g ⇒ R a u²
See lessRange becomes four times.
The displacement of a body is proportional to t³, where t is time elapsed. What is the nature of acceleration -time graph of the body ?
as s αt^3⇒ s = Kt³ velocity, V = ds/dt = 3kt² acceleration, a = dv/dt = 6kt i.e., a α t. ⇒ motion is uniform, accelerated motion, a – t graph is straight-line
as s αt^3⇒ s = Kt³
See lessvelocity, V = ds/dt = 3kt²
acceleration, a = dv/dt = 6kt
i.e., a α t.
⇒ motion is uniform, accelerated motion, a – t graph is straight-line
Can a body have zero velocity and still be accelerating? If yes gives any situation.
Yes, at the highest point of vertical upward motion under gravity.
Yes, at the highest point of vertical upward motion under gravity.
See lessWhat are positive and negative acceleration in straight line motion?
If speed of an object increases with time, its acceleration is positive. (Acceleration is in the direction of motion) and if speed of an object decreases with time its acceleration is negative (Acceleration is opposite to the direction of motion).
If speed of an object increases with time, its acceleration is positive.
(Acceleration is in the direction of motion) and if speed of an object
decreases with time its acceleration is negative (Acceleration is opposite
to the direction of motion).
See less