Φ = Qenc/ε0 where Qenc is the total enclosed charge. Given charges: +5Q,−3Q,+2Q,−4Q Total enclosed charge: Qenc = 5Q−3Q+2Q−4Q = 0 Since the net charge is zero, the outgoing flux is zero. Answer: (b) Zero. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-1/
Φ = Qenc/ε0
where Qenc is the total enclosed charge.
Given charges: +5Q,−3Q,+2Q,−4Q
Total enclosed charge: Qenc = 5Q−3Q+2Q−4Q = 0
Since the net charge is zero, the outgoing flux is zero.
Answer: (b) Zero.
For the system to be in equilibrium, the net force on each charge must be zero. By applying Coulomb’s law and balancing forces symmetrically, the required charge Q at the center must be -q/4 to counteract the repulsion between the two q charges. Answer: (d) -q/4. For more visit here: https://www.tiwRead more
For the system to be in equilibrium, the net force on each charge must be zero. By applying Coulomb’s law and balancing forces symmetrically, the required charge Q at the center must be -q/4 to counteract the repulsion between the two q charges. Answer: (d) -q/4.
The resultant electric field is zero where the fields due to +16q and -4q cancel each other. By using Coulomb’s law and setting the field magnitudes equal, solving for distance gives x = 4L from the charge +16q (toward the right). Answer: (c) 4L. For more visit here: https://www.tiwariacademy.com/ncRead more
The resultant electric field is zero where the fields due to +16q and -4q cancel each other. By using Coulomb’s law and setting the field magnitudes equal, solving for distance gives x = 4L from the charge +16q (toward the right). Answer: (c) 4L.
A vector quantity has both magnitude and direction. Among the given options, electric field (E) is a vector because it has a specific magnitude and direction at every point in space. In contrast, electric charge, electric flux, and electric potential are scalar quantities. Answer: (c) Electric fieldRead more
A vector quantity has both magnitude and direction. Among the given options, electric field (E) is a vector because it has a specific magnitude and direction at every point in space. In contrast, electric charge, electric flux, and electric potential are scalar quantities. Answer: (c) Electric field.
The equation q1 + q2 = 0 signifies an electric dipole because it represents two equal and opposite charges (q1 and 2q) whose sum is zero. An electric dipole consists of such charge pairs separated by a distance, creating an electric field. Answer: (c) Electric dipole. For more visit here: https://wRead more
The equation q1 + q2 = 0 signifies an electric dipole because it represents two equal and opposite charges (q1 and 2q) whose sum is zero. An electric dipole consists of such charge pairs separated by a distance, creating an electric field. Answer: (c) Electric dipole.
Four charges + 5Q,-3Q, + 2Q,-4Q are enclosed inside some surface. What will be the outgoing flux through the surface
Φ = Qenc/ε0 where Qenc is the total enclosed charge. Given charges: +5Q,−3Q,+2Q,−4Q Total enclosed charge: Qenc = 5Q−3Q+2Q−4Q = 0 Since the net charge is zero, the outgoing flux is zero. Answer: (b) Zero. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-1/
Φ = Qenc/ε0
where Qenc is the total enclosed charge.
Given charges: +5Q,−3Q,+2Q,−4Q
Total enclosed charge: Qenc = 5Q−3Q+2Q−4Q = 0
Since the net charge is zero, the outgoing flux is zero.
Answer: (b) Zero.
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A charge Q is placed at the centre of the line joining two charges q and q. The system of three charges will be in equilibrium if Q is
For the system to be in equilibrium, the net force on each charge must be zero. By applying Coulomb’s law and balancing forces symmetrically, the required charge Q at the center must be -q/4 to counteract the repulsion between the two q charges. Answer: (d) -q/4. For more visit here: https://www.tiwRead more
For the system to be in equilibrium, the net force on each charge must be zero. By applying Coulomb’s law and balancing forces symmetrically, the required charge Q at the center must be -q/4 to counteract the repulsion between the two q charges. Answer: (d) -q/4.
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Two point charges + 16 q and – 4 q are located at x = 0 and x = L The location of the point on x-axis at which resultant electric field due to these charges is zero is
The resultant electric field is zero where the fields due to +16q and -4q cancel each other. By using Coulomb’s law and setting the field magnitudes equal, solving for distance gives x = 4L from the charge +16q (toward the right). Answer: (c) 4L. For more visit here: https://www.tiwariacademy.com/ncRead more
The resultant electric field is zero where the fields due to +16q and -4q cancel each other. By using Coulomb’s law and setting the field magnitudes equal, solving for distance gives x = 4L from the charge +16q (toward the right). Answer: (c) 4L.
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Which of the following is a vector quantity?
A vector quantity has both magnitude and direction. Among the given options, electric field (E) is a vector because it has a specific magnitude and direction at every point in space. In contrast, electric charge, electric flux, and electric potential are scalar quantities. Answer: (c) Electric fieldRead more
A vector quantity has both magnitude and direction. Among the given options, electric field (E) is a vector because it has a specific magnitude and direction at every point in space. In contrast, electric charge, electric flux, and electric potential are scalar quantities. Answer: (c) Electric field.
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What does q1 + q2 = 0 signify?
The equation q1 + q2 = 0 signifies an electric dipole because it represents two equal and opposite charges (q1 and 2q) whose sum is zero. An electric dipole consists of such charge pairs separated by a distance, creating an electric field. Answer: (c) Electric dipole. For more visit here: https://wRead more
The equation q1 + q2 = 0 signifies an electric dipole because it represents two equal and opposite charges (q1 and 2q) whose sum is zero. An electric dipole consists of such charge pairs separated by a distance, creating an electric field. Answer: (c) Electric dipole.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-1/