The motion of the center of mass in various binary systems can be described as follows: In binary star systems, two stars orbit around a common center of mass that is closer to the more massive star with their periodic motion influenced by gravitational attraction. In diatomic molecules, the centerRead more
The motion of the center of mass in various binary systems can be described as follows: In binary star systems, two stars orbit around a common center of mass that is closer to the more massive star with their periodic motion influenced by gravitational attraction.
In diatomic molecules, the center of mass lies along the line connecting the two atoms, and its motion changes during vibrations, rotations, or reactions, affecting molecular interactions. In the Earth-Moon system, the center of mass is located inside the Earth, with both bodies orbiting this point, which influences tidal forces and their relative positions.
The center of mass can be found by using the concept of symmetry and geometric principles. For a rectangle, the diagonals cross each other at its center of mass. In the case of a circle or a cylinder, it is located at the middle of the geometric figure. In a solid sphere, it also lies at its center.Read more
The center of mass can be found by using the concept of symmetry and geometric principles. For a rectangle, the diagonals cross each other at its center of mass. In the case of a circle or a cylinder, it is located at the middle of the geometric figure. In a solid sphere, it also lies at its center.
For a triangular plate, it lies at the point of intersection of the medians. In regular polygons, it is at the intersection of diagonals or at the centroid of the shape which is obtained by averaging the coordinates of the vertices.
When a firecracker explodes in the air, its center of mass follows the same trajectory as if no explosion had occurred. The explanation for that lies in the conservation of momentum and the dependence of the motion of the center of mass on external forces such as gravity. In that sense, before the eRead more
When a firecracker explodes in the air, its center of mass follows the same trajectory as if no explosion had occurred. The explanation for that lies in the conservation of momentum and the dependence of the motion of the center of mass on external forces such as gravity. In that sense, before the explosion, the firecracker travels through space like any other projectile along a parabolic path. During and after the explosion, the fragments exert internal forces on one another but do not influence the center of mass. Therefore, the center of mass follows the same parabolic path determined by the initial velocity and gravitational force.
A rigid body is an idealized object whose size and shape are unaffected by external forces. Particles that make up the rigid body can be moving under the effects of external forces, but the relative positions of the particles are preserved. A rigid body does not deform; therefore, all the particlesRead more
A rigid body is an idealized object whose size and shape are unaffected by external forces. Particles that make up the rigid body can be moving under the effects of external forces, but the relative positions of the particles are preserved. A rigid body does not deform; therefore, all the particles of it have the same displacement as the body moves. Similarly, when the rigid body rotates, each particle passes through the same angle about the axis of rotation. While perfect rigidity is impossible, materials such as steel or glass can be approximated as rigid under moderate forces. This simplifies the analysis in physics by assuming no structural deformation under typical conditions.
Discuss the motion of the centre of mass of the following binary systems in nature : (i) Binary stars, (ii) Diatomic molecules, and (iii) Earth-moon systems.
The motion of the center of mass in various binary systems can be described as follows: In binary star systems, two stars orbit around a common center of mass that is closer to the more massive star with their periodic motion influenced by gravitational attraction. In diatomic molecules, the centerRead more
The motion of the center of mass in various binary systems can be described as follows: In binary star systems, two stars orbit around a common center of mass that is closer to the more massive star with their periodic motion influenced by gravitational attraction.
See lessIn diatomic molecules, the center of mass lies along the line connecting the two atoms, and its motion changes during vibrations, rotations, or reactions, affecting molecular interactions. In the Earth-Moon system, the center of mass is located inside the Earth, with both bodies orbiting this point, which influences tidal forces and their relative positions.
How can we locate the centre of mass of rigid bodies of regular geometrical shape and having uniform mass distribution? Give examples.
The center of mass can be found by using the concept of symmetry and geometric principles. For a rectangle, the diagonals cross each other at its center of mass. In the case of a circle or a cylinder, it is located at the middle of the geometric figure. In a solid sphere, it also lies at its center.Read more
The center of mass can be found by using the concept of symmetry and geometric principles. For a rectangle, the diagonals cross each other at its center of mass. In the case of a circle or a cylinder, it is located at the middle of the geometric figure. In a solid sphere, it also lies at its center.
See lessFor a triangular plate, it lies at the point of intersection of the medians. In regular polygons, it is at the intersection of diagonals or at the centroid of the shape which is obtained by averaging the coordinates of the vertices.
Discuss the trajectory of the motion of the centre of mass of fire cracker that explodes in air.
When a firecracker explodes in the air, its center of mass follows the same trajectory as if no explosion had occurred. The explanation for that lies in the conservation of momentum and the dependence of the motion of the center of mass on external forces such as gravity. In that sense, before the eRead more
When a firecracker explodes in the air, its center of mass follows the same trajectory as if no explosion had occurred. The explanation for that lies in the conservation of momentum and the dependence of the motion of the center of mass on external forces such as gravity. In that sense, before the explosion, the firecracker travels through space like any other projectile along a parabolic path. During and after the explosion, the fragments exert internal forces on one another but do not influence the center of mass. Therefore, the center of mass follows the same parabolic path determined by the initial velocity and gravitational force.
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See lessWhat is a rigid body? Give examples.
A rigid body is an idealized object whose size and shape are unaffected by external forces. Particles that make up the rigid body can be moving under the effects of external forces, but the relative positions of the particles are preserved. A rigid body does not deform; therefore, all the particlesRead more
A rigid body is an idealized object whose size and shape are unaffected by external forces. Particles that make up the rigid body can be moving under the effects of external forces, but the relative positions of the particles are preserved. A rigid body does not deform; therefore, all the particles of it have the same displacement as the body moves. Similarly, when the rigid body rotates, each particle passes through the same angle about the axis of rotation. While perfect rigidity is impossible, materials such as steel or glass can be approximated as rigid under moderate forces. This simplifies the analysis in physics by assuming no structural deformation under typical conditions.
See lessHow much will be the weight of a body at the centre of the earth?
Here gₔ = 1% of g = g/100 But gₔ = g(1 - d/R) g/100 = g(1 - d/R) or d/R = 1 - 1/100 = 99/100 d = 99/100 x R = 99/100 x is 6400 = 6336 km
Here gₔ = 1% of g = g/100
See lessBut gₔ = g(1 – d/R)
g/100 = g(1 – d/R)
or d/R = 1 – 1/100 = 99/100
d = 99/100 x R = 99/100 x is 6400 = 6336 km