Focal length of concave lens (OF1), f = −15 cm Image distance, v = −10 cm According to the lens formula, 1/v – 1/u = 1/f 1/u = 1/v – 1/f = -1/10 – 1/(-15) = -1/10 + 1/15 = -5/150 U = -30 cm The negative value of u indicates that the object is placed 30 cm in front of the lens. Focal length of convexRead more
Focal length of concave lens (OF1), f = −15 cm
Image distance, v = −10 cm
According to the lens formula,
1/v – 1/u = 1/f
1/u = 1/v – 1/f = -1/10 – 1/(-15) = -1/10 + 1/15 = -5/150
U = -30 cm
The negative value of u indicates that the object is placed 30 cm in front of the lens.
Focal length of convex mirror, f = +15 cm
Object distance, u = −10 cm
According to the mirror formula,
1/v – 1/u = 1/f
1/v = 1/f – 1/u = 1/15 + 1/10 = 25/150
V = 6 cm
The positive value of v indicates that the image is formed behind the mirror.
Magnification, m = – Image Distance / Object Distance = – v/u = -6/-10 = +0.6
The positive value of magnification indicates that the image formed is virtual and erect.
Focal length of concave lens (OF1), f = −15 cm Image distance, v = −10 cm According to the lens formula, 1/v – 1/u = 1/f 1/u = 1/v – 1/f = -1/10 – 1/(-15) = -1/10 + 1/15 = -5/150 U = -30 cm The negative value of u indicates that the object is placed 30 cm in front of the lens. For more answers visitRead more
Focal length of concave lens (OF1), f = −15 cm
Image distance, v = −10 cm
According to the lens formula,
1/v – 1/u = 1/f
1/u = 1/v – 1/f = -1/10 – 1/(-15) = -1/10 + 1/15 = -5/150
U = -30 cm
The negative value of u indicates that the object is placed 30 cm in front of the lens.
Object distance, u = −25 cm Object height, ho = 5 cm Focal length, f = +10 cm According to the lens formula, 1/v-1/u=1/f 1/v = 1/f + 1/u = 1/10 – 1/25 =15/250 V= 250/15 = 16.66 cm The positive value of v shows that the image is formed at the other side of the lens. Magnification,m = - Image DistanceRead more
Object distance, u = −25 cm
Object height, ho = 5 cm
Focal length, f = +10 cm
According to the lens formula,
1/v-1/u=1/f
1/v = 1/f + 1/u = 1/10 – 1/25 =15/250
V= 250/15 = 16.66 cm
The positive value of v shows that the image is formed at the other side of the lens.
Magnification,m = – Image Distance / Object Distance = – v/u = -16.66 / 25 = -0.66
The negative sign shows that the image is real and formed behind the lens.
Magnification,m = Image height / Object height = H₁ / H0 = H₁=5
H₁ = m X Ho = -0.66 X 5 = -3.3 cm
The negative value of image height indicates that the image formed is inverted.
The position, size, and nature of image are shown in the following ray diagram.
Case I When the upper half of the lens is covered In this case, a ray of light coming from the object will be refracted by the lower half of the lens. These rays meet at the other side of the lens to form the image of the given object, as shown in the following figure. Case II When the lower half ofRead more
Case I
When the upper half of the lens is covered
In this case, a ray of light coming from the object will be refracted by the lower half of
the lens. These rays meet at the other side of the lens to form the image of the given
object, as shown in the following figure.
Case II
When the lower half of the lens is covered
In this case, a ray of light coming from the object is refracted by the upper half of the
lens. These rays meet at the other side of the lens to form the image of the given object,
as shown in the following figure.
(a) Concave (b) Convex (c) Concave Explanation (a) Concave mirror is used in the headlights of a car. This is because concave mirrors can produce powerful parallel beam of light when the light source is placed at their principal focus. (b) Convex mirror is used in side/rear view mirror of a vehicle.Read more
(a) Concave
(b) Convex
(c) Concave
Explanation
(a) Concave mirror is used in the headlights of a car. This is because concave mirrors can
produce powerful parallel beam of light when the light source is placed at their principal
focus.
(b) Convex mirror is used in side/rear view mirror of a vehicle. Convex mirrors give a
virtual, erect, and diminished image of the objects placed in front of it. Because of this,
they have a wide field of view. It enables the driver to see most of the traffic behind
him/her.
(c) Concave mirrors are convergent mirrors. That is why they are used to construct solar
furnaces. Concave mirrors converge the light incident on them at a single point known as
principal focus. Hence, they can be used to produce a large amount of heat at that point.
Explanation (a) Concave mirror is used in the headlights of a car. This is because concave mirrors can produce powerful parallel beam of light when the light source is placed at their principal focus.
Explanation
(a) Concave mirror is used in the headlights of a car. This is because concave mirrors can
produce powerful parallel beam of light when the light source is placed at their principal
focus.
(a) Concave (b) Convex (c) Concave Explanation (a) Concave mirror is used in the headlights of a car. This is because concave mirrors can produce. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-10/
(a) Concave
(b) Convex
(c) Concave
Explanation
(a) Concave mirror is used in the headlights of a car. This is because concave mirrors can
produce.
Range of object distance = 0 cm to15 cm A concave mirror gives an erect image when an object is placed between its pole (P) and the principal focus (F). Hence, to obtain an erect image of an object from a concave mirror of focal length 15 cm, the object must be placed anywhere between the pole and tRead more
Range of object distance = 0 cm to15 cm
A concave mirror gives an erect image when an object is placed between its pole (P) and
the principal focus (F).
Hence, to obtain an erect image of an object from a concave mirror of focal length 15 cm,
the object must be placed anywhere between the pole and the focus. The image formed
will be virtual, erect, and magnified in nature, as shown in the given figure.
(c) A convex lens gives a magnified image of an object when it is placed between the radius of curvature and focal length. Also, magnification is more for convex lenses having shorter focal length. Therefore, for reading small letters, a convex lens of focal length 5 cm should be used. For more answRead more
(c) A convex lens gives a magnified image of an object when it is placed between the
radius of curvature and focal length. Also, magnification is more for convex lenses having
shorter focal length. Therefore, for reading small letters, a convex lens of focal length 5
cm should be used.
(d) A convex mirror always gives a virtual and erect image of smaller size of the object placed in front of it. Similarly, a plane mirror will always give a virtual and erect image of same size as that of the object placed in front of it. Therefore, the given mirror could be either plane or convex.Read more
(d) A convex mirror always gives a virtual and erect image of smaller size of the object
placed in front of it. Similarly, a plane mirror will always give a virtual and erect image of
same size as that of the object placed in front of it. Therefore, the given mirror could be
either plane or convex.
An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. Find the position and nature of the image.
Focal length of concave lens (OF1), f = −15 cm Image distance, v = −10 cm According to the lens formula, 1/v – 1/u = 1/f 1/u = 1/v – 1/f = -1/10 – 1/(-15) = -1/10 + 1/15 = -5/150 U = -30 cm The negative value of u indicates that the object is placed 30 cm in front of the lens. Focal length of convexRead more
Focal length of concave lens (OF1), f = −15 cm
Image distance, v = −10 cm
According to the lens formula,
1/v – 1/u = 1/f
1/u = 1/v – 1/f = -1/10 – 1/(-15) = -1/10 + 1/15 = -5/150
U = -30 cm
The negative value of u indicates that the object is placed 30 cm in front of the lens.
Focal length of convex mirror, f = +15 cm
Object distance, u = −10 cm
According to the mirror formula,
1/v – 1/u = 1/f
1/v = 1/f – 1/u = 1/15 + 1/10 = 25/150
V = 6 cm
The positive value of v indicates that the image is formed behind the mirror.
Magnification, m = – Image Distance / Object Distance = – v/u = -6/-10 = +0.6
The positive value of magnification indicates that the image formed is virtual and erect.
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A concave lens of focal length 15 cm forms an image 10 cm from the lens. How far is the object placed from the lens? Draw the ray diagram.
Focal length of concave lens (OF1), f = −15 cm Image distance, v = −10 cm According to the lens formula, 1/v – 1/u = 1/f 1/u = 1/v – 1/f = -1/10 – 1/(-15) = -1/10 + 1/15 = -5/150 U = -30 cm The negative value of u indicates that the object is placed 30 cm in front of the lens. For more answers visitRead more
Focal length of concave lens (OF1), f = −15 cm
Image distance, v = −10 cm
According to the lens formula,
1/v – 1/u = 1/f
1/u = 1/v – 1/f = -1/10 – 1/(-15) = -1/10 + 1/15 = -5/150
U = -30 cm
The negative value of u indicates that the object is placed 30 cm in front of the lens.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-10/
An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and the nature of the image formed.
Object distance, u = −25 cm Object height, ho = 5 cm Focal length, f = +10 cm According to the lens formula, 1/v-1/u=1/f 1/v = 1/f + 1/u = 1/10 – 1/25 =15/250 V= 250/15 = 16.66 cm The positive value of v shows that the image is formed at the other side of the lens. Magnification,m = - Image DistanceRead more
Object distance, u = −25 cm
Object height, ho = 5 cm
Focal length, f = +10 cm
According to the lens formula,
1/v-1/u=1/f
1/v = 1/f + 1/u = 1/10 – 1/25 =15/250
V= 250/15 = 16.66 cm
The positive value of v shows that the image is formed at the other side of the lens.
Magnification,m = – Image Distance / Object Distance = – v/u = -16.66 / 25 = -0.66
The negative sign shows that the image is real and formed behind the lens.
Magnification,m = Image height / Object height = H₁ / H0 = H₁=5
H₁ = m X Ho = -0.66 X 5 = -3.3 cm
The negative value of image height indicates that the image formed is inverted.
The position, size, and nature of image are shown in the following ray diagram.
For more answers visit to website:
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One-half of a convex lens is covered with a black paper. Will this lens produce a complete image of the object? Verify your answer experimentally. Explain your observations.
Case I When the upper half of the lens is covered In this case, a ray of light coming from the object will be refracted by the lower half of the lens. These rays meet at the other side of the lens to form the image of the given object, as shown in the following figure. Case II When the lower half ofRead more
Case I
When the upper half of the lens is covered
In this case, a ray of light coming from the object will be refracted by the lower half of
the lens. These rays meet at the other side of the lens to form the image of the given
object, as shown in the following figure.
Case II
See lessWhen the lower half of the lens is covered
In this case, a ray of light coming from the object is refracted by the upper half of the
lens. These rays meet at the other side of the lens to form the image of the given object,
as shown in the following figure.
Name the type of mirror used in the following situations.
(a) Concave (b) Convex (c) Concave Explanation (a) Concave mirror is used in the headlights of a car. This is because concave mirrors can produce powerful parallel beam of light when the light source is placed at their principal focus. (b) Convex mirror is used in side/rear view mirror of a vehicle.Read more
(a) Concave
(b) Convex
(c) Concave
Explanation
(a) Concave mirror is used in the headlights of a car. This is because concave mirrors can
produce powerful parallel beam of light when the light source is placed at their principal
focus.
(b) Convex mirror is used in side/rear view mirror of a vehicle. Convex mirrors give a
virtual, erect, and diminished image of the objects placed in front of it. Because of this,
they have a wide field of view. It enables the driver to see most of the traffic behind
him/her.
(c) Concave mirrors are convergent mirrors. That is why they are used to construct solar
furnaces. Concave mirrors converge the light incident on them at a single point known as
principal focus. Hence, they can be used to produce a large amount of heat at that point.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-10/
Name the type of mirror used in the following situations.
Explanation (a) Concave mirror is used in the headlights of a car. This is because concave mirrors can produce powerful parallel beam of light when the light source is placed at their principal focus.
Explanation
See less(a) Concave mirror is used in the headlights of a car. This is because concave mirrors can
produce powerful parallel beam of light when the light source is placed at their principal
focus.
Name the type of mirror used in the following situations.
(a) Concave (b) Convex (c) Concave Explanation (a) Concave mirror is used in the headlights of a car. This is because concave mirrors can produce. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-10/
(a) Concave
(b) Convex
(c) Concave
Explanation
(a) Concave mirror is used in the headlights of a car. This is because concave mirrors can
produce.
For more answers visit to website:
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We wish to obtain an erect image of an object, using a concave mirror of focal length 15 cm. What should be the range of distance of the object from the mirror? What is the nature of the image? Is the image larger or smaller than the object? Draw a ray diagram to show the image formation in this case.
Range of object distance = 0 cm to15 cm A concave mirror gives an erect image when an object is placed between its pole (P) and the principal focus (F). Hence, to obtain an erect image of an object from a concave mirror of focal length 15 cm, the object must be placed anywhere between the pole and tRead more
Range of object distance = 0 cm to15 cm
A concave mirror gives an erect image when an object is placed between its pole (P) and
the principal focus (F).
Hence, to obtain an erect image of an object from a concave mirror of focal length 15 cm,
the object must be placed anywhere between the pole and the focus. The image formed
will be virtual, erect, and magnified in nature, as shown in the given figure.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-10/
Which of the following lenses would you prefer to use while reading small letters found in a dictionary?
(c) A convex lens gives a magnified image of an object when it is placed between the radius of curvature and focal length. Also, magnification is more for convex lenses having shorter focal length. Therefore, for reading small letters, a convex lens of focal length 5 cm should be used. For more answRead more
(c) A convex lens gives a magnified image of an object when it is placed between the
radius of curvature and focal length. Also, magnification is more for convex lenses having
shorter focal length. Therefore, for reading small letters, a convex lens of focal length 5
cm should be used.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-10/
No matter how far you stand from a mirror, your image appears erect. The mirror is likely to be
(d) A convex mirror always gives a virtual and erect image of smaller size of the object placed in front of it. Similarly, a plane mirror will always give a virtual and erect image of same size as that of the object placed in front of it. Therefore, the given mirror could be either plane or convex.Read more
(d) A convex mirror always gives a virtual and erect image of smaller size of the object
placed in front of it. Similarly, a plane mirror will always give a virtual and erect image of
same size as that of the object placed in front of it. Therefore, the given mirror could be
either plane or convex.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-10/