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  1. Asked: In:

    Find the value of k, if x = 2, y = 1 is a solution of the equation 2x + 3y = k.

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    Given equation: x = 2, y = 1 In 2x + 3y = k, putting x = 2 and y = 1, we have, 2x × 2 + 3 × 1 = k ⇒ k = 7 Hence, the value of k is 7.

    Given equation: x = 2, y = 1
    In 2x + 3y = k, putting x = 2 and y = 1, we have,
    2x × 2 + 3 × 1 = k
    ⇒ k = 7
    Hence, the value of k is 7.

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  2. Asked: In:

    Draw the graph of each of the following linear equations in two variables: x + y = 4

    ballu43

    (i) x + y = 4 ⇒ y = 4 - x Putting x = 0, we have, y = 4 - 0 = 4 Putting x = 1, we have, y = 4 - 1 = 3 Hence, A(0, 4) and B(1, 3) are the solutions of the equation.

    (i) x + y = 4
    ⇒ y = 4 – x
    Putting x = 0, we have, y = 4 – 0 = 4
    Putting x = 1, we have, y = 4 – 1 = 3
    Hence, A(0, 4) and B(1, 3) are the solutions of the equation.

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  3. Asked: In:

    Draw the graph of each of the following linear equations in two variables: x – y = 2.

    ballu43

    (ii) x - y = 2 ⇒ y = x - 2 Putting x = 0, we have, y = 0 - 2 = -2 Putting x = 1, we have, y = 1 - 2 = -1 Hence, C(O,-2) and D(1,-1) are the solutions of the equation.

    (ii) x – y = 2
    ⇒ y = x – 2
    Putting x = 0, we have, y = 0 – 2 = -2
    Putting x = 1, we have, y = 1 – 2 = -1
    Hence, C(O,-2) and D(1,-1) are the solutions of the equation.

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  4. Asked: In:

    Draw the graph of each of the following linear equations in two variables: y = 3x

    ballu43

    (iii) y = 3x Putting x = 0, we have, y = 3 × 0 = 0 Putting x = 1, we have, y = 3 × 1 = 3 Hence, E(0, 0) and B(1,3) are the solutions of the equation.

    (iii) y = 3x
    Putting x = 0, we have, y = 3 × 0 = 0
    Putting x = 1, we have, y = 3 × 1 = 3
    Hence, E(0, 0) and B(1,3) are the solutions of the equation.

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