Radius of sphere r = 5.6 cm Surface area of sphere = 4πr² = 4 × 22/7 × 5.6 × 5.6 = 4 × 22 × 0.8 × 5.6 = 394.24 cm² Hence, the surface area of sphere is 394.24 cm².
Radius of sphere r = 5.6 cm
Surface area of sphere = 4πr²
= 4 × 22/7 × 5.6 × 5.6 = 4 × 22 × 0.8 × 5.6 = 394.24 cm²
Hence, the surface area of sphere is 394.24 cm².
Radius of sphere r = 21/2 = 10.5 cm Surface area of sphere = 4πr² = 4 × 22/7 × 10.5 × 10.5 = 4 × 22 × 4.5 × 10.5 = 1386 cm² Hence, the surface area of sphere is 1386 cm².
Radius of sphere r = 21/2 = 10.5 cm
Surface area of sphere = 4πr²
= 4 × 22/7 × 10.5 × 10.5 = 4 × 22 × 4.5 × 10.5 = 1386 cm²
Hence, the surface area of sphere is 1386 cm².
Radius of sphere r = 3.5/2 = 1.75 cm Surface area of sphere = 4πr² = 4 × 22/7 × 1.75 × 1.75 = 4 × 22 × 0.25 × 1.75 = 38.50 cm² Hence, the surface area of sphere is 38.5 cm².
Radius of sphere r = 3.5/2 = 1.75 cm
Surface area of sphere = 4πr²
= 4 × 22/7 × 1.75 × 1.75 = 4 × 22 × 0.25 × 1.75
= 38.50 cm²
Hence, the surface area of sphere is 38.5 cm².
Internal radius of hemispherical bowl r = 10.5/2 = 5.25 cm Inner surface area of hemispherical bowl = 2πr² = 2 × 22/7 × 5.25 × 5.25 = 2 × 22 × 0.75 × 5.25 = 173.25 cm² Cost of tin-plating the rate of Rs 16 per 100 cm² = Rs 173. 25 × 16/100 = Rs 27.72 Hence, the cost of tin- plating inside at the ratRead more
Internal radius of hemispherical bowl r = 10.5/2 = 5.25 cm
Inner surface area of hemispherical bowl = 2πr²
= 2 × 22/7 × 5.25 × 5.25
= 2 × 22 × 0.75 × 5.25
= 173.25 cm²
Cost of tin-plating the rate of Rs 16 per 100 cm²
= Rs 173. 25 × 16/100 = Rs 27.72
Hence, the cost of tin- plating inside at the rate of Rs 16 per 100 cm² is Rs 27.72.
Find the surface area of a sphere of diameter: 14 cm.
Radius of sphere r = 14/2 = 7 cm Surface area of sphere = 4πr² = 4 × 22/7 × 7 × 7 = 4 × 22 × 7 = 616 cm² Hence, the surface area of sphere is 616 cm².
Radius of sphere r = 14/2 = 7 cm
See lessSurface area of sphere = 4πr²
= 4 × 22/7 × 7 × 7 = 4 × 22 × 7 = 616 cm²
Hence, the surface area of sphere is 616 cm².
Find the surface area of a sphere of radius: 5.6 cm
Radius of sphere r = 5.6 cm Surface area of sphere = 4πr² = 4 × 22/7 × 5.6 × 5.6 = 4 × 22 × 0.8 × 5.6 = 394.24 cm² Hence, the surface area of sphere is 394.24 cm².
Radius of sphere r = 5.6 cm
See lessSurface area of sphere = 4πr²
= 4 × 22/7 × 5.6 × 5.6 = 4 × 22 × 0.8 × 5.6 = 394.24 cm²
Hence, the surface area of sphere is 394.24 cm².
Find the surface area of a sphere of diameter: 21 cm.
Radius of sphere r = 21/2 = 10.5 cm Surface area of sphere = 4πr² = 4 × 22/7 × 10.5 × 10.5 = 4 × 22 × 4.5 × 10.5 = 1386 cm² Hence, the surface area of sphere is 1386 cm².
Radius of sphere r = 21/2 = 10.5 cm
See lessSurface area of sphere = 4πr²
= 4 × 22/7 × 10.5 × 10.5 = 4 × 22 × 4.5 × 10.5 = 1386 cm²
Hence, the surface area of sphere is 1386 cm².
Find the surface area of a sphere of diameter: 3.5 m.
Radius of sphere r = 3.5/2 = 1.75 cm Surface area of sphere = 4πr² = 4 × 22/7 × 1.75 × 1.75 = 4 × 22 × 0.25 × 1.75 = 38.50 cm² Hence, the surface area of sphere is 38.5 cm².
Radius of sphere r = 3.5/2 = 1.75 cm
See lessSurface area of sphere = 4πr²
= 4 × 22/7 × 1.75 × 1.75 = 4 × 22 × 0.25 × 1.75
= 38.50 cm²
Hence, the surface area of sphere is 38.5 cm².
A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of Rs 16 per 100 cm².
Internal radius of hemispherical bowl r = 10.5/2 = 5.25 cm Inner surface area of hemispherical bowl = 2πr² = 2 × 22/7 × 5.25 × 5.25 = 2 × 22 × 0.75 × 5.25 = 173.25 cm² Cost of tin-plating the rate of Rs 16 per 100 cm² = Rs 173. 25 × 16/100 = Rs 27.72 Hence, the cost of tin- plating inside at the ratRead more
Internal radius of hemispherical bowl r = 10.5/2 = 5.25 cm
See lessInner surface area of hemispherical bowl = 2πr²
= 2 × 22/7 × 5.25 × 5.25
= 2 × 22 × 0.75 × 5.25
= 173.25 cm²
Cost of tin-plating the rate of Rs 16 per 100 cm²
= Rs 173. 25 × 16/100 = Rs 27.72
Hence, the cost of tin- plating inside at the rate of Rs 16 per 100 cm² is Rs 27.72.