1. In rolling motion, the total kinetic energy is the sum of translational 1/2𝑀𝑣² and rotational 1/2𝐼𝜔² kinetic energy. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6. System of particles and Rotational Motion. Give answer according to your understanding. For more pleasRead more

    In rolling motion, the total kinetic energy is the sum of translational 1/2𝑀𝑣² and rotational 1/2𝐼𝜔² kinetic energy. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6. System of particles and Rotational Motion. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-6/

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  2. For uniform angular velocity, there is no change in 𝜔 over time, so angular acceleration 𝛼 and torque 𝜏 are both zero. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6. System of particle and Rotational Motion Give answer according to your understanding. For more pleasRead more

    For uniform angular velocity, there is no change in 𝜔 over time, so angular acceleration 𝛼 and torque 𝜏 are both zero. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6. System of particle and Rotational Motion Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-6/

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  3. The center of mass of a uniform semicircular ring lies at a distance 2𝑅/𝜋 along the axis of symmetry, derived using integration over the arc. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6. System of particle and Rotational motion. Give answer according to your underRead more

    The center of mass of a uniform semicircular ring lies at a distance 2𝑅/𝜋 along the axis of symmetry, derived using integration over the arc.
    This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6. System of particle and Rotational motion. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-6/

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  4. Step1. Calculate the total apples bought by the first businessman: Apples bought by first businessman =14 × 425 = 5950 Step2. Calculate the total apples bought by the second businessman: Apples bought by second businessman = 21 × 295 = 6195 Step3. Find the difference between the apples bought by theRead more

    Step1. Calculate the total apples bought by the first businessman:
    Apples bought by first businessman =14 × 425 = 5950
    Step2. Calculate the total apples bought by the second businessman:
    Apples bought by second businessman = 21 × 295 = 6195
    Step3. Find the difference between the apples bought by the second businessman and the first:
    Difference = 6195 − 5950 = 245
    Hence, the second businessman buys 245 more apples than the first businessman.

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    https://www.tiwariacademy.com/ncert-solutions/class-4/maths/

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