Choice (a) is correct. We know that if ⁿCᵣ = ⁿCₛ, then r = s or r + s = n Given, ⁿC₁₂ = ⁿC₈ n = 12 + 8 ⇒ n = 20 This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding. For more please visit here: httRead more
Choice (a) is correct.
We know that if ⁿCᵣ = ⁿCₛ, then r = s or r + s = n
Given, ⁿC₁₂ = ⁿC₈
n = 12 + 8 ⇒ n = 20
This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
Choice (b) is correct. Putting n = 11 and r = 3 in n!/(n - r)! r! , we get 11! / (11 - 3)! 3! = 11 × 10 × 9 × 8!/ 8! × 3 × 2 × 1 = 11 × 5 × 3 = 165 This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understandiRead more
Choice (b) is correct.
Putting n = 11 and r = 3 in n!/(n – r)! r! , we get
11! / (11 – 3)! 3! = 11 × 10 × 9 × 8!/ 8! × 3 × 2 × 1 = 11 × 5 × 3 = 165
This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
Choice (c) is correct. Given, ∣ x -1 ∣ > 5 ⇒ (x - 1) 5 ⇒ x 5 + 1 ⇒ x 6 ⇒ x ∈ ( -∞, -4) ∪ (6, ∞) This question related to Chapter 5 maths Class 11th NCERT. From the Chapter 5: Linear Inequalities. Give answer according to your understanding. For more please visit here: https://www.tiwariacademRead more
Choice (c) is correct.
Given, ∣ x -1 ∣ > 5
⇒ (x – 1) 5
⇒ x 5 + 1 ⇒ x 6
⇒ x ∈ ( -∞, -4) ∪ (6, ∞)
This question related to Chapter 5 maths Class 11th NCERT. From the Chapter 5: Linear Inequalities. Give answer according to your understanding.
Choice (b) is correct. Given ∣ x ∣ < 3 ⇒ -3 < x < 3 This question related to Chapter 5 maths Class 11th NCERT. From the Chapter 5: Linear Inequalities. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chaRead more
Choice (b) is correct.
Given ∣ x ∣ < 3 ⇒ -3 < x < 3
This question related to Chapter 5 maths Class 11th NCERT. From the Chapter 5: Linear Inequalities. Give answer according to your understanding.
Choice (c) is correct. Let x cm be the breadth of the rectangle. Length of the rectangle = 3x cm and perimeter of the rectangle = 2 ( length + breadth) = 2(3x + x) = 8x cm Given, minimum perimeter = 160 cm 8x ≥ 160 ⇒ x ≥ 20 Hence, breadth ≥ 20 cm. This question related to Chapter 5 maths Class 11tRead more
Choice (c) is correct.
Let x cm be the breadth of the rectangle.
Length of the rectangle = 3x cm
and perimeter of the rectangle = 2 ( length + breadth) = 2(3x + x) = 8x cm
Given, minimum perimeter = 160 cm
8x ≥ 160 ⇒ x ≥ 20
Hence, breadth ≥ 20 cm.
This question related to Chapter 5 maths Class 11th NCERT. From the Chapter 5: Linear Inequalities. Give answer according to your understanding.
If ⁿC₁₂ = ⁿC₈, then the value of n is :
Choice (a) is correct. We know that if ⁿCᵣ = ⁿCₛ, then r = s or r + s = n Given, ⁿC₁₂ = ⁿC₈ n = 12 + 8 ⇒ n = 20 This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding. For more please visit here: httRead more
Choice (a) is correct.
We know that if ⁿCᵣ = ⁿCₛ, then r = s or r + s = n
Given, ⁿC₁₂ = ⁿC₈
n = 12 + 8 ⇒ n = 20
This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-6
What is the value of n!/(n – r)! r! if n = 11 and r = 3?
Choice (b) is correct. Putting n = 11 and r = 3 in n!/(n - r)! r! , we get 11! / (11 - 3)! 3! = 11 × 10 × 9 × 8!/ 8! × 3 × 2 × 1 = 11 × 5 × 3 = 165 This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understandiRead more
Choice (b) is correct.
Putting n = 11 and r = 3 in n!/(n – r)! r! , we get
11! / (11 – 3)! 3! = 11 × 10 × 9 × 8!/ 8! × 3 × 2 × 1 = 11 × 5 × 3 = 165
This question related to Chapter 6 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-6
If ∣ x – 1 ∣ > 5, then
Choice (c) is correct. Given, ∣ x -1 ∣ > 5 ⇒ (x - 1) 5 ⇒ x 5 + 1 ⇒ x 6 ⇒ x ∈ ( -∞, -4) ∪ (6, ∞) This question related to Chapter 5 maths Class 11th NCERT. From the Chapter 5: Linear Inequalities. Give answer according to your understanding. For more please visit here: https://www.tiwariacademRead more
Choice (c) is correct.
Given, ∣ x -1 ∣ > 5
⇒ (x – 1) 5
⇒ x 5 + 1 ⇒ x 6
⇒ x ∈ ( -∞, -4) ∪ (6, ∞)
This question related to Chapter 5 maths Class 11th NCERT. From the Chapter 5: Linear Inequalities. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-5
If x is a real number and ∣ x ∣ less than 3 then
Choice (b) is correct. Given ∣ x ∣ < 3 ⇒ -3 < x < 3 This question related to Chapter 5 maths Class 11th NCERT. From the Chapter 5: Linear Inequalities. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chaRead more
Choice (b) is correct.
Given ∣ x ∣ < 3 ⇒ -3 < x < 3
This question related to Chapter 5 maths Class 11th NCERT. From the Chapter 5: Linear Inequalities. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-5
The length of a rectangle is three times the breadth. If the minimum perimeter of the rectangle is 160 cm, then
Choice (c) is correct. Let x cm be the breadth of the rectangle. Length of the rectangle = 3x cm and perimeter of the rectangle = 2 ( length + breadth) = 2(3x + x) = 8x cm Given, minimum perimeter = 160 cm 8x ≥ 160 ⇒ x ≥ 20 Hence, breadth ≥ 20 cm. This question related to Chapter 5 maths Class 11tRead more
Choice (c) is correct.
Let x cm be the breadth of the rectangle.
Length of the rectangle = 3x cm
and perimeter of the rectangle = 2 ( length + breadth) = 2(3x + x) = 8x cm
Given, minimum perimeter = 160 cm
8x ≥ 160 ⇒ x ≥ 20
Hence, breadth ≥ 20 cm.
This question related to Chapter 5 maths Class 11th NCERT. From the Chapter 5: Linear Inequalities. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-5