Length of one edge of cube = l Number of edges in a cube = 12 Therefore, total length = 12xl = 12l https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
Length of one edge of cube = l
Number of edges in a cube = 12
Therefore, total length = 12xl = 12l
Side of equilateral triangle = l Therefore, Perimeter of equilateral triangle = 3 x side = 3l https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
Side of equilateral triangle = l
Therefore, Perimeter of equilateral triangle = 3 x side = 3l
Number of oranges in one box = x Number of boxes = 2 Therefore, total number of oranges in boxes = 2x Remaining oranges = 10 Thus, number of oranges = 2x+10 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
Number of oranges in one box = x
Number of boxes = 2
Therefore, total number of oranges in boxes = 2x
Remaining oranges = 10
Thus, number of oranges = 2x+10
Number of laddus gave away = l Number of laddus remaining = 5 Total number of laddus = (l+5) https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
Number of laddus gave away = l
Number of laddus remaining = 5
Total number of laddus = (l+5)
A cube is a three-dimensional figure. It has six faces and all of them are identical squares. The length of an edge of the cube is given by l. find the formula for the total length of the edges of a cube.
Length of one edge of cube = l Number of edges in a cube = 12 Therefore, total length = 12xl = 12l https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
Length of one edge of cube = l
Number of edges in a cube = 12
Therefore, total length = 12xl = 12l
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
See lessThe side of a regular hexagon is denoted by l. Express the perimeter of the hexagon using l. (Hint: A regular hexagon has all its six sides in length)
Side of hexagon = l Therefore, Perimeter of Hexagon = 6 x side = 6l https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
Side of hexagon = l
Therefore, Perimeter of Hexagon = 6 x side = 6l
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
See lessThe side of an equilateral triangle is shown by l Express the perimeter of the equilateral triangle using l.
Side of equilateral triangle = l Therefore, Perimeter of equilateral triangle = 3 x side = 3l https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
Side of equilateral triangle = l
Therefore, Perimeter of equilateral triangle = 3 x side = 3l
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
See lessOranges are to be transferred from larger boxes into smaller boxes. When a large box is emptied, the oranges from it fill two smaller boxes and still 10 oranges remain outside. If the number of oranges in a small box are taken to be x, what is the number of oranges in the larger box?
Number of oranges in one box = x Number of boxes = 2 Therefore, total number of oranges in boxes = 2x Remaining oranges = 10 Thus, number of oranges = 2x+10 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
Number of oranges in one box = x
Number of boxes = 2
Therefore, total number of oranges in boxes = 2x
Remaining oranges = 10
Thus, number of oranges = 2x+10
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
See lessMother has made laddus. She gives some laddus to guests and family members; still 5 laddus remain. If the number of laddus mother gave away, l is how many laddus did she make?
Number of laddus gave away = l Number of laddus remaining = 5 Total number of laddus = (l+5) https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
Number of laddus gave away = l
Number of laddus remaining = 5
Total number of laddus = (l+5)
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
See less