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z+1→Addition y+17→Addition https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
z+1→Addition y+17→Addition
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
(c) and (d) https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
(c) and (d)
(a) (8 x 5) – 7 (b) (8 + 5) – 7 (c) (8 x 7) – 5 (d) (8 + 7) – 5 (e) 5 x (7 + 8) (f) 5 + (7 x 8) (g) 5 + (8 – 7) (h) 5 – (7 + 8) https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
(a) (8 x 5) – 7 (b) (8 + 5) – 7 (c) (8 x 7) – 5 (d) (8 + 7) – 5 (e) 5 x (7 + 8) (f) 5 + (7 x 8) (g) 5 + (8 – 7) (h) 5 – (7 + 8)
(a+b) + c = a+(b+c) https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
(a+b) + c = a+(b+c)
Since, length of diameter is double the length of radius. Therefore, d=2r https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
Since, length of diameter is double the length of radius. Therefore, d=2r
Identify the operations (addition, subtraction, division, multiplication) in forming the following expressions and tell how the expressions have been formed: a+z, z-1, y+17, y-17
z+1→Addition y+17→Addition https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
z+1→Addition
y+17→Addition
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
See lessWhich out of the following are expressions with numbers only: (a) Y+3 (b) (7×20)-8z (c) 5(21-7) +7×2 (d) 5 (e) 3x (f) 5-5n (g) (7×20)-(5×10)-45+p
(c) and (d) https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
(c) and (d)
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
See lessMake up as many expressions with numbers (no variables) as you can from three numbers 5, 7 and 8. Every number should be used not more than once. Use only addition, subtraction and multiplication. (Hint: Three possible expressions are 5 + (8 – 7), 5 – (8 – 7), (5 x 8) + 7 make the other expressions)
(a) (8 x 5) – 7 (b) (8 + 5) – 7 (c) (8 x 7) – 5 (d) (8 + 7) – 5 (e) 5 x (7 + 8) (f) 5 + (7 x 8) (g) 5 + (8 – 7) (h) 5 – (7 + 8) https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
(a) (8 x 5) – 7
(b) (8 + 5) – 7
(c) (8 x 7) – 5
(d) (8 + 7) – 5
(e) 5 x (7 + 8)
(f) 5 + (7 x 8)
(g) 5 + (8 – 7)
(h) 5 – (7 + 8)
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
See lessTo find sum of three numbers 14, 27 and 13. We can have two ways. (a) We may first add 14 and 27 to get 41 and then add 13 to it to get the total sum 54, or (b) We may add 27 and 13 to get 40 and then add 14 to get the sum 54. Thus (14 + 27) + 13 = 14 + (27 + 13) This can be done for any three numbers. This property is known as the associativity of addition of numbers. Express this property which we have already studied in the chapter on Whole Numbers, in a general way, by using variables and ,ab . c
(a+b) + c = a+(b+c) https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
(a+b) + c = a+(b+c)
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
See lessThe diameter of a circle is a line, which joins two points on the circle and also passes through the centre of the circle. (In the adjoining figure AB is a diameter of the circle; C is its centre). Express the diameter of the circle (d) in terms of its radius (r).
Since, length of diameter is double the length of radius. Therefore, d=2r https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
Since, length of diameter is double the length of radius.
Therefore, d=2r
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-11/
See less