(a) Area of region = 100 cm x 144 cm = 14400 cm² Area of one tile = 5 cm x 12 cm = 60 cm² Number of tiles = Area of region/Area of one tile 14400/60 = 240 Thus, 240 tiles are required. (b) Area of region = 70 cm x 36 cm = 2520 cm² Area of one tile = 5 cm x 12 cm = 60 cm² Number of tiles = Area of reRead more
(a) Area of region = 100 cm x 144 cm = 14400 cm²
Area of one tile = 5 cm x 12 cm = 60 cm²
Number of tiles = Area of region/Area of one tile
14400/60 = 240
Thus, 240 tiles are required.
(b) Area of region = 70 cm x 36 cm = 2520 cm²
Area of one tile = 5 cm x 12 cm = 60 cm²
Number of tiles = Area of region/Area of one tile
=2520/60=42
Thus, 42 tiles are required.
Side of square bed = 1 m Area of square bed = side x side = 1 m x 1 m = 1 m² ∴ Area of 5 square beds = 1 x 5 = 5 m² Now, Length of land = 5 m Breadth of land = 4 m ∴ Area of land = length x breadth = 5 m x 4 m = 20 m² Area of remaining part = Area of land – Area of 5 flower beds = 20 m² – 5 m² = 15Read more
Side of square bed = 1 m
Area of square bed = side x side = 1 m x 1 m = 1 m²
∴ Area of 5 square beds = 1 x 5 = 5 m²
Now, Length of land = 5 m
Breadth of land = 4 m
∴ Area of land = length x breadth
= 5 m x 4 m = 20 m²
Area of remaining part = Area of land – Area of 5 flower beds
= 20 m² – 5 m² = 15 m²
Length of floor = 5 m and breadth of floor = 4 m Area of floor = length x breadth = 5 m x 4 m = 20 m² Now, Side of square carpet = 3 m Area of square carpet = side x side = 3 x 3 = 9 m² Area of floor that is not carpeted = 20 m² – 9 m² = 11 m² https://www.tiwariacademy.com/ncert-solutions/class-6/maRead more
Length of floor = 5 m and breadth of floor = 4 m
Area of floor = length x breadth
= 5 m x 4 m = 20 m²
Now, Side of square carpet = 3 m
Area of square carpet = side x side = 3 x 3 = 9 m²
Area of floor that is not carpeted = 20 m² – 9 m² = 11 m²
Length of room = 4 m Breadth of room = 3 m 50 cm = 3.50 m Area of carpet = length x breadth = 4 x 3.50 = 14m² https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Length of room = 4 m
Breadth of room = 3 m 50 cm = 3.50 m
Area of carpet = length x breadth = 4 x 3.50 = 14m²
Length of table = 2 m Breadth of table = 1 m 50 cm = 1.50 m Area of table = length x breadth = 2 m x 1.50 m = 3 m² https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Length of table = 2 m
Breadth of table = 1 m 50 cm = 1.50 m
Area of table = length x breadth
= 2 m x 1.50 m = 3 m²
Length of land = 500 m and Breadth of land = 200 m Area of land = length x breadth = 500 m x 200 m = 1,00,000 m² ∴ Cost of tilling 100 sq. m of land = ₹ 8 ∴ Cost of tilling 1,00,000 sq. m of land = 8x100000/100 = ₹ 8000 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Length of land = 500 m and Breadth of land = 200 m
Area of land = length x breadth = 500 m x 200 m = 1,00,000 m²
∴ Cost of tilling 100 sq. m of land = ₹ 8
∴ Cost of tilling 1,00,000 sq. m of land = 8×100000/100 = ₹ 8000
Length of rectangle = 50 m and Area of rectangle = 300 m² Since, Area of rectangle = length x breadth Therefore, Breadth = Area of rectangle/Length = 300/50 = 6 m Thus, the breadth of the garden is 6 m. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Length of rectangle = 50 m and Area of rectangle = 300 m²
Since, Area of rectangle = length x breadth
Therefore, Breadth = Area of rectangle/Length = 300/50 = 6 m
Thus, the breadth of the garden is 6 m.
(a) Area of rectangle = length x breadth = 9 m x 6 m = 54 m² (b) Area of rectangle = length x breadth= 3 m x 17 m = 51 m² (c) Area of rectangle = length x breadth= 4 m x 14 m = 56 m² Thus, the rectangle (c) has largest area, and rectangle (b) has smallest area. https://www.tiwariacademy.com/ncert-soRead more
(a) Area of rectangle = length x breadth = 9 m x 6 m = 54 m²
(b) Area of rectangle = length x breadth= 3 m x 17 m = 51 m²
(c) Area of rectangle = length x breadth= 4 m x 14 m = 56 m²
Thus, the rectangle (c) has largest area, and rectangle (b) has smallest area.
(a) Area of square = side x side = 10 cm x 10 cm = 100 cm² (b) Area of square = side x side = 14 cm x 14 cm = 196 cm² (c) Area of square = side x side = 5 m x 5 m = 25 m² https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
(a) Area of square = side x side = 10 cm x 10 cm = 100 cm²
(b) Area of square = side x side = 14 cm x 14 cm = 196 cm²
(c) Area of square = side x side = 5 m x 5 m = 25 m²
(a) Area of rectangle = length x breadth = 3 cm x 4 cm = 12 cm² (b) Area of rectangle = length x breadth = 12 m x 21 m = 252 m² (c) Area of rectangle = length x breadth = 2 km x 3 km = 6 km² (d) Area of rectangle = length x breadth = 2 m x 70 cm = 2 m x 0.7 m = 1.4 m² https://www.tiwariacademy.com/nRead more
(a) Area of rectangle = length x breadth
= 3 cm x 4 cm = 12 cm²
(b) Area of rectangle = length x breadth
= 12 m x 21 m = 252 m²
(c) Area of rectangle = length x breadth
= 2 km x 3 km = 6 km²
(d) Area of rectangle = length x breadth
= 2 m x 70 cm = 2 m x 0.7 m = 1.4 m²
How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively? (a) 100 cm and 144 cm (b) 70 cm and 36 cm
(a) Area of region = 100 cm x 144 cm = 14400 cm² Area of one tile = 5 cm x 12 cm = 60 cm² Number of tiles = Area of region/Area of one tile 14400/60 = 240 Thus, 240 tiles are required. (b) Area of region = 70 cm x 36 cm = 2520 cm² Area of one tile = 5 cm x 12 cm = 60 cm² Number of tiles = Area of reRead more
(a) Area of region = 100 cm x 144 cm = 14400 cm²
Area of one tile = 5 cm x 12 cm = 60 cm²
Number of tiles = Area of region/Area of one tile
14400/60 = 240
Thus, 240 tiles are required.
(b) Area of region = 70 cm x 36 cm = 2520 cm²
Area of one tile = 5 cm x 12 cm = 60 cm²
Number of tiles = Area of region/Area of one tile
=2520/60=42
Thus, 42 tiles are required.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessFive square flower beds each of sides 1 m are dug on a piece of land 5 m long and 4 m wide. What is the area of the remaining part of the land?
Side of square bed = 1 m Area of square bed = side x side = 1 m x 1 m = 1 m² ∴ Area of 5 square beds = 1 x 5 = 5 m² Now, Length of land = 5 m Breadth of land = 4 m ∴ Area of land = length x breadth = 5 m x 4 m = 20 m² Area of remaining part = Area of land – Area of 5 flower beds = 20 m² – 5 m² = 15Read more
Side of square bed = 1 m
Area of square bed = side x side = 1 m x 1 m = 1 m²
∴ Area of 5 square beds = 1 x 5 = 5 m²
Now, Length of land = 5 m
Breadth of land = 4 m
∴ Area of land = length x breadth
= 5 m x 4 m = 20 m²
Area of remaining part = Area of land – Area of 5 flower beds
= 20 m² – 5 m² = 15 m²
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessA floor is 5 m long and 4 m wide. A square carpet of sides 3 m is laid on the floor. Find the area of the floor that is not carpeted.
Length of floor = 5 m and breadth of floor = 4 m Area of floor = length x breadth = 5 m x 4 m = 20 m² Now, Side of square carpet = 3 m Area of square carpet = side x side = 3 x 3 = 9 m² Area of floor that is not carpeted = 20 m² – 9 m² = 11 m² https://www.tiwariacademy.com/ncert-solutions/class-6/maRead more
Length of floor = 5 m and breadth of floor = 4 m
Area of floor = length x breadth
= 5 m x 4 m = 20 m²
Now, Side of square carpet = 3 m
Area of square carpet = side x side = 3 x 3 = 9 m²
Area of floor that is not carpeted = 20 m² – 9 m² = 11 m²
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessA room us 4 m long and 3 m 50 cm wide. How many square meters of carpet is needed to cover the floor of the room?
Length of room = 4 m Breadth of room = 3 m 50 cm = 3.50 m Area of carpet = length x breadth = 4 x 3.50 = 14m² https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Length of room = 4 m
Breadth of room = 3 m 50 cm = 3.50 m
Area of carpet = length x breadth = 4 x 3.50 = 14m²
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessA table-top measures 2 m by 1 m 50 cm. What is its area in square meters?
Length of table = 2 m Breadth of table = 1 m 50 cm = 1.50 m Area of table = length x breadth = 2 m x 1.50 m = 3 m² https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Length of table = 2 m
Breadth of table = 1 m 50 cm = 1.50 m
Area of table = length x breadth
= 2 m x 1.50 m = 3 m²
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessWhat is the cost of tilling a rectangular plot of land 500 m long and 200 m wide at the rate of ₹8 per hundred sq. m?
Length of land = 500 m and Breadth of land = 200 m Area of land = length x breadth = 500 m x 200 m = 1,00,000 m² ∴ Cost of tilling 100 sq. m of land = ₹ 8 ∴ Cost of tilling 1,00,000 sq. m of land = 8x100000/100 = ₹ 8000 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Length of land = 500 m and Breadth of land = 200 m
Area of land = length x breadth = 500 m x 200 m = 1,00,000 m²
∴ Cost of tilling 100 sq. m of land = ₹ 8
∴ Cost of tilling 1,00,000 sq. m of land = 8×100000/100 = ₹ 8000
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessThe area of a rectangle garden 50 m long is 300 m², find the width of the garden.
Length of rectangle = 50 m and Area of rectangle = 300 m² Since, Area of rectangle = length x breadth Therefore, Breadth = Area of rectangle/Length = 300/50 = 6 m Thus, the breadth of the garden is 6 m. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Length of rectangle = 50 m and Area of rectangle = 300 m²
Since, Area of rectangle = length x breadth
Therefore, Breadth = Area of rectangle/Length = 300/50 = 6 m
Thus, the breadth of the garden is 6 m.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessThe length and the breadth of three rectangles are as given below: (a) 9 m and 6 m (b) 17 m and 3 m (c) 4 m and 14 m Which one has the largest area and which one has the smallest?
(a) Area of rectangle = length x breadth = 9 m x 6 m = 54 m² (b) Area of rectangle = length x breadth= 3 m x 17 m = 51 m² (c) Area of rectangle = length x breadth= 4 m x 14 m = 56 m² Thus, the rectangle (c) has largest area, and rectangle (b) has smallest area. https://www.tiwariacademy.com/ncert-soRead more
(a) Area of rectangle = length x breadth = 9 m x 6 m = 54 m²
(b) Area of rectangle = length x breadth= 3 m x 17 m = 51 m²
(c) Area of rectangle = length x breadth= 4 m x 14 m = 56 m²
Thus, the rectangle (c) has largest area, and rectangle (b) has smallest area.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessFind the areas of the squares whose sides are: (a) 10 cm (b) 14 cm (c) 5 cm
(a) Area of square = side x side = 10 cm x 10 cm = 100 cm² (b) Area of square = side x side = 14 cm x 14 cm = 196 cm² (c) Area of square = side x side = 5 m x 5 m = 25 m² https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
(a) Area of square = side x side = 10 cm x 10 cm = 100 cm²
(b) Area of square = side x side = 14 cm x 14 cm = 196 cm²
(c) Area of square = side x side = 5 m x 5 m = 25 m²
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessFind the areas of the rectangles whose sides are: (a) 3 cm and 4 cm (b) 12 m and 21 m (c) 2 km and 3 km (d) 2 m and 70 cm
(a) Area of rectangle = length x breadth = 3 cm x 4 cm = 12 cm² (b) Area of rectangle = length x breadth = 12 m x 21 m = 252 m² (c) Area of rectangle = length x breadth = 2 km x 3 km = 6 km² (d) Area of rectangle = length x breadth = 2 m x 70 cm = 2 m x 0.7 m = 1.4 m² https://www.tiwariacademy.com/nRead more
(a) Area of rectangle = length x breadth
= 3 cm x 4 cm = 12 cm²
(b) Area of rectangle = length x breadth
= 12 m x 21 m = 252 m²
(c) Area of rectangle = length x breadth
= 2 km x 3 km = 6 km²
(d) Area of rectangle = length x breadth
= 2 m x 70 cm = 2 m x 0.7 m = 1.4 m²
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See less