(a) Area of region = 100 cm x 144 cm = 14400 cm² Area of one tile = 5 cm x 12 cm = 60 cm² Number of tiles = Area of region/Area of one tile 14400/60 = 240 Thus, 240 tiles are required. (b) Area of region = 70 cm x 36 cm = 2520 cm² Area of one tile = 5 cm x 12 cm = 60 cm² Number of tiles = Area of reRead more
(a) Area of region = 100 cm x 144 cm = 14400 cm²
Area of one tile = 5 cm x 12 cm = 60 cm²
Number of tiles = Area of region/Area of one tile
14400/60 = 240
Thus, 240 tiles are required.
(b) Area of region = 70 cm x 36 cm = 2520 cm²
Area of one tile = 5 cm x 12 cm = 60 cm²
Number of tiles = Area of region/Area of one tile
=2520/60=42
Thus, 42 tiles are required.
Side of square bed = 1 m Area of square bed = side x side = 1 m x 1 m = 1 m² ∴ Area of 5 square beds = 1 x 5 = 5 m² Now, Length of land = 5 m Breadth of land = 4 m ∴ Area of land = length x breadth = 5 m x 4 m = 20 m² Area of remaining part = Area of land – Area of 5 flower beds = 20 m² – 5 m² = 15Read more
Side of square bed = 1 m
Area of square bed = side x side = 1 m x 1 m = 1 m²
∴ Area of 5 square beds = 1 x 5 = 5 m²
Now, Length of land = 5 m
Breadth of land = 4 m
∴ Area of land = length x breadth
= 5 m x 4 m = 20 m²
Area of remaining part = Area of land – Area of 5 flower beds
= 20 m² – 5 m² = 15 m²
Length of floor = 5 m and breadth of floor = 4 m Area of floor = length x breadth = 5 m x 4 m = 20 m² Now, Side of square carpet = 3 m Area of square carpet = side x side = 3 x 3 = 9 m² Area of floor that is not carpeted = 20 m² – 9 m² = 11 m² https://www.tiwariacademy.com/ncert-solutions/class-6/maRead more
Length of floor = 5 m and breadth of floor = 4 m
Area of floor = length x breadth
= 5 m x 4 m = 20 m²
Now, Side of square carpet = 3 m
Area of square carpet = side x side = 3 x 3 = 9 m²
Area of floor that is not carpeted = 20 m² – 9 m² = 11 m²
Length of room = 4 m Breadth of room = 3 m 50 cm = 3.50 m Area of carpet = length x breadth = 4 x 3.50 = 14m² https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Length of room = 4 m
Breadth of room = 3 m 50 cm = 3.50 m
Area of carpet = length x breadth = 4 x 3.50 = 14m²
Length of table = 2 m Breadth of table = 1 m 50 cm = 1.50 m Area of table = length x breadth = 2 m x 1.50 m = 3 m² https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Length of table = 2 m
Breadth of table = 1 m 50 cm = 1.50 m
Area of table = length x breadth
= 2 m x 1.50 m = 3 m²
How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively? (a) 100 cm and 144 cm (b) 70 cm and 36 cm
(a) Area of region = 100 cm x 144 cm = 14400 cm² Area of one tile = 5 cm x 12 cm = 60 cm² Number of tiles = Area of region/Area of one tile 14400/60 = 240 Thus, 240 tiles are required. (b) Area of region = 70 cm x 36 cm = 2520 cm² Area of one tile = 5 cm x 12 cm = 60 cm² Number of tiles = Area of reRead more
(a) Area of region = 100 cm x 144 cm = 14400 cm²
Area of one tile = 5 cm x 12 cm = 60 cm²
Number of tiles = Area of region/Area of one tile
14400/60 = 240
Thus, 240 tiles are required.
(b) Area of region = 70 cm x 36 cm = 2520 cm²
Area of one tile = 5 cm x 12 cm = 60 cm²
Number of tiles = Area of region/Area of one tile
=2520/60=42
Thus, 42 tiles are required.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessFive square flower beds each of sides 1 m are dug on a piece of land 5 m long and 4 m wide. What is the area of the remaining part of the land?
Side of square bed = 1 m Area of square bed = side x side = 1 m x 1 m = 1 m² ∴ Area of 5 square beds = 1 x 5 = 5 m² Now, Length of land = 5 m Breadth of land = 4 m ∴ Area of land = length x breadth = 5 m x 4 m = 20 m² Area of remaining part = Area of land – Area of 5 flower beds = 20 m² – 5 m² = 15Read more
Side of square bed = 1 m
Area of square bed = side x side = 1 m x 1 m = 1 m²
∴ Area of 5 square beds = 1 x 5 = 5 m²
Now, Length of land = 5 m
Breadth of land = 4 m
∴ Area of land = length x breadth
= 5 m x 4 m = 20 m²
Area of remaining part = Area of land – Area of 5 flower beds
= 20 m² – 5 m² = 15 m²
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessA floor is 5 m long and 4 m wide. A square carpet of sides 3 m is laid on the floor. Find the area of the floor that is not carpeted.
Length of floor = 5 m and breadth of floor = 4 m Area of floor = length x breadth = 5 m x 4 m = 20 m² Now, Side of square carpet = 3 m Area of square carpet = side x side = 3 x 3 = 9 m² Area of floor that is not carpeted = 20 m² – 9 m² = 11 m² https://www.tiwariacademy.com/ncert-solutions/class-6/maRead more
Length of floor = 5 m and breadth of floor = 4 m
Area of floor = length x breadth
= 5 m x 4 m = 20 m²
Now, Side of square carpet = 3 m
Area of square carpet = side x side = 3 x 3 = 9 m²
Area of floor that is not carpeted = 20 m² – 9 m² = 11 m²
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessA room us 4 m long and 3 m 50 cm wide. How many square meters of carpet is needed to cover the floor of the room?
Length of room = 4 m Breadth of room = 3 m 50 cm = 3.50 m Area of carpet = length x breadth = 4 x 3.50 = 14m² https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Length of room = 4 m
Breadth of room = 3 m 50 cm = 3.50 m
Area of carpet = length x breadth = 4 x 3.50 = 14m²
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessA table-top measures 2 m by 1 m 50 cm. What is its area in square meters?
Length of table = 2 m Breadth of table = 1 m 50 cm = 1.50 m Area of table = length x breadth = 2 m x 1.50 m = 3 m² https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Length of table = 2 m
Breadth of table = 1 m 50 cm = 1.50 m
Area of table = length x breadth
= 2 m x 1.50 m = 3 m²
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See less