(a) 6 m (b) 10 m (c) Second arrangement has greater perimeter. (d) Yes, if all the squares are arranged in row, the perimeter be 10 cm. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
(a) 6 m
(b) 10 m
(c) Second arrangement has greater perimeter.
(d) Yes, if all the squares are arranged in row, the perimeter be 10 cm.
Distance covered by Sweety = Perimeter of square park Perimeter of square = 4 x side = 4 x 75 = 300 m Thus, distance covered by Sweety is 300 m. Now, distance covered by Bulbul = Perimeter of rectangular park Perimeter of rectangular park = 2 x (length + breadth) = 2 x (60 + 45) = 2 x 105 = 210 m ThRead more
Distance covered by Sweety = Perimeter of square park
Perimeter of square = 4 x side
= 4 x 75 = 300 m
Thus, distance covered by Sweety is 300 m.
Now, distance covered by Bulbul = Perimeter of rectangular park
Perimeter of rectangular park = 2 x (length + breadth)
= 2 x (60 + 45)
= 2 x 105 = 210 m
Thus, Bulbul covers the distance of 210 m and Bulbul covers less distance.
Length of rectangular park = 175 m Breadth of rectangular park = 125 m Perimeter of park = 2 x (length + breadth) = 2 x (175 + 125) = 2 x 300 = 600 m Since, the cost of fencing park per meter = ₹ 12 Therefore, the cost of fencing park of 600 m = 12 x 600 = ₹ 7,200 https://www.tiwariacademy.com/ncertRead more
Length of rectangular park = 175 m
Breadth of rectangular park = 125 m
Perimeter of park = 2 x (length + breadth)
= 2 x (175 + 125)
= 2 x 300 = 600 m
Since, the cost of fencing park per meter = ₹ 12
Therefore, the cost of fencing park of 600 m = 12 x 600 = ₹ 7,200
Side of square = 250 m Perimeter of square = 4 x side = 4 x 250 = 1000 m Since, cost of fencing of per meter = ₹ 20 Therefore, the cost of fencing of 1000 meters = 20 x 1000 = ₹20,000 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Side of square = 250 m
Perimeter of square = 4 x side
= 4 x 250
= 1000 m
Since, cost of fencing of per meter = ₹ 20
Therefore, the cost of fencing of 1000 meters = 20 x 1000 = ₹20,000
Let the length of third side be x cm. Length of other two side are 12 cm and 14 cm. Now, Perimeter of triangle = 36 cm ⇒ 12+14+x=36 ⇒ 26+x=36 ⇒ x=36-26 ⇒ x=10 cm Thus, the length of third side is 10 cm. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Let the length of third side be x cm.
Length of other two side are 12 cm and 14 cm.
Now, Perimeter of triangle = 36 cm
⇒ 12+14+x=36
⇒ 26+x=36
⇒ x=36-26
⇒ x=10 cm
Thus, the length of third side is 10 cm.
Length of string = Perimeter of each figure (a) Perimeter of square = 30 cm ⇒ 4 x side = 30 cm ⇒ Side = 30/4 = 7.5 cm Thus, the length of each side of square is 7.5 cm. (b) Perimeter of equilateral triangle = 30 cm ⇒ 3 x side = 30 cm ⇒ Side = 30/3 = 10 cm Thus, the length of each side of equilateralRead more
Length of string = Perimeter of each figure
(a) Perimeter of square = 30 cm
⇒ 4 x side = 30 cm
⇒ Side = 30/4 = 7.5 cm
Thus, the length of each side of square is 7.5 cm.
(b) Perimeter of equilateral triangle = 30 cm
⇒ 3 x side = 30 cm
⇒ Side = 30/3 = 10 cm
Thus, the length of each side of equilateral triangle is 10 cm.
(c) Perimeter of hexagon = 30 cm
⇒ 6 x side = 30 cm
⇒ Side = 30/6 = 5 cm
Thus, the side of each side of hexagon is 5 cm.
Perimeter of regular pentagon = 100 cm ⇒ 5 x side = 100 cm ⇒ Side = 100/5 = 20 cm Thus, the side of regular pentagon is 20 cm. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Perimeter of regular pentagon = 100 cm
⇒ 5 x side = 100 cm
⇒ Side = 100/5 = 20 cm
Thus, the side of regular pentagon is 20 cm.
Perimeter of square = 4 x side ⇒ 20 = 4 x side ⇒ Side = 20/4 = 5 cm Thus, the side of square is 5 cm. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Perimeter of square = 4 x side
⇒ 20 = 4 x side
⇒ Side = 20/4 = 5 cm
Thus, the side of square is 5 cm.
Perimeter of Hexagon = 6 x length of one side = 6 x 8 m = 48 m Thus, the perimeter of hexagon is 48 m. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Perimeter of Hexagon = 6 x length of one side
= 6 x 8 m
= 48 m
Thus, the perimeter of hexagon is 48 m.
Perimeter of triangle = Sum of all three sides = 10 cm + 14 cm + 15 cm = 39 cm Thus, the perimeter of triangle is 39 cm. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Perimeter of triangle = Sum of all three sides
= 10 cm + 14 cm + 15 cm
= 39 cm
Thus, the perimeter of triangle is 39 cm.
Avneet buys 9 square paving slabs, each with a side ½ m. He lays them in the form of a square (a) What is the perimeter of his arrangement? (b) Shari does not like his arrangement. She gets him to lay them out like a cross. What is the perimeter of her arrangement? (c) Which has greater perimeter? (d) Avneet wonders, if there is a way of getting an even greater perimeter. Can you find a way of doing this? (The paving slabs must meet along complete edges, i.e., they cannot be broken.)
(a) 6 m (b) 10 m (c) Second arrangement has greater perimeter. (d) Yes, if all the squares are arranged in row, the perimeter be 10 cm. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
(a) 6 m
(b) 10 m
(c) Second arrangement has greater perimeter.
(d) Yes, if all the squares are arranged in row, the perimeter be 10 cm.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessSweety runs around a square park of side 75 m. Bulbul runs around a rectangular park with length of 60 m and breadth 45 m. Who covers less distance?
Distance covered by Sweety = Perimeter of square park Perimeter of square = 4 x side = 4 x 75 = 300 m Thus, distance covered by Sweety is 300 m. Now, distance covered by Bulbul = Perimeter of rectangular park Perimeter of rectangular park = 2 x (length + breadth) = 2 x (60 + 45) = 2 x 105 = 210 m ThRead more
Distance covered by Sweety = Perimeter of square park
Perimeter of square = 4 x side
= 4 x 75 = 300 m
Thus, distance covered by Sweety is 300 m.
Now, distance covered by Bulbul = Perimeter of rectangular park
Perimeter of rectangular park = 2 x (length + breadth)
= 2 x (60 + 45)
= 2 x 105 = 210 m
Thus, Bulbul covers the distance of 210 m and Bulbul covers less distance.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessFind the cost of fencing a rectangular park of length 175 m and breadth 125 m at the rate of ₹12 per meter.
Length of rectangular park = 175 m Breadth of rectangular park = 125 m Perimeter of park = 2 x (length + breadth) = 2 x (175 + 125) = 2 x 300 = 600 m Since, the cost of fencing park per meter = ₹ 12 Therefore, the cost of fencing park of 600 m = 12 x 600 = ₹ 7,200 https://www.tiwariacademy.com/ncertRead more
Length of rectangular park = 175 m
Breadth of rectangular park = 125 m
Perimeter of park = 2 x (length + breadth)
= 2 x (175 + 125)
= 2 x 300 = 600 m
Since, the cost of fencing park per meter = ₹ 12
Therefore, the cost of fencing park of 600 m = 12 x 600 = ₹ 7,200
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessFind the cost of fencing a square park of side 250 m at the rate of ₹20 per meter.
Side of square = 250 m Perimeter of square = 4 x side = 4 x 250 = 1000 m Since, cost of fencing of per meter = ₹ 20 Therefore, the cost of fencing of 1000 meters = 20 x 1000 = ₹20,000 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Side of square = 250 m
Perimeter of square = 4 x side
= 4 x 250
= 1000 m
Since, cost of fencing of per meter = ₹ 20
Therefore, the cost of fencing of 1000 meters = 20 x 1000 = ₹20,000
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessTwo sides of a triangle are 12 cm and 14 cm. The perimeter of the triangle is 36 cm. What is the third side?
Let the length of third side be x cm. Length of other two side are 12 cm and 14 cm. Now, Perimeter of triangle = 36 cm ⇒ 12+14+x=36 ⇒ 26+x=36 ⇒ x=36-26 ⇒ x=10 cm Thus, the length of third side is 10 cm. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Let the length of third side be x cm.
Length of other two side are 12 cm and 14 cm.
Now, Perimeter of triangle = 36 cm
⇒ 12+14+x=36
⇒ 26+x=36
⇒ x=36-26
⇒ x=10 cm
Thus, the length of third side is 10 cm.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessA piece of string is 30 cm long. What will be the length of each side if the string is used to form: (a) a square (b) an equilateral triangle (c) a regular hexagon?
Length of string = Perimeter of each figure (a) Perimeter of square = 30 cm ⇒ 4 x side = 30 cm ⇒ Side = 30/4 = 7.5 cm Thus, the length of each side of square is 7.5 cm. (b) Perimeter of equilateral triangle = 30 cm ⇒ 3 x side = 30 cm ⇒ Side = 30/3 = 10 cm Thus, the length of each side of equilateralRead more
Length of string = Perimeter of each figure
(a) Perimeter of square = 30 cm
⇒ 4 x side = 30 cm
⇒ Side = 30/4 = 7.5 cm
Thus, the length of each side of square is 7.5 cm.
(b) Perimeter of equilateral triangle = 30 cm
⇒ 3 x side = 30 cm
⇒ Side = 30/3 = 10 cm
Thus, the length of each side of equilateral triangle is 10 cm.
(c) Perimeter of hexagon = 30 cm
⇒ 6 x side = 30 cm
⇒ Side = 30/6 = 5 cm
Thus, the side of each side of hexagon is 5 cm.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessThe perimeter of a regular pentagon is 100 cm. How long is its each side?
Perimeter of regular pentagon = 100 cm ⇒ 5 x side = 100 cm ⇒ Side = 100/5 = 20 cm Thus, the side of regular pentagon is 20 cm. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Perimeter of regular pentagon = 100 cm
⇒ 5 x side = 100 cm
⇒ Side = 100/5 = 20 cm
Thus, the side of regular pentagon is 20 cm.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessFind the side of the square whose perimeter is 20 m.
Perimeter of square = 4 x side ⇒ 20 = 4 x side ⇒ Side = 20/4 = 5 cm Thus, the side of square is 5 cm. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Perimeter of square = 4 x side
⇒ 20 = 4 x side
⇒ Side = 20/4 = 5 cm
Thus, the side of square is 5 cm.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessFind the perimeter of a regular hexagon with each side measuring 8 cm.
Perimeter of Hexagon = 6 x length of one side = 6 x 8 m = 48 m Thus, the perimeter of hexagon is 48 m. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Perimeter of Hexagon = 6 x length of one side
= 6 x 8 m
= 48 m
Thus, the perimeter of hexagon is 48 m.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessFind the perimeter of a triangle with sides measuring 10 cm, 14 cm and 15 cm.
Perimeter of triangle = Sum of all three sides = 10 cm + 14 cm + 15 cm = 39 cm Thus, the perimeter of triangle is 39 cm. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Perimeter of triangle = Sum of all three sides
= 10 cm + 14 cm + 15 cm
= 39 cm
Thus, the perimeter of triangle is 39 cm.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See less