Length of land = 500 m and Breadth of land = 200 m Area of land = length x breadth = 500 m x 200 m = 1,00,000 m² ∴ Cost of tilling 100 sq. m of land = ₹ 8 ∴ Cost of tilling 1,00,000 sq. m of land = 8x100000/100 = ₹ 8000 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Length of land = 500 m and Breadth of land = 200 m
Area of land = length x breadth = 500 m x 200 m = 1,00,000 m²
∴ Cost of tilling 100 sq. m of land = ₹ 8
∴ Cost of tilling 1,00,000 sq. m of land = 8×100000/100 = ₹ 8000
Length of rectangle = 50 m and Area of rectangle = 300 m² Since, Area of rectangle = length x breadth Therefore, Breadth = Area of rectangle/Length = 300/50 = 6 m Thus, the breadth of the garden is 6 m. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Length of rectangle = 50 m and Area of rectangle = 300 m²
Since, Area of rectangle = length x breadth
Therefore, Breadth = Area of rectangle/Length = 300/50 = 6 m
Thus, the breadth of the garden is 6 m.
(a) Area of rectangle = length x breadth = 9 m x 6 m = 54 m² (b) Area of rectangle = length x breadth= 3 m x 17 m = 51 m² (c) Area of rectangle = length x breadth= 4 m x 14 m = 56 m² Thus, the rectangle (c) has largest area, and rectangle (b) has smallest area. https://www.tiwariacademy.com/ncert-soRead more
(a) Area of rectangle = length x breadth = 9 m x 6 m = 54 m²
(b) Area of rectangle = length x breadth= 3 m x 17 m = 51 m²
(c) Area of rectangle = length x breadth= 4 m x 14 m = 56 m²
Thus, the rectangle (c) has largest area, and rectangle (b) has smallest area.
(a) Area of square = side x side = 10 cm x 10 cm = 100 cm² (b) Area of square = side x side = 14 cm x 14 cm = 196 cm² (c) Area of square = side x side = 5 m x 5 m = 25 m² https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
(a) Area of square = side x side = 10 cm x 10 cm = 100 cm²
(b) Area of square = side x side = 14 cm x 14 cm = 196 cm²
(c) Area of square = side x side = 5 m x 5 m = 25 m²
(a) Area of rectangle = length x breadth = 3 cm x 4 cm = 12 cm² (b) Area of rectangle = length x breadth = 12 m x 21 m = 252 m² (c) Area of rectangle = length x breadth = 2 km x 3 km = 6 km² (d) Area of rectangle = length x breadth = 2 m x 70 cm = 2 m x 0.7 m = 1.4 m² https://www.tiwariacademy.com/nRead more
(a) Area of rectangle = length x breadth
= 3 cm x 4 cm = 12 cm²
(b) Area of rectangle = length x breadth
= 12 m x 21 m = 252 m²
(c) Area of rectangle = length x breadth
= 2 km x 3 km = 6 km²
(d) Area of rectangle = length x breadth
= 2 m x 70 cm = 2 m x 0.7 m = 1.4 m²
What is the cost of tilling a rectangular plot of land 500 m long and 200 m wide at the rate of ₹8 per hundred sq. m?
Length of land = 500 m and Breadth of land = 200 m Area of land = length x breadth = 500 m x 200 m = 1,00,000 m² ∴ Cost of tilling 100 sq. m of land = ₹ 8 ∴ Cost of tilling 1,00,000 sq. m of land = 8x100000/100 = ₹ 8000 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Length of land = 500 m and Breadth of land = 200 m
Area of land = length x breadth = 500 m x 200 m = 1,00,000 m²
∴ Cost of tilling 100 sq. m of land = ₹ 8
∴ Cost of tilling 1,00,000 sq. m of land = 8×100000/100 = ₹ 8000
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessThe area of a rectangle garden 50 m long is 300 m², find the width of the garden.
Length of rectangle = 50 m and Area of rectangle = 300 m² Since, Area of rectangle = length x breadth Therefore, Breadth = Area of rectangle/Length = 300/50 = 6 m Thus, the breadth of the garden is 6 m. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
Length of rectangle = 50 m and Area of rectangle = 300 m²
Since, Area of rectangle = length x breadth
Therefore, Breadth = Area of rectangle/Length = 300/50 = 6 m
Thus, the breadth of the garden is 6 m.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessThe length and the breadth of three rectangles are as given below: (a) 9 m and 6 m (b) 17 m and 3 m (c) 4 m and 14 m Which one has the largest area and which one has the smallest?
(a) Area of rectangle = length x breadth = 9 m x 6 m = 54 m² (b) Area of rectangle = length x breadth= 3 m x 17 m = 51 m² (c) Area of rectangle = length x breadth= 4 m x 14 m = 56 m² Thus, the rectangle (c) has largest area, and rectangle (b) has smallest area. https://www.tiwariacademy.com/ncert-soRead more
(a) Area of rectangle = length x breadth = 9 m x 6 m = 54 m²
(b) Area of rectangle = length x breadth= 3 m x 17 m = 51 m²
(c) Area of rectangle = length x breadth= 4 m x 14 m = 56 m²
Thus, the rectangle (c) has largest area, and rectangle (b) has smallest area.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessFind the areas of the squares whose sides are: (a) 10 cm (b) 14 cm (c) 5 cm
(a) Area of square = side x side = 10 cm x 10 cm = 100 cm² (b) Area of square = side x side = 14 cm x 14 cm = 196 cm² (c) Area of square = side x side = 5 m x 5 m = 25 m² https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
(a) Area of square = side x side = 10 cm x 10 cm = 100 cm²
(b) Area of square = side x side = 14 cm x 14 cm = 196 cm²
(c) Area of square = side x side = 5 m x 5 m = 25 m²
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See lessFind the areas of the rectangles whose sides are: (a) 3 cm and 4 cm (b) 12 m and 21 m (c) 2 km and 3 km (d) 2 m and 70 cm
(a) Area of rectangle = length x breadth = 3 cm x 4 cm = 12 cm² (b) Area of rectangle = length x breadth = 12 m x 21 m = 252 m² (c) Area of rectangle = length x breadth = 2 km x 3 km = 6 km² (d) Area of rectangle = length x breadth = 2 m x 70 cm = 2 m x 0.7 m = 1.4 m² https://www.tiwariacademy.com/nRead more
(a) Area of rectangle = length x breadth
= 3 cm x 4 cm = 12 cm²
(b) Area of rectangle = length x breadth
= 12 m x 21 m = 252 m²
(c) Area of rectangle = length x breadth
= 2 km x 3 km = 6 km²
(d) Area of rectangle = length x breadth
= 2 m x 70 cm = 2 m x 0.7 m = 1.4 m²
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-10/
See less