(i) 126° + 44° = 170° l ||m because sum of interior opposite angles should be 180. (ii) 75° + 75° = 150° l ||m because sum of angles does not obey the property of parallel lines. (iii) 57° + 123° = 180° l ||m due to supplementary angles property of parallel lines. (iv) 98° + 72° + 170° l is not parRead more
(i) 126° + 44° = 170°
l ||m because sum of interior opposite angles should be 180.
(ii) 75° + 75° = 150°
l ||m because sum of angles does not obey the property of parallel lines.
(iii) 57° + 123° = 180°
l ||m due to supplementary angles property of parallel lines.
(iv) 98° + 72° + 170°
l is not parallel to m because sum of angles does not obey the property of
parallel lines.
(i) Given, AB || DE and BC is a transversal line and ∠ABC = 70° ∵ ∠ABC = ∠DGC [Corresponding angles] ∴ ∠DGC = 70° ……….(i) (ii) Given, BC || EF and DE is a transversal line and ∠DGC = 70° ∵ ∠DGC = ∠DEF [Corresponding angles] ∴ ∠DEF = 70° [From equation (i)] Class 7 Maths Chapter 5 Exercise 5.2 for moRead more
(i) Given, AB || DE and BC is a transversal line and ∠ABC = 70°
∵ ∠ABC = ∠DGC [Corresponding angles]
∴ ∠DGC = 70° ……….(i)
(ii) Given, BC || EF and DE is a transversal line and ∠DGC = 70°
∵ ∠DGC = ∠DEF [Corresponding angles]
∴ ∠DEF = 70° [From equation (i)]
(i) Given, l||m and t is transversal line. ∴ Interior vertically opposite angle between lines l and t = 110° ∴ 110° + x = 180° [Supplementary angles] ⇒ x = 180° - 110° = 70° (ii) Given, l||m and t is transversal line. x + 2x = [Interior opposite angles] ⇒ 3x = 180° ⇒ x= 180°/3 = 60° (iii) Given, l||Read more
(i) Given, l||m and t is transversal line.
∴ Interior vertically opposite angle between lines l and t = 110°
∴ 110° + x = 180° [Supplementary angles]
⇒ x = 180° – 110° = 70°
(ii) Given, l||m and t is transversal line.
x + 2x = [Interior opposite angles]
⇒ 3x = 180°
⇒ x= 180°/3 = 60°
(iii) Given, l||m and a||b.
x=100° [Corresponding angles]
Given, p||q and cut by a transversal line. ∵ 125° + e = 180° [Linear pair] ∴ e = 180° - 125° = 55° ……….(i) Now e = f = 55° [Vertically opposite angles] Also a = f = 55° [Alternate interior angles] a = b + 180° [Linear pair] ⇒ 55° + b = 180° [From equation (i)] ⇒ b = 180° - 55° = 125° Now a = c = 55°Read more
Given, p||q and cut by a transversal line.
∵ 125° + e = 180° [Linear pair]
∴ e = 180° – 125° = 55° ……….(i)
Now e = f = 55° [Vertically opposite angles]
Also a = f = 55° [Alternate interior angles]
a = b + 180° [Linear pair]
⇒ 55° + b = 180° [From equation (i)]
⇒ b = 180° – 55° = 125°
Now a = c = 55° and b = d = 125° [Vertically opposite angles]
Thus, a = 55°,b = 125°, c = 55°, d = 125°, e = 55° and f = 55°.
(i) The pairs of corresponding angles: ∠1, ∠5; ∠2, ∠6; ∠4, ∠8 and ∠3, ∠7 (ii) The pairs of alternate interior angles are: ∠3, ∠5 and ∠2, ∠8 (iii) The pair of interior angles on the same side of the transversal: ∠3, ∠8 and ∠2, ∠5 (iv) The vertically opposite angles are: ∠1, ∠3; ∠2, ∠4; ∠6, ∠8 and ∠5,Read more
(i) The pairs of corresponding angles:
∠1, ∠5; ∠2, ∠6; ∠4, ∠8 and ∠3, ∠7
(ii) The pairs of alternate interior angles are:
∠3, ∠5 and ∠2, ∠8
(iii) The pair of interior angles on the same side of the transversal:
∠3, ∠8 and ∠2, ∠5
(iv) The vertically opposite angles are:
∠1, ∠3; ∠2, ∠4; ∠6, ∠8 and ∠5, ∠7
(i) Given, a||b, then ∠1 = ∠5 [Corresponding angles] If two parallel lines are cut by a transversal, each pair of corresponding angles are equal in measure. (ii) Given, ∠4 = ∠6, then a||b [Alternate interior angles] When a transversal cuts two lines such that pairs of alternate interior angles are eRead more
(i) Given, a||b, then ∠1 = ∠5 [Corresponding angles]
If two parallel lines are cut by a transversal, each pair of corresponding
angles are equal in measure.
(ii) Given, ∠4 = ∠6, then a||b [Alternate interior angles]
When a transversal cuts two lines such that pairs of alternate interior
angles are equal, the lines have to be parallel.
(iii) Given, ∠4 + ∠5 = 180°, then a||b [Co-interior Angles]
When a transversal cuts two lines, such that pairs of interior angles on the
same side of transversal are supplementary, the lines have to be parallel.
(i) Obtuse vertically opposite angles means greater than 90° and equal ∠AOD = ∠BOC. (ii) Adjacent complementary angles means angles have common vertex, common arm, non-common arms are on either side of common arm and sum of angles is 90° . (iii) Equal supplementary angles means sum of angles is 180°Read more
(i) Obtuse vertically opposite angles means greater than 90° and equal
∠AOD = ∠BOC.
(ii) Adjacent complementary angles means angles have common vertex,
common arm, non-common arms are on either side of common arm and
sum of angles is 90° .
(iii) Equal supplementary angles means sum of angles is 180° and supplement
angles are equal.
(iv) Unequal supplementary angles means sum of angles is 180° and
supplement angles are unequal.
i.e., ∠AOE, ∠EOC; ∠AOD, ∠DOC and ∠AOB, ∠BOC
(v) Adjacent angles that do not form a linear pair mean, angles have common
ray but the angles in a linear pair are not supplementary.
i.e., ∠AOB, ∠AOE; ∠AOE, ∠EOD and ∠EOD, ∠COD
(i) If two angles are complementary, then the sum of their measures is 90°. (ii) If two angles are supplementary, then the sum of their measures is 180°. (iii) Two angles forming a linear pair are supplementary. (iv) If two adjacent angles are supplementary, they form a linear pair. Class 7 Maths ChRead more
(i) If two angles are complementary, then the sum of their measures is 90°.
(ii) If two angles are supplementary, then the sum of their measures is 180°.
(iii) Two angles forming a linear pair are supplementary.
(iv) If two adjacent angles are supplementary, they form a linear pair.
(i) x = 55° [Vertically opposite angles] Now 55° + y = 180° [Linear pair] ⇒ y = 180° - 55° = 125° Also y = z = 125° [Vertically opposite angles] Thus, x = 55°, y = 125° and z = 125°. (ii) 40° + x + 25° = 180° [Angles on straight line] ⇒ 65° + x = 180° ⇒ x = 180° - 65° = 115° Now 40° + y = 180° [LineRead more
(i) x = 55° [Vertically opposite angles]
Now 55° + y = 180° [Linear pair]
⇒ y = 180° – 55° = 125°
Also y = z = 125° [Vertically opposite angles]
Thus, x = 55°, y = 125° and z = 125°.
(ii) 40° + x + 25° = 180° [Angles on straight line]
⇒ 65° + x = 180°
⇒ x = 180° – 65° = 115°
Now 40° + y = 180° [Linear pair]
⇒ y = 180° – 40° = 140° ……….(i)
Also y+z = 180°
⇒ 140° + z = 180° [Linear pair]
⇒ z = 180° – 140° = 40° [From equation (i)]
Thus, x = 115°, y = 140° and z = 40°
∠1 and ∠2 are not adjacent angles because their vertex is not common. Class 7 Maths Chapter 5 Exercise 5.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
∠1 and ∠2 are not adjacent angles because their vertex is not common.
In the given figures below, decide whether l is parallel to m.
(i) 126° + 44° = 170° l ||m because sum of interior opposite angles should be 180. (ii) 75° + 75° = 150° l ||m because sum of angles does not obey the property of parallel lines. (iii) 57° + 123° = 180° l ||m due to supplementary angles property of parallel lines. (iv) 98° + 72° + 170° l is not parRead more
(i) 126° + 44° = 170°
l ||m because sum of interior opposite angles should be 180.
(ii) 75° + 75° = 150°
l ||m because sum of angles does not obey the property of parallel lines.
(iii) 57° + 123° = 180°
l ||m due to supplementary angles property of parallel lines.
(iv) 98° + 72° + 170°
l is not parallel to m because sum of angles does not obey the property of
parallel lines.
Class 7 Maths Chapter 5 Exercise 5.2
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
In the given figure, the arms of two angles are parallel. If ∆ABC = 70°, then find:, (i) ∠DGC (ii) ∠ DEF
(i) Given, AB || DE and BC is a transversal line and ∠ABC = 70° ∵ ∠ABC = ∠DGC [Corresponding angles] ∴ ∠DGC = 70° ……….(i) (ii) Given, BC || EF and DE is a transversal line and ∠DGC = 70° ∵ ∠DGC = ∠DEF [Corresponding angles] ∴ ∠DEF = 70° [From equation (i)] Class 7 Maths Chapter 5 Exercise 5.2 for moRead more
(i) Given, AB || DE and BC is a transversal line and ∠ABC = 70°
∵ ∠ABC = ∠DGC [Corresponding angles]
∴ ∠DGC = 70° ……….(i)
(ii) Given, BC || EF and DE is a transversal line and ∠DGC = 70°
∵ ∠DGC = ∠DEF [Corresponding angles]
∴ ∠DEF = 70° [From equation (i)]
Class 7 Maths Chapter 5 Exercise 5.2
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
Find the values of x in each of the following figures if l||m
(i) Given, l||m and t is transversal line. ∴ Interior vertically opposite angle between lines l and t = 110° ∴ 110° + x = 180° [Supplementary angles] ⇒ x = 180° - 110° = 70° (ii) Given, l||m and t is transversal line. x + 2x = [Interior opposite angles] ⇒ 3x = 180° ⇒ x= 180°/3 = 60° (iii) Given, l||Read more
(i) Given, l||m and t is transversal line.
∴ Interior vertically opposite angle between lines l and t = 110°
∴ 110° + x = 180° [Supplementary angles]
⇒ x = 180° – 110° = 70°
(ii) Given, l||m and t is transversal line.
x + 2x = [Interior opposite angles]
⇒ 3x = 180°
⇒ x= 180°/3 = 60°
(iii) Given, l||m and a||b.
x=100° [Corresponding angles]
Class 7 Maths Chapter 5 Exercise 5.2
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
In the adjoining figure, p||q. Find the unknown angles.
Given, p||q and cut by a transversal line. ∵ 125° + e = 180° [Linear pair] ∴ e = 180° - 125° = 55° ……….(i) Now e = f = 55° [Vertically opposite angles] Also a = f = 55° [Alternate interior angles] a = b + 180° [Linear pair] ⇒ 55° + b = 180° [From equation (i)] ⇒ b = 180° - 55° = 125° Now a = c = 55°Read more
Given, p||q and cut by a transversal line.
∵ 125° + e = 180° [Linear pair]
∴ e = 180° – 125° = 55° ……….(i)
Now e = f = 55° [Vertically opposite angles]
Also a = f = 55° [Alternate interior angles]
a = b + 180° [Linear pair]
⇒ 55° + b = 180° [From equation (i)]
⇒ b = 180° – 55° = 125°
Now a = c = 55° and b = d = 125° [Vertically opposite angles]
Thus, a = 55°,b = 125°, c = 55°, d = 125°, e = 55° and f = 55°.
Class 7 Maths Chapter 5 Exercise 5.2
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
In the adjoining figure, identify:(i) the pairs of corresponding angles. (ii) the pairs of alternate interior angles. (iii) the pairs of interior angles on the same side of the transversal. (iv) the vertically opposite angles.
(i) The pairs of corresponding angles: ∠1, ∠5; ∠2, ∠6; ∠4, ∠8 and ∠3, ∠7 (ii) The pairs of alternate interior angles are: ∠3, ∠5 and ∠2, ∠8 (iii) The pair of interior angles on the same side of the transversal: ∠3, ∠8 and ∠2, ∠5 (iv) The vertically opposite angles are: ∠1, ∠3; ∠2, ∠4; ∠6, ∠8 and ∠5,Read more
(i) The pairs of corresponding angles:
∠1, ∠5; ∠2, ∠6; ∠4, ∠8 and ∠3, ∠7
(ii) The pairs of alternate interior angles are:
∠3, ∠5 and ∠2, ∠8
(iii) The pair of interior angles on the same side of the transversal:
∠3, ∠8 and ∠2, ∠5
(iv) The vertically opposite angles are:
∠1, ∠3; ∠2, ∠4; ∠6, ∠8 and ∠5, ∠7
Class 7 Maths Chapter 5 Exercise 5.2
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
State the property that is used in each of the following statements: (i) If a||b, then ∠1 = ∠5. (ii) If ∠4 = ∠6, then a||b.(iii) If ∠4 + ∠5 + 180°, then a||b.
(i) Given, a||b, then ∠1 = ∠5 [Corresponding angles] If two parallel lines are cut by a transversal, each pair of corresponding angles are equal in measure. (ii) Given, ∠4 = ∠6, then a||b [Alternate interior angles] When a transversal cuts two lines such that pairs of alternate interior angles are eRead more
(i) Given, a||b, then ∠1 = ∠5 [Corresponding angles]
If two parallel lines are cut by a transversal, each pair of corresponding
angles are equal in measure.
(ii) Given, ∠4 = ∠6, then a||b [Alternate interior angles]
When a transversal cuts two lines such that pairs of alternate interior
angles are equal, the lines have to be parallel.
(iii) Given, ∠4 + ∠5 = 180°, then a||b [Co-interior Angles]
When a transversal cuts two lines, such that pairs of interior angles on the
same side of transversal are supplementary, the lines have to be parallel.
Class 7 Maths Chapter 5 Exercise 5.2
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
In the adjoining figure, name the following pairs of angles: (i) Obtuse vertically opposite angles. (ii) Adjacent complementary angles. (iii) Equal supplementary angles. (iv) Unequal supplementary angles. (v) Adjacent angles that do not form a linear pair.
(i) Obtuse vertically opposite angles means greater than 90° and equal ∠AOD = ∠BOC. (ii) Adjacent complementary angles means angles have common vertex, common arm, non-common arms are on either side of common arm and sum of angles is 90° . (iii) Equal supplementary angles means sum of angles is 180°Read more
(i) Obtuse vertically opposite angles means greater than 90° and equal
∠AOD = ∠BOC.
(ii) Adjacent complementary angles means angles have common vertex,
common arm, non-common arms are on either side of common arm and
sum of angles is 90° .
(iii) Equal supplementary angles means sum of angles is 180° and supplement
angles are equal.
(iv) Unequal supplementary angles means sum of angles is 180° and
supplement angles are unequal.
i.e., ∠AOE, ∠EOC; ∠AOD, ∠DOC and ∠AOB, ∠BOC
(v) Adjacent angles that do not form a linear pair mean, angles have common
ray but the angles in a linear pair are not supplementary.
i.e., ∠AOB, ∠AOE; ∠AOE, ∠EOD and ∠EOD, ∠COD
Class 7 Maths Chapter 5 Exercise 5.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
Fill in the blanks: (i) If two angles are complementary, then the sum of their measures is _______________. (ii) If two angles are supplementary, then the sum of their measures is _______________. (iii) Two angles forming a linear pair are _______________. (iv) If two adjacent angles are supplementary, they form a _______________.
(i) If two angles are complementary, then the sum of their measures is 90°. (ii) If two angles are supplementary, then the sum of their measures is 180°. (iii) Two angles forming a linear pair are supplementary. (iv) If two adjacent angles are supplementary, they form a linear pair. Class 7 Maths ChRead more
(i) If two angles are complementary, then the sum of their measures is 90°.
(ii) If two angles are supplementary, then the sum of their measures is 180°.
(iii) Two angles forming a linear pair are supplementary.
(iv) If two adjacent angles are supplementary, they form a linear pair.
Class 7 Maths Chapter 5 Exercise 5.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
Find the values of the angles x, y and z in each of the following.
(i) x = 55° [Vertically opposite angles] Now 55° + y = 180° [Linear pair] ⇒ y = 180° - 55° = 125° Also y = z = 125° [Vertically opposite angles] Thus, x = 55°, y = 125° and z = 125°. (ii) 40° + x + 25° = 180° [Angles on straight line] ⇒ 65° + x = 180° ⇒ x = 180° - 65° = 115° Now 40° + y = 180° [LineRead more
(i) x = 55° [Vertically opposite angles]
Now 55° + y = 180° [Linear pair]
⇒ y = 180° – 55° = 125°
Also y = z = 125° [Vertically opposite angles]
Thus, x = 55°, y = 125° and z = 125°.
(ii) 40° + x + 25° = 180° [Angles on straight line]
⇒ 65° + x = 180°
⇒ x = 180° – 65° = 115°
Now 40° + y = 180° [Linear pair]
⇒ y = 180° – 40° = 140° ……….(i)
Also y+z = 180°
⇒ 140° + z = 180° [Linear pair]
⇒ z = 180° – 140° = 40° [From equation (i)]
Thus, x = 115°, y = 140° and z = 40°
Class 7 Maths Chapter 5 Exercise 5.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
In the following figure, is ∠1 adjacent to ∠2? Give reasons
∠1 and ∠2 are not adjacent angles because their vertex is not common. Class 7 Maths Chapter 5 Exercise 5.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
∠1 and ∠2 are not adjacent angles because their vertex is not common.
Class 7 Maths Chapter 5 Exercise 5.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/