(i) Vertically opposite angles, ∠1 and ∠4; ∠5 and ∠2 + ∠3. (ii) Linear pairs ∠1 and ∠5; ∠5 and ∠4. Class 7 Maths Chapter 5 Exercise 5.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
(i) Vertically opposite angles, ∠1 and ∠4; ∠5 and ∠2 + ∠3.
(ii) Linear pairs ∠1 and ∠5; ∠5 and ∠4.
(i) Yes, in ∠AOE, OC is common arm. (ii) No, they have no non-common arms on opposite side of common arm. (iii) Yes, they form linear pair. (iv) Yes, they are supplementary. (v) Yes, they are vertically opposite angles. (vi) Vertically opposite angles of ∠5 is ∠COB. Class 7 Maths Chapter 5 ExerciseRead more
(i) Yes, in ∠AOE, OC is common arm.
(ii) No, they have no non-common arms on opposite side of common arm.
(iii) Yes, they form linear pair.
(iv) Yes, they are supplementary.
(v) Yes, they are vertically opposite angles.
(vi) Vertically opposite angles of ∠5 is ∠COB.
Let the complementary angles be x and y, i.e., x + y = 90° It is given that x > 45° Adding y both sides, x + y > 45° + y ⇒ 90° > 45° + y ⇒ 90° - 45° > y ⇒ y < 45° Thus, its complementary angle is less than 45° . Class 7 Maths Chapter 5 Exercise 5.1 for more answers vist to: https://wwRead more
Let the complementary angles be x and y, i.e., x + y = 90°
It is given that x > 45°
Adding y both sides, x + y > 45° + y
⇒ 90° > 45° + y
⇒ 90° – 45° > y
⇒ y < 45°
Thus, its complementary angle is less than 45° .
(i) No, because sum of two acute angles is less than 180°. (ii) No, because sum of two obtuse angles is more than 180°. (iii) Yes, because sum of two right angles is 180°. Class 7 Maths Chapter 5 Exercise 5.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chaptRead more
(i) No, because sum of two acute angles is less than 180°.
(ii) No, because sum of two obtuse angles is more than 180°.
(iii) Yes, because sum of two right angles is 180°.
If ∠1 is decreased then, ∠2 will increase with the same measure, so that both the angles still remain supplementary. Class 7 Maths Chapter 5 Exercise 5.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
If ∠1 is decreased then, ∠2 will increase with the same measure, so that both the angles still remain supplementary.
Let x be two equal angles of its supplement. Therefore, x + x = 180° [Supplementary angles] ⇒ 2x= 180° ⇒ x = 180°/2 = 90° Thus, 90° is equal to its supplement. Class 7 Maths Chapter 5 Exercise 5.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
Let x be two equal angles of its supplement.
Therefore, x + x = 180° [Supplementary angles]
⇒ 2x= 180°
⇒ x = 180°/2 = 90°
Let one of the two equal complementary angles be x. ∴ x + x = 90° ⇒ 2x= 90° ⇒ x = 90°/2 = 45° Thus, 45° is equal to its complement. Class 7 Maths Chapter 5 Exercise 5.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
Let one of the two equal complementary angles be x.
∴ x + x = 90°
⇒ 2x= 90°
⇒ x = 90°/2 = 45°
If sum of two angles is 180° , then they are called supplementary angles. If sum of two angles is 90° , then they are called complementary angles. (i) 65° + 115° = 180° These are supplementary angles. (ii) 63° + 27° = 90° These are complementary angles. (iii) 112° + 68° = 180° These are supplementarRead more
If sum of two angles is 180° , then they are called supplementary angles.
If sum of two angles is 90° , then they are called complementary angles.
(i) 65° + 115° = 180° These are supplementary angles.
(ii) 63° + 27° = 90° These are complementary angles.
(iii) 112° + 68° = 180° These are supplementary angles.
(iv) 130° + 50° = 180° These are supplementary angles.
(v) 45° + 45° = 90° These are complementary angles.
(vi) 80° + 10° = 90° These are complementary angles.
Supplementary angle = 180° - given angle (i) Supplement of 105° = 180° - 105° = 75° (ii) Supplement of 87° = 180° - 87° = 93° (iii) Supplement of 154° = 180° - 154° = 26° Class 7 Maths Chapter 5 Exercise 5.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapteRead more
Supplementary angle = 180° – given angle
(i) Supplement of 105° = 180° – 105° = 75°
(ii) Supplement of 87° = 180° – 87° = 93°
(iii) Supplement of 154° = 180° – 154° = 26°
Complementary angle = 90° - given angle (i) Complement of 20° = 90° - 20° = 70° (ii) Complement of 63° = 90° - 63° = 27° (iii) Complement of 57° = 90° - 57° = 33° Class 7 Maths Chapter 5 Exercise 5.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
Complementary angle = 90° – given angle
(i) Complement of 20° = 90° – 20° = 70°
(ii) Complement of 63° = 90° – 63° = 27°
(iii) Complement of 57° = 90° – 57° = 33°
Indicate which pairs of angles are: (i) Vertically opposite angles? (ii) Linear pairs?
(i) Vertically opposite angles, ∠1 and ∠4; ∠5 and ∠2 + ∠3. (ii) Linear pairs ∠1 and ∠5; ∠5 and ∠4. Class 7 Maths Chapter 5 Exercise 5.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
(i) Vertically opposite angles, ∠1 and ∠4; ∠5 and ∠2 + ∠3.
(ii) Linear pairs ∠1 and ∠5; ∠5 and ∠4.
Class 7 Maths Chapter 5 Exercise 5.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
In the adjoining figure: (i) Is ∠1 adjacent to ∠2? (ii) Is ∠AOC adjacent to ∠AOE? (iii) Do ∠COE and ∠EOD form a linear pair? (iv) Are ∠BOD and ∠DOA supplementary? (v) Is ∠1 vertically opposite to ∠4? (vi) What is the vertically opposite angle of ∠5?
(i) Yes, in ∠AOE, OC is common arm. (ii) No, they have no non-common arms on opposite side of common arm. (iii) Yes, they form linear pair. (iv) Yes, they are supplementary. (v) Yes, they are vertically opposite angles. (vi) Vertically opposite angles of ∠5 is ∠COB. Class 7 Maths Chapter 5 ExerciseRead more
(i) Yes, in ∠AOE, OC is common arm.
(ii) No, they have no non-common arms on opposite side of common arm.
(iii) Yes, they form linear pair.
(iv) Yes, they are supplementary.
(v) Yes, they are vertically opposite angles.
(vi) Vertically opposite angles of ∠5 is ∠COB.
Class 7 Maths Chapter 5 Exercise 5.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
An angle is greater than 45°. Is its complementary angle greater than 45° or equal to 45° or less than 45°?
Let the complementary angles be x and y, i.e., x + y = 90° It is given that x > 45° Adding y both sides, x + y > 45° + y ⇒ 90° > 45° + y ⇒ 90° - 45° > y ⇒ y < 45° Thus, its complementary angle is less than 45° . Class 7 Maths Chapter 5 Exercise 5.1 for more answers vist to: https://wwRead more
Let the complementary angles be x and y, i.e., x + y = 90°
It is given that x > 45°
Adding y both sides, x + y > 45° + y
⇒ 90° > 45° + y
⇒ 90° – 45° > y
⇒ y < 45°
Thus, its complementary angle is less than 45° .
Class 7 Maths Chapter 5 Exercise 5.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
Can two angles be supplementary if both of them are: (i) acute (ii) obtuse (iii) right?
(i) No, because sum of two acute angles is less than 180°. (ii) No, because sum of two obtuse angles is more than 180°. (iii) Yes, because sum of two right angles is 180°. Class 7 Maths Chapter 5 Exercise 5.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chaptRead more
(i) No, because sum of two acute angles is less than 180°.
(ii) No, because sum of two obtuse angles is more than 180°.
(iii) Yes, because sum of two right angles is 180°.
Class 7 Maths Chapter 5 Exercise 5.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
In the given figure, ∠1 and ∠2 are supplementary angles. If ∠1 is decreased, what changes should take place in ∠2 so that both the angles still remain supplementary?
If ∠1 is decreased then, ∠2 will increase with the same measure, so that both the angles still remain supplementary. Class 7 Maths Chapter 5 Exercise 5.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
If ∠1 is decreased then, ∠2 will increase with the same measure, so that both the angles still remain supplementary.
Class 7 Maths Chapter 5 Exercise 5.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
Find the angle which is equal to its supplement.
Let x be two equal angles of its supplement. Therefore, x + x = 180° [Supplementary angles] ⇒ 2x= 180° ⇒ x = 180°/2 = 90° Thus, 90° is equal to its supplement. Class 7 Maths Chapter 5 Exercise 5.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
Let x be two equal angles of its supplement.
Therefore, x + x = 180° [Supplementary angles]
⇒ 2x= 180°
⇒ x = 180°/2 = 90°
Thus, 90° is equal to its supplement.
Class 7 Maths Chapter 5 Exercise 5.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
Find the angle which is equal to its complement.
Let one of the two equal complementary angles be x. ∴ x + x = 90° ⇒ 2x= 90° ⇒ x = 90°/2 = 45° Thus, 45° is equal to its complement. Class 7 Maths Chapter 5 Exercise 5.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
Let one of the two equal complementary angles be x.
∴ x + x = 90°
⇒ 2x= 90°
⇒ x = 90°/2 = 45°
Thus, 45° is equal to its complement.
Class 7 Maths Chapter 5 Exercise 5.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
Identify which of the following pairs of angles are complementary and which are supplementary: (i) 65°,115° (ii) 63°,27° (iii) 112°,68° (iv) 130°,50° (v) 45°,45° (vi) 80°,10°
If sum of two angles is 180° , then they are called supplementary angles. If sum of two angles is 90° , then they are called complementary angles. (i) 65° + 115° = 180° These are supplementary angles. (ii) 63° + 27° = 90° These are complementary angles. (iii) 112° + 68° = 180° These are supplementarRead more
If sum of two angles is 180° , then they are called supplementary angles.
If sum of two angles is 90° , then they are called complementary angles.
(i) 65° + 115° = 180° These are supplementary angles.
(ii) 63° + 27° = 90° These are complementary angles.
(iii) 112° + 68° = 180° These are supplementary angles.
(iv) 130° + 50° = 180° These are supplementary angles.
(v) 45° + 45° = 90° These are complementary angles.
(vi) 80° + 10° = 90° These are complementary angles.
Class 7 Maths Chapter 5 Exercise 5.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
Find the supplement of each of the following angles:
Supplementary angle = 180° - given angle (i) Supplement of 105° = 180° - 105° = 75° (ii) Supplement of 87° = 180° - 87° = 93° (iii) Supplement of 154° = 180° - 154° = 26° Class 7 Maths Chapter 5 Exercise 5.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapteRead more
Supplementary angle = 180° – given angle
(i) Supplement of 105° = 180° – 105° = 75°
(ii) Supplement of 87° = 180° – 87° = 93°
(iii) Supplement of 154° = 180° – 154° = 26°
Class 7 Maths Chapter 5 Exercise 5.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
Find the complement of each of the following angles:
Complementary angle = 90° - given angle (i) Complement of 20° = 90° - 20° = 70° (ii) Complement of 63° = 90° - 63° = 27° (iii) Complement of 57° = 90° - 57° = 33° Class 7 Maths Chapter 5 Exercise 5.1 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/
Complementary angle = 90° – given angle
(i) Complement of 20° = 90° – 20° = 70°
(ii) Complement of 63° = 90° – 63° = 27°
(iii) Complement of 57° = 90° – 57° = 33°
Class 7 Maths Chapter 5 Exercise 5.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-5/