Aadrita Gupta

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Aadrita Gupta

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Ashok0210

Asked: February 20, 2021In: Class 12 Physics

A cube of side b has a charge q at each of its vertices. Determine the potential and electric field due to this charge array at the centre of the cube.

Class 12 Physics, CBSE and UP Board, Electrostatic Potential and Capacitance, Additional Exercise,Chapter-2 Exercise 2.13, NCERT Solutions for Class 12 Physics

Ashok0210

Asked: February 20, 2021In: Class 12 Physics

A charge of 8 mC is located at the origin. Calculate the work done in taking a small charge of –2 × 10⁻ 9 C from a point P (0, 0, 3 cm) to a point Q (0, 4 cm, 0), via a point R (0, 6 cm, 9 cm).

Class 12 Physics, CBSE and UP Board, Electrostatic Potential and Capacitance, Additional Exercise, Chapter-2 Exercise 2.12, NCERT Solutions for Class 12 Physics

Ashok0210

Asked: February 20, 2021In: Class 12 Physics

Obtain the equivalent capacitance of the network in Fig. 2.35. For a 300 V supply, determine the charge and voltage across each capacitor.

Class 12 Physics, CBSE and UP Board, Electrostatic Potential and Capacitance, Additional Exercise,Chapter-2 Exercise 2.25, NCERT Solutions for Class 12 Physics

Ashok0210

Asked: February 20, 2021In: Class 12 Physics

Figure 2.34 shows a charge array known as an electric quadrupole. For a point on the axis of the quadrupole, obtain the dependence of potential on r for r/a >> 1, and contrast your results with that due to an electric dipole, and an electric monopole (i.e., a single charge).

Class 12 Physics, CBSE and UP Board, Electrostatic Potential and Capacitance, Additional Exercise,Chapter-2 Exercise 2.22, NCERT Solutions for Class 12 Physics

Ashok0210

Asked: February 20, 2021In: Class 12 Physics

If one of the two electrons of a H₂ molecule is removed, we get a hydrogen molecular ion H₂+. In the ground state of an H₂+, the two protons are separated by roughly 1.5 Å, and the electron is roughly 1 Å from each proton. Determine the potential energy of the system. Specify your choice of the zero of potential energy.

Class 12 Physics, CBSE and UP Board, Electrostatic Potential and Capacitance, Additional Exercise,Chapter-2 Exercise 2.19, NCERT Solutions for Class 12 Physics

Ashok0210

Asked: February 20, 2021In: Class 12 Physics

A spherical capacitor consists of two concentric spherical conductors, held in position by suitable insulating supports (Fig. 2.36). Show that the capacitance of a spherical capacitor is given by C=(4πε0 r₁r₂)/(r₁-r₂) where r₁ and r₂ are the radii of outer and inner spheres, respectively.

Class 12 Physics, CBSE and UP Board, Electrostatic Potential and Capacitance, Additional Exercise,Chapter-2 Exercise 2.29,NCERT Solutions for Class 12 Physics

Ashok0210

Asked: February 19, 2021In: Class 12 Physics

Two charges 5 × 10⁻8 C and –3 × 10⁻8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.

Class 12 Physics, CBSE and UP Board, Electrostatic Potential and Capacitance,Chapter-2 Exercise 2.1, NCERT Solutions for Class 12 Physics

Ashok0210

Asked: February 19, 2021In: Class 12 Physics

Two charges 2 μC and –2 μC are placed at points A and B 6 cm apart. (a) Identify an equipotential surface of the system. (b) What is the direction of the electric field at every point on this surface?

Class 12 Physics,CBSE and UP Board,Electrostatic Potential and Capacitance,Chapter-2 Exercise 2.3,NCERT Solutions for Class 12 Physics

Ashok0210

Asked: February 19, 2021In: Class 12 Physics

A regular hexagon of side 10 cm has a charge 5 μC at each of its vertices. Calculate the potential at the centre of the hexagon.

Class 12 Physics,CBSE and UP Board,Electrostatic Potential and Capacitance,Chapter-2 Exercise 2.2,NCERT Solutions for Class 12 Physics

Ashok0210

Asked: February 19, 2021In: Class 12 Physics

Two charges 5 × 10^–8 C and –3 × 10^–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.

Class 12 Physics ,CBSE and UP Board ,Electrostatic Potential and Capacitance,Chapter-2 Exercise 2.1,NCERT Solutions for Class 12 Physics

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Aadrita Gupta

A cube of side b has a charge q at each of its vertices. Determine the potential and electric field due to this charge array at the centre of the cube.

A charge of 8 mC is located at the origin. Calculate the work done in taking a small charge of –2 × 10⁻ 9 C from a point P (0, 0, 3 cm) to a point Q (0, 4 cm, 0), via a point R (0, 6 cm, 9 cm).

Obtain the equivalent capacitance of the network in Fig. 2.35. For a 300 V supply, determine the charge and voltage across each capacitor.

Figure 2.34 shows a charge array known as an electric quadrupole. For a point on the axis of the quadrupole, obtain the dependence of potential on r for r/a >> 1, and contrast your results with that due to an electric dipole, and an electric monopole (i.e., a single charge).

Two charges 5 × 10⁻8 C and –3 × 10⁻8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.

Two charges 2 μC and –2 μC are placed at points A and B 6 cm apart. (a) Identify an equipotential surface of the system. (b) What is the direction of the electric field at every point on this surface?

A regular hexagon of side 10 cm has a charge 5 μC at each of its vertices. Calculate the potential at the centre of the hexagon.

Two charges 5 × 10^–8 C and –3 × 10^–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.

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