(a) 578 x 161 578 round off to 600 161 round off to 200 The estimated product = 600 x 200 = 1,20,000 (b) 5281 x 3491 5281 round of to 5,000 3491 round off to 3,500 The estimated product = 5,000 x 3,500 = 1,75,00,000 (c) 1291 x 592 1291 round off to 1300 592 round off to 600 The estimated product = 1Read more
(a) 578 x 161
578 round off to 600
161 round off to 200
The estimated product = 600 x 200 = 1,20,000
(b) 5281 x 3491
5281 round of to 5,000
3491 round off to 3,500
The estimated product = 5,000 x 3,500 = 1,75,00,000
(c) 1291 x 592
1291 round off to 1300
592 round off to 600
The estimated product = 1300 x 600 = 7,80,000
(d) 9250 x 29
9250 round off to 10,000
229 round off to 30
The estimated product = 10,000 x 30 = 3,00,000
(a) 439 round off to 400 334 round off to 300 4317 round off to 4300 Estimated sum = 5000 (b) 108734 round off to 108700 47599 round off to 47600 Estimated difference = 61100 (c) 8325 round off to 8300 491 round off to 500 Estimated difference = 7800 (d) 489348 round off to 489300 48365 round off toRead more
(a) 439 round off to 400
334 round off to 300
4317 round off to 4300
Estimated sum = 5000
(b) 108734 round off to 108700
47599 round off to 47600
Estimated difference = 61100
(c) 8325 round off to 8300
491 round off to 500
Estimated difference = 7800
(d) 489348 round off to 489300
48365 round off to 48400
Estimated difference = 440900
(a) 730 round off to 700 998 round off to 1000 Estimated sum = 1700 (b) 796 round off to 800 314 round off to 300 Estimated sum = 500 (c) 12904 round off to 13000 2888 round off to 3000 Estimated sum = 16000 (d) 28292 round off to 28000 21496 round off to 21000 Estimated difference= 7000 https://wwwRead more
(a) 730 round off to 700
998 round off to 1000
Estimated sum = 1700
(b) 796 round off to 800
314 round off to 300
Estimated sum = 500
(c) 12904 round off to 13000
2888 round off to 3000
Estimated sum = 16000
(d) 28292 round off to 28000
21496 round off to 21000
Estimated difference= 7000
Capacity of curd in a vessel = 4 litres 500 ml = 4 x 1000 ml + 500 ml = 4500 ml Capacity of one glass = 25 ml Number of glasses can be filled = 4500 ÷ 25 Therefore, 180 glasses can be filled by curd. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
Capacity of curd in a vessel = 4 litres 500 ml = 4 x 1000 ml + 500 ml = 4500 ml
Capacity of one glass = 25 ml
Number of glasses can be filled = 4500 ÷ 25
Therefore, 180 glasses can be filled by curd.
Distance between school and home = 1.875 km Distance between home and school = + 1.875 km Total distance covered in one day = 3.750 km Distance covered in six days = 3.750 x 6 = 22.500 km Therefore, 22 km 500 m distance covered in six days. https://www.tiwariacademy.com/ncert-solutions/class-6/mathsRead more
Distance between school and home = 1.875 km
Distance between home and school = + 1.875 km
Total distance covered in one day = 3.750 km
Distance covered in six days = 3.750 x 6 = 22.500 km
Therefore, 22 km 500 m distance covered in six days.
The weight of one box = 4 kg 500 g = 4 x 1000 g + 500 g = 4500 g Maximum load can be loaded in van = 800 kg = 800 x 1000 g = 800000 g Number of boxes = 800000 ÷ 4500 Therefore, 177 boxes can be loaded. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
The weight of one box = 4 kg 500 g = 4 x 1000 g + 500 g = 4500 g
Maximum load can be loaded in van = 800 kg = 800 x 1000 g = 800000 g
Number of boxes = 800000 ÷ 4500
Cloth required to stitch one shirt = 2 m 15 cm = 2 x 100 cm + 15 cm = 215 cm Length of cloth = 40 m = 40 x 100 cm = 4000 cm Number of shirts can be stitched = 4000 ÷ 215 Therefore, 18 shirts can be stitched and 130 cm (1 m 30 cm) cloth will remain. https://www.tiwariacademy.com/ncert-solutions/classRead more
Cloth required to stitch one shirt = 2 m 15 cm
= 2 x 100 cm + 15 cm
= 215 cm
Length of cloth = 40 m = 40 x 100 cm = 4000 cm
Number of shirts can be stitched = 4000 ÷ 215
Therefore, 18 shirts can be stitched and 130 cm (1 m 30 cm) cloth will remain.
Cost of one radio = ₹ 1200 Cost of 40 radios = 1200 x 40 = ₹ 48,000 Now, Total money with merchant = ₹ 78,592 Money spent by her = – ₹ 48,000 Money left with her = ₹ 30,592 Therefore, ₹ 30,592 will remain with her after the purchase. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapteRead more
Cost of one radio = ₹ 1200
Cost of 40 radios = 1200 x 40 = ₹ 48,000
Now,
Total money with merchant = ₹ 78,592
Money spent by her = – ₹ 48,000
Money left with her = ₹ 30,592
Therefore, ₹ 30,592 will remain with her after the purchase.
Number of screws manufactured in one day = 2,825 Number of days in the month of January (31 days) = 2,825 x 31 = 87,575 Therefore, the machine produced 87,575 screws in the month of January. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
Number of screws manufactured in one day = 2,825
Number of days in the month of January (31 days) = 2,825 x 31
= 87,575
Therefore, the machine produced 87,575 screws in the month of January.
Estimate the following products using general rule: (a) 578 x 161 (b) 5281 x 3491 (c) 1291 x 592 (d) 9250 x 29
(a) 578 x 161 578 round off to 600 161 round off to 200 The estimated product = 600 x 200 = 1,20,000 (b) 5281 x 3491 5281 round of to 5,000 3491 round off to 3,500 The estimated product = 5,000 x 3,500 = 1,75,00,000 (c) 1291 x 592 1291 round off to 1300 592 round off to 600 The estimated product = 1Read more
(a) 578 x 161
578 round off to 600
161 round off to 200
The estimated product = 600 x 200 = 1,20,000
(b) 5281 x 3491
5281 round of to 5,000
3491 round off to 3,500
The estimated product = 5,000 x 3,500 = 1,75,00,000
(c) 1291 x 592
1291 round off to 1300
592 round off to 600
The estimated product = 1300 x 600 = 7,80,000
(d) 9250 x 29
9250 round off to 10,000
229 round off to 30
The estimated product = 10,000 x 30 = 3,00,000
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
See lessGive a rough estimate (by rounding off to nearest hundreds) and also a closer estimate (by rounding off to nearest tens): (a) 439 + 334 + 4317 (b) 1,08,737 – 47,599 (c) 8325 – 491 (d) 4,89,348 – 48,365
(a) 439 round off to 400 334 round off to 300 4317 round off to 4300 Estimated sum = 5000 (b) 108734 round off to 108700 47599 round off to 47600 Estimated difference = 61100 (c) 8325 round off to 8300 491 round off to 500 Estimated difference = 7800 (d) 489348 round off to 489300 48365 round off toRead more
(a) 439 round off to 400
334 round off to 300
4317 round off to 4300
Estimated sum = 5000
(b) 108734 round off to 108700
47599 round off to 47600
Estimated difference = 61100
(c) 8325 round off to 8300
491 round off to 500
Estimated difference = 7800
(d) 489348 round off to 489300
48365 round off to 48400
Estimated difference = 440900
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
See lessEstimate each of the following using general rule: (a) 730 + 998 (b) 796 – 314 (c) 12,904 + 2,888 (d) 28,292 – 21,496
(a) 730 round off to 700 998 round off to 1000 Estimated sum = 1700 (b) 796 round off to 800 314 round off to 300 Estimated sum = 500 (c) 12904 round off to 13000 2888 round off to 3000 Estimated sum = 16000 (d) 28292 round off to 28000 21496 round off to 21000 Estimated difference= 7000 https://wwwRead more
(a) 730 round off to 700
998 round off to 1000
Estimated sum = 1700
(b) 796 round off to 800
314 round off to 300
Estimated sum = 500
(c) 12904 round off to 13000
2888 round off to 3000
Estimated sum = 16000
(d) 28292 round off to 28000
21496 round off to 21000
Estimated difference= 7000
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
See lessA vessel has 4 litres and 500 ml of curd. In how many glasses each of 25 ml capacity, can it be filled?
Capacity of curd in a vessel = 4 litres 500 ml = 4 x 1000 ml + 500 ml = 4500 ml Capacity of one glass = 25 ml Number of glasses can be filled = 4500 ÷ 25 Therefore, 180 glasses can be filled by curd. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
Capacity of curd in a vessel = 4 litres 500 ml = 4 x 1000 ml + 500 ml = 4500 ml
Capacity of one glass = 25 ml
Number of glasses can be filled = 4500 ÷ 25
Therefore, 180 glasses can be filled by curd.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
See lessThe distance between the school and the house of a student’s house is 1 km 875 m. Every day she walks both ways. Find the total distance covered by her in six days.
Distance between school and home = 1.875 km Distance between home and school = + 1.875 km Total distance covered in one day = 3.750 km Distance covered in six days = 3.750 x 6 = 22.500 km Therefore, 22 km 500 m distance covered in six days. https://www.tiwariacademy.com/ncert-solutions/class-6/mathsRead more
Distance between school and home = 1.875 km
Distance between home and school = + 1.875 km
Total distance covered in one day = 3.750 km
Distance covered in six days = 3.750 x 6 = 22.500 km
Therefore, 22 km 500 m distance covered in six days.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
See lessMedicine is packed in boxes, each weighing 4 kg 500 g. How many such boxes can be loaded in a can which cannot carry beyond 800 kg?
The weight of one box = 4 kg 500 g = 4 x 1000 g + 500 g = 4500 g Maximum load can be loaded in van = 800 kg = 800 x 1000 g = 800000 g Number of boxes = 800000 ÷ 4500 Therefore, 177 boxes can be loaded. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
The weight of one box = 4 kg 500 g = 4 x 1000 g + 500 g = 4500 g
Maximum load can be loaded in van = 800 kg = 800 x 1000 g = 800000 g
Number of boxes = 800000 ÷ 4500
Therefore, 177 boxes can be loaded.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
See lessTo stitch a shirt 2 m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain?
Cloth required to stitch one shirt = 2 m 15 cm = 2 x 100 cm + 15 cm = 215 cm Length of cloth = 40 m = 40 x 100 cm = 4000 cm Number of shirts can be stitched = 4000 ÷ 215 Therefore, 18 shirts can be stitched and 130 cm (1 m 30 cm) cloth will remain. https://www.tiwariacademy.com/ncert-solutions/classRead more
Cloth required to stitch one shirt = 2 m 15 cm
= 2 x 100 cm + 15 cm
= 215 cm
Length of cloth = 40 m = 40 x 100 cm = 4000 cm
Number of shirts can be stitched = 4000 ÷ 215
Therefore, 18 shirts can be stitched and 130 cm (1 m 30 cm) cloth will remain.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
See lessA student multiplied 7236 by 65 instead of multiplying by 56. By how much was his answer greater than the correct answer?
Wrong answer = 7236 x 65 7236 x 65 36180 43416 x 470340 Correct answer = 7236 x 56 7236 x 56 43416 36180 x 405216 Difference in answers = 470340 – 405216 = 65,124 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
Wrong answer = 7236 x 65
7236
x 65
36180
43416 x
470340
Correct answer = 7236 x 56
7236
x 56
43416
36180 x
405216
Difference in answers = 470340 – 405216
= 65,124
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
See lessA merchant had ₹78,592 with her. She placed an order for purchasing 40 radio sets at ₹1,200 each. How much money will remain with her after the purchase?
Cost of one radio = ₹ 1200 Cost of 40 radios = 1200 x 40 = ₹ 48,000 Now, Total money with merchant = ₹ 78,592 Money spent by her = – ₹ 48,000 Money left with her = ₹ 30,592 Therefore, ₹ 30,592 will remain with her after the purchase. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapteRead more
Cost of one radio = ₹ 1200
Cost of 40 radios = 1200 x 40 = ₹ 48,000
Now,
Total money with merchant = ₹ 78,592
Money spent by her = – ₹ 48,000
Money left with her = ₹ 30,592
Therefore, ₹ 30,592 will remain with her after the purchase.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
See lessA machine, on an average, manufactures 2,825 screws a day. How many screws did it produce in the month of January 2006?
Number of screws manufactured in one day = 2,825 Number of days in the month of January (31 days) = 2,825 x 31 = 87,575 Therefore, the machine produced 87,575 screws in the month of January. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
Number of screws manufactured in one day = 2,825
Number of days in the month of January (31 days) = 2,825 x 31
= 87,575
Therefore, the machine produced 87,575 screws in the month of January.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
See less