The weight of one box = 4 kg 500 g = 4 x 1000 g + 500 g = 4500 g Maximum load can be loaded in van = 800 kg = 800 x 1000 g = 800000 g Number of boxes = 800000 ÷ 4500 Therefore, 177 boxes can be loaded. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
The weight of one box = 4 kg 500 g = 4 x 1000 g + 500 g = 4500 g
Maximum load can be loaded in van = 800 kg = 800 x 1000 g = 800000 g
Number of boxes = 800000 ÷ 4500
Cloth required to stitch one shirt = 2 m 15 cm = 2 x 100 cm + 15 cm = 215 cm Length of cloth = 40 m = 40 x 100 cm = 4000 cm Number of shirts can be stitched = 4000 ÷ 215 Therefore, 18 shirts can be stitched and 130 cm (1 m 30 cm) cloth will remain. https://www.tiwariacademy.com/ncert-solutions/classRead more
Cloth required to stitch one shirt = 2 m 15 cm
= 2 x 100 cm + 15 cm
= 215 cm
Length of cloth = 40 m = 40 x 100 cm = 4000 cm
Number of shirts can be stitched = 4000 ÷ 215
Therefore, 18 shirts can be stitched and 130 cm (1 m 30 cm) cloth will remain.
Cost of one radio = ₹ 1200 Cost of 40 radios = 1200 x 40 = ₹ 48,000 Now, Total money with merchant = ₹ 78,592 Money spent by her = – ₹ 48,000 Money left with her = ₹ 30,592 Therefore, ₹ 30,592 will remain with her after the purchase. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapteRead more
Cost of one radio = ₹ 1200
Cost of 40 radios = 1200 x 40 = ₹ 48,000
Now,
Total money with merchant = ₹ 78,592
Money spent by her = – ₹ 48,000
Money left with her = ₹ 30,592
Therefore, ₹ 30,592 will remain with her after the purchase.
Number of screws manufactured in one day = 2,825 Number of days in the month of January (31 days) = 2,825 x 31 = 87,575 Therefore, the machine produced 87,575 screws in the month of January. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
Number of screws manufactured in one day = 2,825
Number of days in the month of January (31 days) = 2,825 x 31
= 87,575
Therefore, the machine produced 87,575 screws in the month of January.
Medicine is packed in boxes, each weighing 4 kg 500 g. How many such boxes can be loaded in a can which cannot carry beyond 800 kg?
The weight of one box = 4 kg 500 g = 4 x 1000 g + 500 g = 4500 g Maximum load can be loaded in van = 800 kg = 800 x 1000 g = 800000 g Number of boxes = 800000 ÷ 4500 Therefore, 177 boxes can be loaded. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
The weight of one box = 4 kg 500 g = 4 x 1000 g + 500 g = 4500 g
Maximum load can be loaded in van = 800 kg = 800 x 1000 g = 800000 g
Number of boxes = 800000 ÷ 4500
Therefore, 177 boxes can be loaded.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
See lessTo stitch a shirt 2 m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain?
Cloth required to stitch one shirt = 2 m 15 cm = 2 x 100 cm + 15 cm = 215 cm Length of cloth = 40 m = 40 x 100 cm = 4000 cm Number of shirts can be stitched = 4000 ÷ 215 Therefore, 18 shirts can be stitched and 130 cm (1 m 30 cm) cloth will remain. https://www.tiwariacademy.com/ncert-solutions/classRead more
Cloth required to stitch one shirt = 2 m 15 cm
= 2 x 100 cm + 15 cm
= 215 cm
Length of cloth = 40 m = 40 x 100 cm = 4000 cm
Number of shirts can be stitched = 4000 ÷ 215
Therefore, 18 shirts can be stitched and 130 cm (1 m 30 cm) cloth will remain.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
See lessA student multiplied 7236 by 65 instead of multiplying by 56. By how much was his answer greater than the correct answer?
Wrong answer = 7236 x 65 7236 x 65 36180 43416 x 470340 Correct answer = 7236 x 56 7236 x 56 43416 36180 x 405216 Difference in answers = 470340 – 405216 = 65,124 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
Wrong answer = 7236 x 65
7236
x 65
36180
43416 x
470340
Correct answer = 7236 x 56
7236
x 56
43416
36180 x
405216
Difference in answers = 470340 – 405216
= 65,124
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
See lessA merchant had ₹78,592 with her. She placed an order for purchasing 40 radio sets at ₹1,200 each. How much money will remain with her after the purchase?
Cost of one radio = ₹ 1200 Cost of 40 radios = 1200 x 40 = ₹ 48,000 Now, Total money with merchant = ₹ 78,592 Money spent by her = – ₹ 48,000 Money left with her = ₹ 30,592 Therefore, ₹ 30,592 will remain with her after the purchase. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapteRead more
Cost of one radio = ₹ 1200
Cost of 40 radios = 1200 x 40 = ₹ 48,000
Now,
Total money with merchant = ₹ 78,592
Money spent by her = – ₹ 48,000
Money left with her = ₹ 30,592
Therefore, ₹ 30,592 will remain with her after the purchase.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
See lessA machine, on an average, manufactures 2,825 screws a day. How many screws did it produce in the month of January 2006?
Number of screws manufactured in one day = 2,825 Number of days in the month of January (31 days) = 2,825 x 31 = 87,575 Therefore, the machine produced 87,575 screws in the month of January. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
Number of screws manufactured in one day = 2,825
Number of days in the month of January (31 days) = 2,825 x 31
= 87,575
Therefore, the machine produced 87,575 screws in the month of January.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-1/
See less