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If we multiply a number by 5/2 and add 2/3 to the product, we get –7/12. Find the number.
Let the required number be represented by the variable x. Translating the word problem into a mathematical equation results in 5/2 x + 2/3 = -7/12. To solve for x, subtract 2/3 from both sides of the expression, making 5/2 x = -7/12 - 8/12, which combines to -15/12. Multiplying both sides by 2/5 isoRead more
Let the required number be represented by the variable x. Translating the word problem into a mathematical equation results in 5/2 x + 2/3 = -7/12. To solve for x, subtract 2/3 from both sides of the expression, making 5/2 x = -7/12 – 8/12, which combines to -15/12. Multiplying both sides by 2/5 isolates the variable, resulting in x = (-15/12) multiplied by (2/5), which simplifies perfectly to -1/2.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessIf you have rupees 800 and you save rupees 250 every month, find the amount you have after (i) 6 months (ii) 2 years. Express this as a linear pattern.
The savings situation forms a linear pattern represented by the equation y = 800 + 250m, where m represents the number of months passed. For part (i), substituting m = 6 months into the expression results in 800 + 250(6) = 2300 rupees. For part (ii), 2 years is equivalent to 24 months. SubstitutingRead more
The savings situation forms a linear pattern represented by the equation y = 800 + 250m, where m represents the number of months passed. For part (i), substituting m = 6 months into the expression results in 800 + 250(6) = 2300 rupees. For part (ii), 2 years is equivalent to 24 months. Substituting m = 24 into the formula results in 800 + 250(24) = 6800 rupees altogether.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessThe digits of a two-digit number differ by 3. If the digits are interchanged and the resulting number is added to the original number, we get 143. Find both the numbers.
Let the digits be x and y. Since they differ by 3, we can assume y = x - 3. The original two-digit number is 10x + y, which simplifies to 11x - 3. Interchanging the digits creates the new number 10y + x, which simplifies to 11x - 30. Adding these two expressions gives (11x - 3) + (11x - 30) = 143. TRead more
Let the digits be x and y. Since they differ by 3, we can assume y = x – 3. The original two-digit number is 10x + y, which simplifies to 11x – 3. Interchanging the digits creates the new number 10y + x, which simplifies to 11x – 30. Adding these two expressions gives (11x – 3) + (11x – 30) = 143. This reduces to 22x – 33 = 143, meaning 22x = 176, so x = 8. The numbers are 85 and 58.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessThe work done by a body on the application of a constant force is the product of the constant force and the distance travelled by the body in the direction of the force. Express this in the form of a linear equation in two variables (work w and distance d) and draw its graph by taking the constant force as 3 units. What is the work done when the distance travelled is 2 units? Verify it by plotting it on the graph.
The relationship is expressed as work equals force times distance, creating the linear equation w = 3d with a constant force of 3 units. To find the work done when the distance travelled is 2 units, substitute d = 2 into the formula, yielding w = 3(2) = 6 units of work. On a standard coordinate grapRead more
The relationship is expressed as work equals force times distance, creating the linear equation w = 3d with a constant force of 3 units. To find the work done when the distance travelled is 2 units, substitute d = 2 into the formula, yielding w = 3(2) = 6 units of work. On a standard coordinate graph with distance on the horizontal axis and work on the vertical axis, plotting the linear path through (0,0) and (2,6) verifies the result.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessA merchant in the port city of Lothal is exchanging bags of spices for copper ingots. He receives 15 ingots for every 2 bags of spices. If he brings 12 bags of spices to the market, how many copper ingots will he leave with?
The exchange rate between the goods establishes a direct proportional relationship. The merchant receives 15 copper ingots for every 2 bags of spices. Since he brings a total of 12 bags of spices to the market, we can find the number of pairs by dividing 12 by 2, which gives 6 pairs. Multiplying theRead more
The exchange rate between the goods establishes a direct proportional relationship. The merchant receives 15 copper ingots for every 2 bags of spices. Since he brings a total of 12 bags of spices to the market, we can find the number of pairs by dividing 12 by 2, which gives 6 pairs. Multiplying these 6 units by the 15 ingots per pair results in a total of 90 copper ingots.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 3 The world of numbers (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-3/
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