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  1. Infinitely many circles can pass through two given points. Among them, the smallest circle is formed when the two points become the endpoints of the diameter. In this case, the centre lies at the midpoint of the line segment joining the points. Therefore, the least possible radius is equal to half tRead more

    Infinitely many circles can pass through two given points. Among them, the smallest circle is formed when the two points become the endpoints of the diameter. In this case, the centre lies at the midpoint of the line segment joining the points. Therefore, the least possible radius is equal to half the distance between the two given points.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/

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  2. No point can be equally distant from three collinear points. The perpendicular bisectors of AB and BC remain parallel, so they never meet to form a circumcentre. Without a common circumcentre, a circle cannot pass through all three collinear points. Also, a straight line can intersect a circle at aRead more

    No point can be equally distant from three collinear points. The perpendicular bisectors of AB and BC remain parallel, so they never meet to form a circumcentre. Without a common circumcentre, a circle cannot pass through all three collinear points. Also, a straight line can intersect a circle at a maximum of two distinct points, never at three distinct points.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/

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  3. Yes, it is possible to construct other triangles congruent to the given triangle on the same circumcircle. These triangles have identical side lengths and angles but occupy different positions on the circle. Although their orientation changes, they remain congruent and share the same circumcircle.Read more

    Yes, it is possible to construct other triangles congruent to the given triangle on the same circumcircle. These triangles have identical side lengths and angles but occupy different positions on the circle. Although their orientation changes, they remain congruent and share the same circumcircle.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/

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    • 208
  4. We analyze the given conditional equation by moving terms to one side, which gives the simplified statement x - 2y - 6 = 0. Now, we rewrite the main polynomial expression using these exact bases, formatting it as x cube + (-2y) cube + (-6) cube minus 3 times x times (-2y) times (-6). According to alRead more

    We analyze the given conditional equation by moving terms to one side, which gives the simplified statement x – 2y – 6 = 0. Now, we rewrite the main polynomial expression using these exact bases, formatting it as x cube + (-2y) cube + (-6) cube minus 3 times x times (-2y) times (-6). According to algebraic conditions, when the sum of three base terms is equal to zero, the sum of their individual cubes minus three times their product automatically equals zero. Thus, the answer is 0.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/

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  5. We rearrange the given polynomial expression into the standard conditional cubic identity template. We can rewrite the mathematical statement as x cube + y cube + (4) cube minus 3 times x times y times 4. This matches the identity where the three components are x, y and 4. The identity states that iRead more

    We rearrange the given polynomial expression into the standard conditional cubic identity template. We can rewrite the mathematical statement as x cube + y cube + (4) cube minus 3 times x times y times 4. This matches the identity where the three components are x, y and 4. The identity states that if the sum of these three numbers equals zero, the total expression equals zero. Since x + y = -4, the sum x + y + 4 equals zero, making the value 0.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/

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