No. There is no point that is equally distant from three collinear points. The perpendicular bisectors of AB and BC are parallel and never intersect. Therefore, no circle can pass through three collinear points.
A, B and C are three collinear points. Can you find a point P such that PA = PB = PC? What can you say about the perpendicular bisectors of AB and BC? Draw and check. Can you show that for three collinear points A, B and C, the perpendicular bisector of AB and BC are parallel? Is it possible for a circle to pass through collinear points? Can you draw a line that cuts a given circle in three distinct points?
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No point can be equally distant from three collinear points. The perpendicular bisectors of AB and BC remain parallel, so they never meet to form a circumcentre. Without a common circumcentre, a circle cannot pass through all three collinear points. Also, a straight line can intersect a circle at a maximum of two distinct points, never at three distinct points.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/