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The coach of a cricket team buys 7 bats and 6 balls for ₹8880. Later, she buys 3 bats and 5 balls for ₹4000. Find the cost of each bat and each ball.
Let the cost of one bat be ₹x and one ball be ₹y. The conditions give 7x + 6y = 8880 and 3x + 5y = 4000. Multiplying the first equation by 5 and the second by 6 gives 35x + 30y = 44400 and 18x + 30y = 24000. Subtracting them eliminates y, producing 17x = 20400, giving x = 1200. Substituting x givesRead more
Let the cost of one bat be ₹x and one ball be ₹y. The conditions give 7x + 6y = 8880 and 3x + 5y = 4000. Multiplying the first equation by 5 and the second by 6 gives 35x + 30y = 44400 and 18x + 30y = 24000. Subtracting them eliminates y, producing 17x = 20400, giving x = 1200. Substituting x gives y = 80. A bat costs ₹1200 and a ball ₹80.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-13/
See lessThe taxi charges in a city consist of a fixed charge together with the charge for the distance covered for every km. For a distance of 10 km, the total amount paid is ₹155 and for a journey of 15 km, the total amount paid is ₹220. What is the fixed charge and the charge per km? How much does a person have to pay for travelling a distance of 25 km?
Let the fixed charge be ₹x and running charge be ₹y per kilometre. The equations are x + 10y = 155 and x + 15y = 220. Subtracting the first equation from the second eliminates x, giving 5y = 65, which means y = 13. Substituting into the first equation yields x + 130 = 155, so x = 25. For 25 km, totaRead more
Let the fixed charge be ₹x and running charge be ₹y per kilometre. The equations are x + 10y = 155 and x + 15y = 220. Subtracting the first equation from the second eliminates x, giving 5y = 65, which means y = 13. Substituting into the first equation yields x + 130 = 155, so x = 25. For 25 km, total fare is x + 25y = 25 + 25(13) = ₹350.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-13/
See lessA fraction becomes equal to 9/11 if 2 is added to both the numerator and the denominator. If 3 is added to both the numerator and the denominator, it becomes equal to 5/6. Find the fraction.
Let the required fraction be x/y. The first condition gives (x + 2)/(y + 2) = 9/11, which simplifies to 11x - 9y = -4. The second condition gives (x + 3)/(y + 3) = 5/6, which simplifies to 6x - 5y = -3. Multiplying the first equation by 5 and the second by 9, then subtracting them, eliminates y to yRead more
Let the required fraction be x/y. The first condition gives (x + 2)/(y + 2) = 9/11, which simplifies to 11x – 9y = -4. The second condition gives (x + 3)/(y + 3) = 5/6, which simplifies to 6x – 5y = -3. Multiplying the first equation by 5 and the second by 9, then subtracting them, eliminates y to yield x = 7. Substituting x = 7 gives y = 9. Thus, the fraction is 7/9.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-13/
See lessIf we add 1 to the numerator and subtract 1 from the denominator, a fraction reduces to 1. It becomes equal to 1/2 if we add 1 only to the denominator. What is the fraction?
Let the required fraction be x/y. According to the first condition, (x + 1)/(y - 1) = 1, which cross-multiplies to x - y = -2. According to the second condition, x/(y + 1) = 1/2, which simplifies to 2x - y = 1. Subtracting the first equation from the second eliminates y, giving x = 3. Substituting xRead more
Let the required fraction be x/y. According to the first condition, (x + 1)/(y – 1) = 1, which cross-multiplies to x – y = -2. According to the second condition, x/(y + 1) = 1/2, which simplifies to 2x – y = 1. Subtracting the first equation from the second eliminates y, giving x = 3. Substituting x = 3 into x – y = -2 yields y = 5. Hence, the fraction is 3/5.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-13/
See lessFive years ago, Nuri was thrice as old as Sonu. Ten years later, Nuri will be twice as old as Sonu. How old are Nuri and Sonu?
Let the present ages of Nuri and Sonu be x and y years respectively. Five years ago, (x - 5) = 3(y - 5), which simplifies to x - 3y = -10. Ten years later, (x + 10) = 2(y + 10), which simplifies to x - 2y = 10. Subtracting the first equation from the second eliminates x and gives y = 20. SubstitutinRead more
Let the present ages of Nuri and Sonu be x and y years respectively. Five years ago, (x – 5) = 3(y – 5), which simplifies to x – 3y = -10. Ten years later, (x + 10) = 2(y + 10), which simplifies to x – 2y = 10. Subtracting the first equation from the second eliminates x and gives y = 20. Substituting y = 20 yields x = 50. Therefore, Nuri is 50 and Sonu is 20 years old.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-13/
See less