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  1. Yes. If ∠AXB = ∠AYB and X and Y lie on the same side of AB, then both points lie on the same segment of the circle. The angle subtended by a chord at points on the same segment is equal. Hence, equal angles are obtained at X and Y. This follows directly from the property that an arc subtends equal aRead more

    Yes. If ∠AXB = ∠AYB and X and Y lie on the same side of AB, then both points lie on the same segment of the circle. The angle subtended by a chord at points on the same segment is equal. Hence, equal angles are obtained at X and Y. This follows directly from the property that an arc subtends equal angles at points on the remaining part of the circle.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/

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  2. Yes. Since ∠AXB = ∠AYB, the line segment AB subtends equal angles at X and Y. If X and Y are on the same side of AB, Theorem 10 states that the four points A, B, X and Y lie on a circle. Therefore, the circle passing through A, B and X will also pass through Y. Thus, A, B, X and Y are concyclic.Read more

    Yes. Since ∠AXB = ∠AYB, the line segment AB subtends equal angles at X and Y. If X and Y are on the same side of AB, Theorem 10 states that the four points A, B, X and Y lie on a circle. Therefore, the circle passing through A, B and X will also pass through Y. Thus, A, B, X and Y are concyclic.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/

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  3. Since A, B, C and D lie on the same circle, ABCD is a cyclic quadrilateral. In a cyclic quadrilateral, the sum of two opposite angles is 180°. Here, ∠D = 100° and ∠B = x. Therefore, x + 100° = 180° x = 180° - 100° x = 80° Hence, the value of x is 80°.   For more NCERT Solutions for Class 9 MathRead more

    Since A, B, C and D lie on the same circle, ABCD is a cyclic quadrilateral. In a cyclic quadrilateral, the sum of two opposite angles is 180°.

    Here, ∠D = 100° and ∠B = x.

    Therefore,

    x + 100° = 180°

    x = 180° – 100°

    x = 80°

    Hence, the value of x is 80°.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/

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  4. Let the perpendicular distance from the centre to the chord be 5 cm and the radius be 13 cm. The perpendicular from the centre to a chord bisects the chord. Thus, we get a right triangle with hypotenuse 13 cm and one side 5 cm. Half chord = √(13² - 5²) = √144 = 12 cm Therefore, length of the chord =Read more

    Let the perpendicular distance from the centre to the chord be 5 cm and the radius be 13 cm. The perpendicular from the centre to a chord bisects the chord. Thus, we get a right triangle with hypotenuse 13 cm and one side 5 cm.

    Half chord = √(13² – 5²) = √144 = 12 cm

    Therefore, length of the chord = 2 × 12 = 24 cm.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/

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  5. Draw perpendiculars from the centre to both chords. The radii are equal, and the perpendicular distances are also equal. Using the Baudhāyana–Pythagoras Theorem, the half-lengths of both chords are equal. Doubling these equal half-chords gives equal full chord lengths. Therefore, the two chords areRead more

    Draw perpendiculars from the centre to both chords. The radii are equal, and the perpendicular distances are also equal. Using the Baudhāyana–Pythagoras Theorem, the half-lengths of both chords are equal. Doubling these equal half-chords gives equal full chord lengths. Therefore, the two chords are equal, proving that AB = GF.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/

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