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  1. The total distance travelled is 200 + 200 = 400 km, while the total time taken is 3 + 2 = 5 hours. Therefore, average speed = 400/5 = 80 km/h. Since the vehicle travels 200 km north and then 200 km south, it returns to the starting point. Hence, displacement is zero and average velocity = 0/5 = 0 kmRead more

    The total distance travelled is 200 + 200 = 400 km, while the total time taken is 3 + 2 = 5 hours. Therefore, average speed = 400/5 = 80 km/h. Since the vehicle travels 200 km north and then 200 km south, it returns to the starting point. Hence, displacement is zero and average velocity = 0/5 = 0 km/h.

     

    For more NCERT Solutions of Class 9 Science Exploration Chapter 4 Describing Motion Around Us Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-4/

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  2. Yes, the ball’s motion is straight-line motion because it moves along the straight inclined track from O to D. Taking O as the origin, its motion can be represented using a horizontal line showing its successive positions. Since the ball continuously moves in the same direction without changing itsRead more

    Yes, the ball’s motion is straight-line motion because it moves along the straight inclined track from O to D. Taking O as the origin, its motion can be represented using a horizontal line showing its successive positions. Since the ball continuously moves in the same direction without changing its path, the total distance travelled and the magnitude of displacement are equal at positions A, B, C and D.

     

    For more NCERT Solutions of Class 9 Science Exploration Chapter 4 Describing Motion Around Us Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-4/

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    • 230
  3. Fuel used in a vehicle depends on the total distance travelled rather than its displacement. Fuel is consumed as the vehicle moves through the actual path covered. For example, if a vehicle travels from home to a place and returns home, its displacement is zero, but it has travelled a certain distanRead more

    Fuel used in a vehicle depends on the total distance travelled rather than its displacement. Fuel is consumed as the vehicle moves through the actual path covered. For example, if a vehicle travels from home to a place and returns home, its displacement is zero, but it has travelled a certain distance and consumed fuel. Thus, fuel consumption is related to distance travelled, not displacement.

     

    For more NCERT Solutions of Class 9 Science Exploration Chapter 4 Describing Motion Around Us Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-4/

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    • 194
  4. No, we cannot conclude that CD = 2AB. The distance of chord AB from the centre being twice the distance of chord CD does not mean that CD is twice AB. According to Theorem 8, the longer chord is closer to the centre, but the relationship between chord length and distance is not directly proportionalRead more

    No, we cannot conclude that CD = 2AB. The distance of chord AB from the centre being twice the distance of chord CD does not mean that CD is twice AB. According to Theorem 8, the longer chord is closer to the centre, but the relationship between chord length and distance is not directly proportional. Chord length also depends on the radius of the circle. Therefore, the given distances alone are not sufficient to establish CD = 2AB.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/

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  5. To find this product using an identity approach, we can break down both numbers relative to base tens, writing them as the binomial product (20 - 2)(30 - 1). Applying the distributive expansion gives 20 times 30 minus 20 times 1 minus 2 times 30 plus 2 times 1. This evaluates to 600 minus 20 minus 6Read more

    To find this product using an identity approach, we can break down both numbers relative to base tens, writing them as the binomial product (20 – 2)(30 – 1). Applying the distributive expansion gives 20 times 30 minus 20 times 1 minus 2 times 30 plus 2 times 1. This evaluates to 600 minus 20 minus 60 plus 2. Solving this basic arithmetic sequence yields 522.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/

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