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  1. No, objects A and B never have equal velocity. In a position-time graph, the slope of the graph represents velocity. The graphs of A and B have different slopes throughout their motion. Although their position-time graphs intersect, this only means that they are at the same position at that instant.Read more

    No, objects A and B never have equal velocity. In a position-time graph, the slope of the graph represents velocity. The graphs of A and B have different slopes throughout their motion. Although their position-time graphs intersect, this only means that they are at the same position at that instant. It does not mean that their velocities are equal. Therefore, their velocities are never equal.

     

    For more NCERT Solutions of Class 9 Science Exploration Chapter 4 Describing Motion Around Us Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-4/

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  2. For the motorbike, initial velocity u = 28 m s⁻¹, final velocity v = 0 and distance s = 98 m. Using v² = u² + 2as: 0 = 28² + 2(a)(98), giving a = −4 m s⁻². Using v = u + at: 0 = 28 − 4t, so t = 7 s. Thus, acceleration is −4 m s⁻² and stopping time is 7 s.   For more NCERT Solutions of Class 9 SRead more

    For the motorbike, initial velocity u = 28 m s⁻¹, final velocity v = 0 and distance s = 98 m. Using v² = u² + 2as:
    0 = 28² + 2(a)(98), giving a = −4 m s⁻².
    Using v = u + at: 0 = 28 − 4t, so t = 7 s. Thus, acceleration is −4 m s⁻² and stopping time is 7 s.

     

    For more NCERT Solutions of Class 9 Science Exploration Chapter 4 Describing Motion Around Us Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-4/

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  3. The initial velocity of the car is u = 0 m s⁻¹, final velocity is v = 24 m s⁻¹ and time is t = 6 s. Average acceleration = (v − u)/t = (24 − 0)/6 = 4 m s⁻². Distance travelled = average velocity × time = [(u + v)/2] × t = [(0 + 24)/2] × 6 = 72 m.   For more NCERT Solutions of Class 9 Science ExRead more

    The initial velocity of the car is u = 0 m s⁻¹, final velocity is v = 24 m s⁻¹ and time is t = 6 s.
    Average acceleration = (v − u)/t = (24 − 0)/6 = 4 m s⁻².
    Distance travelled = average velocity × time = [(u + v)/2] × t = [(0 + 24)/2] × 6 = 72 m.

     

    For more NCERT Solutions of Class 9 Science Exploration Chapter 4 Describing Motion Around Us Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-4/

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  4. Yes, it is possible for the scooter to be accelerating even when its speedometer reading remains constant. Acceleration is the rate of change of velocity and velocity depends on both speed and direction. Therefore, if the scooter moves with constant speed but continuously changes its direction, itsRead more

    Yes, it is possible for the scooter to be accelerating even when its speedometer reading remains constant. Acceleration is the rate of change of velocity and velocity depends on both speed and direction. Therefore, if the scooter moves with constant speed but continuously changes its direction, its velocity changes and the scooter is accelerating. For example, this occurs when the scooter moves along a circular path.

     

    For more NCERT Solutions of Class 9 Science Exploration Chapter 4 Describing Motion Around Us Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-4/

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  5. (i) The magnitude of average velocity is equal to average speed when an object travels along a straight-line path without changing its direction, so distance travelled equals the magnitude of displacement. (ii) The magnitude of average velocity can be zero when the object returns to its starting poiRead more

    (i) The magnitude of average velocity is equal to average speed when an object travels along a straight-line path without changing its direction, so distance travelled equals the magnitude of displacement.
    (ii) The magnitude of average velocity can be zero when the object returns to its starting point. Its displacement is then zero, but its total distance travelled is not zero, so its average speed remains non-zero.

     

    For more NCERT Solutions of Class 9 Science Exploration Chapter 4 Describing Motion Around Us Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-4/

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