Using the meter bridge formula R/S = L1/(100 – L1), we substitute R = 2Ω, L1 = 40 cm: 2/S = 40/60 Solving, S = 3Ω. Correct answer: (b) 3Ω. Class 12th Science Physics NCERT MCQ Questions NCERT Books MCQ ...

Let the EMFs of the two cells be E₁ and E₂. In series: E₁ + E₂ ∝ 8 m With one reversed: E₁ – E₂ ∝ 2 m Solving, (E₁ + E₂) / (E₁ – E₂) = 8/2 = 4.

The internal resistance of the cell is 0.5 Ω, calculated using Ohm’s law by equating EMF expressions for both resistor cases. Correct answer: (d). Class 12th Science Physics NCERT MCQ Questions NCERT Books MCQ Questions Session 2024-2025.

Since the conductor has a nonzero potential and there are no external charges, there must be charges present to maintain this potential. In electrostatic equilibrium, any excess charge on a conductor resides only on the surface, as the electric field ...

The correct answers are (b) and (c). In a region of constant potential, the electric field is zero because the electric field is the negative gradient of potential. Since potential is constant, its gradient is zero. Also, there can be ...